tinh B=(1.2.3.4...2012).(1+1/2+1/3+...+1/2012)
Những câu hỏi liên quan
cho B=1.2.3.4.....2012.(1+1\2+1\3+...+1\2012.CMR B chia hết cho 2013
cho B=(1.2.3.4...2012).(1+1/2+1/3+...+1/2012) chung minh B chi het cho2013
Cho:
B=1.2.3.4.......2012.(1+1/2+1/3+1/4+.......+1/2012)
Chung minh B chia het cho 2013
cho A= 1.2.3.4..........2012.(1+1/2+1/3+1/4+............+1/2012)
Chứng minh A chia hết cho 2013
Tinh [(1+2012/1)*(1+2012/2)*(1+2012/3)*...*(1+2012/1000)]/[(1+1000/1)*(1+1000/2)*(1+1000/3)*...*(1+1000/2012)]
cmr:1/1.2+2/1.2.3+3/1.2.3.4+....+2011/1.2...2012<1
cmr:\(\dfrac{1}{1.2}+\dfrac{2}{1.2.3}+\dfrac{3}{1.2.3.4}+....+\dfrac{2011}{1.2...2012}< 1\)
Cho A= (2012/1+2011/2+2010/3+.......+1/2012)/(1/2+1/3+1/4+....+1/2013)
Tinh A
\(A=\frac{\frac{2012}{1}+\frac{2011}{2}+\frac{2010}{3}+...+\frac{1}{2012}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2013}}\)'
\(A=\frac{\left(1+\frac{2012}{2}+1+\frac{2010}{2}+1+...+\frac{1}{2012}+1\right)}{\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2013}\right)}\)
\(A=\frac{\left(1+\frac{2013}{2}+\frac{2013}{3}+...+\frac{2013}{2012}\right)}{\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2013}\right)}\)
\(A=\frac{2013\left(\frac{1}{2013}+\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2012}\right)}{\left(\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{2013}\right)}\)
\(\Rightarrow A=2013\)
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Giải thích giùm e dấu bằng thứ nhất và hai được ko ạ?
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cho a 1+ 3+3^2+3^3+3^4+..........3^2012
b = 3^2012:2
tinh a-b