`( 5/6 -1/2 ) : 2/3`

`= ( 5/6 - 3/6) xx 3/2`

`= 1/3 xx 3/2`

`= 3/6`

`=1/2`

`@ `

`(5/6-1/2) : 2/3`

`= 5/6 : 2/3 - 1/2 : 2/3`

`= 5/6 xx 3/2 - 1/2 xx 3/2`

`= 15/12 - 3/4`

`= 5/4 -3/4`

`= 2/4`

`=1/2`

`------`

`(3/4 +1/2) : 3/5`

`= ( 3/4 + 2/4) xx 5/3`

`= 5/4 xx 5/3`

`= 25/12`

`@ `

`(3/4 + 1/2) : 3/5`

`= 3/4 : 3/5 + 1/2 : 3/5`

`= 3/4 xx 5/3 + 1/2 xx 5/3`

`= 5/4 + 5/6`

`=25/12` 

`(3/4 +1/2): 3/4`

`=(3/4 +2/4) xx 4/3`

`= 5/4 xx 4/3`

`=20/12`

`= 5/3`

`-----`

`(3/4 +1/2) : 3/4`

`= 3/4 : 3/4 + 1/2 : 3/4`

`= 1 + 1/2 xx 4/3`

`=1+ 2/3`

`= 3/3+2/3`

`=5/3`

20/24

C1= 8/15x1/4= 2/15

C2= 1/3 x1/4+ 1/5x1/4

    = 1/12+1/20

    =2/15

cách 1 : [ 1/3 + 1/5 ] x 1/4 = 8/15 x 1/4

                                       = 8/60

cách 2 : [ 1/3 + 1/5 ] x 1/4 = 1/3 x 1/4 + 1/5 x 1/4

                                       =1/12 + 1/20

                                       = 8/60

nếu ai thấy đúng cho minh k nhé

\(\left(x+1\right)\left(x+3\right)\left(x+5\right)\left(x+7\right)+15=0\)

\(\Leftrightarrow\left(x^2+8x+7\right)\left(x^2+8x+15\right)+15=0\)

Đặt \(x^2+8x+11=y\Rightarrow x^2+8x+7=y-4;x^2+8x+15=y+4\)

Khi đó:

\(pt\Leftrightarrow\left(y-4\right)\left(y+4\right)+15=0\)

\(\Leftrightarrow y^2-1=0\)

\(\Leftrightarrow y=1;y=-1\)

Nếu \(y=1\Rightarrow x^2+8x+11=1\)

\(\Rightarrow x^2+8x+10=0\)

\(\Rightarrow-\left(6-x^2-8x-16\right)=0\)

\(\Rightarrow-\left[6-\left(x+4\right)^2\right]=0\)

\(\Rightarrow-\left(\sqrt{6}-x-4\right)\left(\sqrt{6}+x+4\right)=0\)

\(\Rightarrow x=-4-\sqrt{6};x=\sqrt{6}-4\)

Nếu \(y=-1\),ta có:

\(x^2+8x+11=-1\)

\(\Rightarrow x^2+8x+12=0\)

\(\Rightarrow x^2+2x+6x+12=0\)

\(\Rightarrow x\left(x+2\right)+6\left(x+2\right)=0\)

\(\Rightarrow\left(x+2\right)\left(x+6\right)=0\)

\(\Rightarrow x=-2;x=-6\)

Vậy \(x=-2;x=-6;x=-4-\sqrt{6};x=\sqrt{6}-4\)

\(\frac{3}{22}\times\frac{3}{11}\times22\)

1.\(=\frac{3\times3\times22}{22\times11\times1}\)

\(=\frac{3\times3}{11\times1}\)

\(=\frac{9}{11}\)

2.  \(=\frac{9}{242}\times22\)

\(=\frac{198}{242}\)

\(=\frac{9\times2\times11}{2\times11\times11}\)

\(=\frac{9}{11}\)

\(\left(\frac{1}{2}+\frac{1}{3}\right)\times\frac{2}{5}\)

1.\(=\frac{5}{6}\times\frac{2}{5}\)

\(=\frac{5\times2}{3\times2\times5}\)

\(=\frac{1}{3}\)

2.\(\)\(=\frac{1}{2}\times\frac{2}{5}+\frac{1}{3}\times\frac{2}{5}\)

\(=\frac{1}{5}+\frac{2}{15}\)

\(=\frac{3}{15}+\frac{2}{15}\)

\(=\frac{5}{15}=\frac{1}{3}\)

Have a good day

Áp dụng công thức dãy số cách đều, ta có tổng của dãy trên là: 

(1 + 99) x 99 : 2 = 4950

Đáp số: 4950

*Dãy trên có 99 số hạng.