xin lỗi mk làm sai kết quả là 254

1+1+2+2+4+4+8+8+16+16+32+32+64+64=254

290 nha bn.

mọi người giúp minh giải câu hỏi này đi ạ

1/2+1/4+1/8+1/16+1/32+1/64
= 2 x (1/2+1/4+1/8+1/16+1/32+1/64)
            = 1 + 1/2+1/4+1/8+1/16+1/32
=> 2A - A = (1+1/2+1/4+1/8+1/16+1/32) - (1/2+1/4+1/8+1/16+1/32+1/64)
=> A = 1 - 1/64
         = 63/64

\(1-\dfrac{1}{2}=\dfrac{1}{2}\)

\(\dfrac{1}{2}-\dfrac{1}{4}=\dfrac{1}{4}\)

Vậy A = \(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{4}+\dfrac{1}{4}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{16}+\dfrac{1}{16}-\dfrac{1}{32}+\dfrac{1}{32}-\dfrac{1}{64}\)

=\(1-\dfrac{1}{64}=\dfrac{63}{64}\)

ai nhanh mình k

1 /2 -1 /4 + 1 /8-1 /16 + 1 /32-1 /64 < 1 /3

Cách 1:21/64 < 1/3

Cách 2:21/64 < 0.(3)

Đúng

1 /2 + 1 /4 + 1 /8 + 1 /16 + 1 /32 + 1 /64 < 1 /3

Cách 2:63/64 < 0.(3)

Ko đúng

Câu 3 mình ko biết

a)cho \(\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}\)là A

ta có:A=\(\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}\)

2A=\(\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}\right)2\)

2A=\(1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\frac{1}{16}-\frac{1}{32}\)

2A+A=\(\left(1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\frac{1}{16}-\frac{1}{32}\right)+\left(\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}\right)\)

3A=\(1-\frac{1}{64}\Rightarrow3A=\frac{63}{64}\Rightarrow A=\frac{21}{64}< \frac{1}{3}\)

vậy \(\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}< \frac{1}{3}\)

b) sai đề (\(\frac{63}{64}< \frac{1}{3}\)hay sao)

c)sai nối (nếu x=y=3 thì 2x+3y=17 chia hết nhưng 9x+5y=42 ko chia hết)

\(2xB=1+\dfrac{1}{2}+\dfrac{1}{4}+\dfrac{1}{8}+\dfrac{1}{16}+\dfrac{1}{32}\)

\(B=2xB-B=1-\dfrac{1}{64}=\dfrac{63}{64}\)

2

4

8

16

32

64

128

256

2

4

8

16

64

128

256

          k mk nhé

1+1=2

2+2=4

4+4=8

8+8=16

16+16=32

32+32=64

64+64=128

128+128=256

tk m nhé

                    \(A=\frac{1}{2}-\frac{1}{4}-\frac{1}{8}-\frac{1}{16}-\frac{1}{32}-\frac{1}{64}\)

\(\Leftrightarrow\)\(2A=1-\frac{1}{2}-\frac{1}{4}-\frac{1}{8}-\frac{1}{16}-\frac{1}{32}\)

\(\Leftrightarrow\)\(2A-A=\left(1-\frac{1}{2}-\frac{1}{4}-\frac{1}{8}-\frac{1}{16}-\frac{1}{32}\right)\)\(-\left(\frac{1}{2}-\frac{1}{4}-\frac{1}{6}-\frac{1}{8}-\frac{1}{16}-\frac{1}{32}-\frac{1}{64}\right)\)

\(\Leftrightarrow\)\(A=1-\frac{1}{64}\)\(=\frac{63}{64}\)

1/2 - 1/4 - 1/8 - 1/16 - 1/32 - 1/64 

= 32/64 - 16/64 - 8/64 - 4/64 - 2/64 - 1/64 

= 1/64 .

^ - ^ . Mình không chăc chắn lắm đâu !

= 1- 1/2+1/2-1/4+1/4-1/8+1/8-1/16+1/16-1/32+1/32-1/64

= 1 + ( 1/2 - 1/2 ) + ( 1/4  -  1/4 ) + .... + ( 1/32 - 1/32 ) -1/64

= 1 + 0 + 0 + 0 + 0 + 0 -1/64

= 1 - 1/64 = 63/64

1/2+1/4+1/8+1/16+1/32+1/64=63/64 

nhớ k mik nha

Nghi lời giải ra cho mình với.

Gọi A= 1/2 + 1/4 + 1/8 + .......+ 1/16 +1/32 + 1/64

\(A=\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+\frac{1}{2^4}+\frac{1}{2^5}\frac{1}{2^6}\)

\(2A=1+\frac{1}{2}+\frac{1}{2^2}+....+\frac{1}{2^5}\)

\(2A-A=A=1-\frac{1}{2^5}=1-\frac{1}{64}=\frac{63}{64}\)

63/64 nhé

\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{32}+\frac{1}{64}\)

=\(\frac{1}{1\cdot2}+\frac{1}{2\cdot2}+\frac{1}{2\cdot4}+\frac{1}{2\cdot16}+\frac{1}{2\cdot32}\)

=\(\frac{1}{2}\cdot\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{16}+\frac{1}{32}\right)\)

=\(\frac{1}{2}\cdot\frac{119}{64}\)

=\(\frac{119}{128}\)

Đặt A = 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64

A * 2 = 1/1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32

A * 2 - A = 1/1 + 1/2 + 1/4 + 1/8 + 1/16 + 1/32 - 1/2 - 1/4 - 1/8 - 1/16 - 1/32 - 1/64

A           = 1/1 - 1/64

A           = 63/64