`(2/(2xx4)+2/(4xx6)+2/(6xx8)+2/(8xx10))xxy=1/3`

`=>(1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/10)xxy=1/3`

`=>(1/2-1/10)xxy=1/3`

`=>(5/10-1/10)xxy=1/3`

`=>4/10xxy=1/3`

`=>2/5xxy=1/3`

`=>y=1/3:2/5`

`=>y=1/3xx5/2`

`=>y=5/6`

A==2/2x4+2/4x6+2/6x8+2/8x10

A=1/2-1/4+1/4-1/6+1/6-1/8+1/8-1/10

A=1/2-1/10=2/5.

Mk lam xong dau tien, k nhe

Cx2=2/2-2/4+2/4-2/6+2/6-2/8+2/8-2/10

Cx2=2/2-2/10=10/10+-2/10=4/5

Suy ra:C=4/5:2=4/5x1/2=2/5

=1/2-1/4+1/4-1/6+1/6-1/8+...+1/2014-1/2016

=1/2-1/2016

=1007/2016

TK va ket ban nhe

=2/2-2/2016

=1007/1008 : 2

= 1007/2016

1007/2016

TA có 

4-2/2*4+6-4/4*6+8-6/6*8+...+2016-2014/2014*2016

=1/2-1/4+1/4-1/6+...+1/2014-1/2016

=1/2+1/4-1/4+1/6-1/6+...+1/2014-1/2014-1/2016

=1/2-1/2016

=1007/2016

2/2x4+2/4x6+2/6x8+......................+2/2014x2016

=1/2-`1/4+1/4-1/6+1/6-1/8 +..............................+1/2014-1/2016

=1/2-1/2016

=1007/2016

đặt biểu thức đó là A

ta có A=\(\frac{2}{2x4}+\frac{2}{4x6}+...+\frac{2}{2014x2016}\)

\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{12}+...+\frac{1}{2014}-\frac{1}{2016}\)

=\(\frac{1}{2}-\frac{1}{2016}\)

=1007/2016

k nha đúng đấy

2/2x4+2/4x6+2/6x8+...+2/2014x2016

= 1/2-1/4+1/4-1/6+...+1/2014-1/2016

= 1/2- 1/2016

= 1007/2016

mk trả lời đầu tiên đó . k nhé ai k mk mk k lại

\(\frac{1007}{2016}\)

Bằng 1007/2016 nha bạn k mk nha kết bạn vs lun mk hết lượt rùi

2/2x4+ 2/4x6+ 2/6x8+...+2/2014x2016

=1/2-1/4+1/4-1/6+1/6-1/8+...+1/2014-1/2016

=1/2-1/2016

=1008/2016-1/2016

=1007/2016

2/2x4+2/4x6+2/6x8+...+2/2014x2016

=1/2-1/4+1/4-1/6+1/6-1/8+...+1/2014-1/2016

=1/2-1/2016

=1007/2016

Tích mk nha bn

\(\frac{2}{2x4}+\frac{2}{4x6}+\frac{2}{6x8}+...+\frac{2}{2014x2016}\)

\(=\frac{4-2}{2x4}+\frac{6-4}{4x6}+\frac{8-6}{6x8}+...+\frac{2016-2014}{2014x2016}\)

\(=\frac{4}{2x4}-\frac{2}{2x4}+\frac{6}{4x6}-\frac{4}{4x6}+\frac{8}{6x8}-\frac{6}{6x8}+...+\frac{2018}{2016x2018}-\frac{2016}{2016x2018}\)

\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{6}+\frac{1}{6}-\frac{1}{8}+...+\frac{1}{2016}-\frac{1}{2018}\)

\(=\frac{1}{2}-\frac{1}{2018}\)

\(=\frac{504}{1009}\)