Exer 1: There is a division with the quotient is 6 and the remainder is 3. The sum of dividend, divisor and remainder are 195. Find the dividend are divisor.
Exer 2: Prove that: Amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3: Given natural number, n = \(\overline{1ab1}\). Let m be the natural number which is written the opposite respectively of n. Prove that the different of n and m divisibles by 90.
Exer 1:
Trả lời:
The sum of dividend and divisor are:
195 - 3 = 192
Because the quotient is 6.
The divisor is:
(192-3) : (6+1) = 27
The dividend is:
192 - 27 = 165
Exer 2:
Trả lời:
Let three unknow numbers be: n, n + 1, n + 2.
Because n has three forms: 3k, 3k + 1, 3k + 2.
+) If n
Xin lỗi, mình vẫn chưa viết xong, rồi mình viết tiếp đây:
+) If n = 3k then there is only n divisibles by 3.
+) If n = 3k + 1 then there is only n + 2 divisibles by 3.
+) If n = 3k + 2 then there is only n + 1 divisibles by 3.
Thus, amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3:
Trả lời:
When we written the opposite respectively of n, we obtain \(\overline{1ba1}\).
We have:
\(\overline{1ab1}\) + \(\overline{1ba1}\) = (1000 + 100a + 10b + 1) - (1000 + 100b + 10a + 1)
= 90a - 90b
= 90(a - b)\(⋮\) 90
Thus, the difference of n and m which divisibles by 90.
Question 1:
The least common multiple of 330; 65; 15 is
Question 2:
Given seven numbers: 25; 17; 39; 43; 239; 1021; 1023.
The composite numbers are
(Write numbers in order from the least to the greatest and use ";")
Question 3:
The common factors of 18 and 27 are
(Write numbers in order from the least to the greatest and use ";")
Question 4:
Given the set of even numbers: {2; 4; 6; …; 100}.The number of elements is
Question 5:
Find four integer numbers a,b,c,d such that
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
Answer: (a;b;c;d)=()
Question 6:
Find a four-digit natural number that is less than 2015.If the thousands digit is erased,the number will be decreased by 9 times.
Answer:The number is
Question 7:
Calculate: 1×2+2×3+⋯+100×101=
Question 8:
The term of the expression A=1-7+13-19+25-31+⋯ is
Question 9:
Given the expression A= ...
Find the value of n such that 2A+3=
Answer: n=
Question 10:
A natural number has six digits and the units digit is 4.If the units digit is moved to the first row then the number will be increasedby 4 times.The number is
The number of values of n such that 2^n+34 which is a square number is ....
The number of values of n such that n^2+34 which is a square number is ....
The number of values of n such that 2^n+34 which is a square number is ....
Giúp tui nhanh đi các bạn !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Số giá trị của n là 1 giá trị và số n có giá trị bằng 1 thì 2^n+34 là 1 số chính phương.Thử lại:2^1+34=36 và 36=6^2
Số giá trị của n là 1 giá trị và n=1 do 2^1+34=36 mà 36=6^2
The 215th term of the expression A=1-7+13-19+25-31+⋯ is
Question 2:
The number of factors of 120 is
Question 5:
Find four integer numbers a,b,c,d such that
a + b + c + d = 1
a + c + d = 2
a + b + d = 3
a + b + c = 4
Answer: (a;b;c;d)=()
Question 6:
The 215th term of the expression A=1-7+13-19+25-31+⋯ is
Question 7:
A natural number will be increased by 9 times ifthe digit 0 is written between tens digit and units digit.The number is
Question 8:
Calculate: 1×2+2×3+⋯+100×101=
Question 9:
The root of the equation (x+1)+(x+2)+(x+3)+⋯+(x+100)=5750 is x=
Question 10:
The sum of digits of 31000 is A,the sum of digits of A is B,and the sum of digits of B is C.The value of C is
2: Ước của 120 là:
{1;2;3;4;5;6;8;10;12;15;20;24;30;40;60;120}
9: x+ (1+2+3+4+...+100) = 5750
x + 5050= 5750
x = 5750 - 5050 = 700
6. Chữ số thứ 215 là 1285
cau 2 la co 16 uoc
cau 5 a=7 b=-1 c=-2 d=-3
The number of values of n such that n2+34 which is a square number is
The number of values of n such that n2+34 which is a square number is.............?
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