The quotient of a division is 35 and the remainder is 0.If the dividend is increased to 1056 units,the quotient will be 57.The divisor is
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THE QUOTIENT OF DIVISION IS 35 AND THE REMAINDER IS 0. IF THE DIVIDEND IS INCREASED TO 1056 UNITS ,THE QUOTIENT WILL BE 57 . THE DIVISOR IS
Thương của DIVISION LÀ 35 VÀ REMAINDER LÀ 0. NẾU CỔ TỨC LÀ GIA TĂNG ĐỐI VỚI ĐƠN VỊ 1056, THE Hàm QUOTIENT SẼ 57. THE DIVISOR LÀ
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Nhờ Google-sama nhể? Thề cái này là Toán Tiếng Anh
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Given a division.If dividend and divisor are increased to 90 and 6 units respectively,then the quotient and the remainder are not changed. The quotient is.......?
Mau lên đi các bạn ơi còn 30 phút nữa là mình đi rồi
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1.The term 215th of the expression A=1-7+13-19+25-31+⋯ is...
2.The number of values of n such that n2+34 which is a square number is...
3.Given a division If dividend and divisor are increased to 90 and 6 units respectively,then the quotient and the remainder are not changed the quotient is...
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cau 2 la n=1 chu cau 1 voi 3 minh ko biet
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Given a division.If dividend and divisor are increased to 90 and 6 units respectively,then the quotient and the remainder are not changed.
Exer 1: There is a division with the quotient is 6 and the remainder is 3. The sum of dividend, divisor and remainder are 195. Find the dividend are divisor.
Exer 2: Prove that: Amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3: Given natural number, n overline{1ab1}. Let m be the natural number which is written the opposite respectively of n. Prove that the different of n and m divisibles by 90.
Đọc tiếp
Exer 1: There is a division with the quotient is 6 and the remainder is 3. The sum of dividend, divisor and remainder are 195. Find the dividend are divisor.
Exer 2: Prove that: Amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3: Given natural number, n = \(\overline{1ab1}\). Let m be the natural number which is written the opposite respectively of n. Prove that the different of n and m divisibles by 90.
Exer 1:
Trả lời:
The sum of dividend and divisor are:
195 - 3 = 192
Because the quotient is 6.
The divisor is:
(192-3) : (6+1) = 27
The dividend is:
192 - 27 = 165
Exer 2:
Trả lời:
Let three unknow numbers be: n, n + 1, n + 2.
Because n has three forms: 3k, 3k + 1, 3k + 2.
+) If n
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Xin lỗi, mình vẫn chưa viết xong, rồi mình viết tiếp đây:
+) If n = 3k then there is only n divisibles by 3.
+) If n = 3k + 1 then there is only n + 2 divisibles by 3.
+) If n = 3k + 2 then there is only n + 1 divisibles by 3.
Thus, amoney three consecutive natural numbers, there is one only one the number which divisibles by 3.
Exer 3:
Trả lời:
When we written the opposite respectively of n, we obtain \(\overline{1ba1}\).
We have:
\(\overline{1ab1}\) + \(\overline{1ba1}\) = (1000 + 100a + 10b + 1) - (1000 + 100b + 10a + 1)
= 90a - 90b
= 90(a - b)\(⋮\) 90
Thus, the difference of n and m which divisibles by 90.
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When X divided by 234, the remainder is the greatest possible remainder and the quotient is 5.
The value of X is
When X divided by 234, the remainder is the greatest possible remainder and the quotient is 5.
The value of X is
When X divided by 234, the remainder is the greatest possible remainder and the quotient is 5.
The value of X is
When X divided by 234, the remainder is the greatest possible remainder and the quotient is 5.
The value of X is