\(\frac{2005\times2007-1}{2004+2005\times2006}\)

\(=\frac{2005\times\left(2006+1\right)-1}{2004+2005\times2006}\)

\(=\frac{2005\times2006+2005\times1-1}{2004+2005\times2006}\)

\(=\frac{2005\times2006+2005-1}{2004+2005\times2006}\)

\(=\frac{2005\times2006+2004}{2004+2005\times2006}\)

\(=1\)

_Chúc bạn học tốt_

có phải 0 ko

C=(2005x2006+2005-1)/(2004+2005x2006)=

(2005x2006+2004)/(2004+2005x2006)=1

rồi cảm ơn tôi đã làm trước khi cậu ra đáp án

A = \(\frac{2005\times2007-1}{2004+2005\times2006}=\frac{2005\times\left(2006+1\right)-1}{2004+2005\times2006}=\frac{2005\times2006+2005-1}{2004+2005\times2006}\)

\(=\frac{2005\times2006+2004}{2004+2005\times2006}=1\)

\(\frac{2005.2007-1}{2004+2005.2006}\)

\(=\frac{2005.\left(2006+1\right)-1}{2004+2005.2006}\)

\(=\frac{2005.2006+2005-1}{2004+2005..2006}\)

\(=\frac{2005.2006+2004}{2004+2005.2006}\)

\(=1\)

4024035

4024034 k mik nha

\(\frac{2005\times2007-1}{2004+2005\times2006}\)

=\(\frac{2005\times\left(2006+1\right)-1}{2004+2005\times2006}\)

=\(\frac{2005\times2006+2005\times1-1}{2004+2005\times2006}\)

=\(\frac{2005\times2006+2005-1}{2004+2005\times2006}\)

=\(\frac{2005\times2006+2004}{2004+2005\times2006}\)

Ta thấy tử số và mẫu số giống nhau nên kết quả của biểu thức bằng 1

Li-ke cho mik nhé!

\(\frac{2005.2007-1}{2004+2005.2006}=\frac{2005.\left(2006+1\right)-1}{2004+2005.2006}=\frac{2005.2006+2005.1-1}{2004+2005.2006}=\frac{2005.2006+2004}{2004+2005.2006}=1\)

\(\frac{2005.2007-1}{2004+2005.2006}=\frac{2005.\left(2006+1\right)-1}{2005.2006+2004}=\frac{2005.2006+2005-1}{2005.2006+2004}=\frac{2005.2006+2004}{2005.2006+2004}=1\)

?????????????????????????????????????????

\(\frac{2006.2007-3}{2005.2007+2004}=\frac{2005.2007+2007-3}{2005.2007+2004}=\frac{2007-3}{2004}=\frac{2004}{2004}=1\)

Đúng 100%

Đúng 100%

Đúng 100%

=4028043 nha

nguyễn hữu đức sai rồi nha

\(\dfrac{1}{2001.2003}+\dfrac{1}{2003.2005}+...+\dfrac{1}{2011.2013}\)

\(=\dfrac{1}{2}\left(\dfrac{2}{2001.2003}+\dfrac{1}{2003.2005}+...+\dfrac{1}{2011.2013}\right)\)

\(=\dfrac{1}{2}\left(\dfrac{1}{2001}-\dfrac{1}{2003}+\dfrac{1}{2003}-\dfrac{1}{2005}+...+\dfrac{1}{2011}-\dfrac{1}{2013}\right)\)

\(=\dfrac{1}{2}\left(\dfrac{1}{2001}-\dfrac{1}{2013}\right)=\dfrac{2}{1342671}\)

=1/2.(2/2001.2003+2/2003.2005+.....+2/2011.2013)

=1/2(1/2001-1/2003+1/2003-1/2005+....+1/2011-1/2013)

=1/2(1/2001-1/2013)

=2/1342671