\(\dfrac{38}{45}-\left(\dfrac{8}{45}-\dfrac{17}{51}-\dfrac{3}{11}\right)\)
\(=\dfrac{38}{45}-\dfrac{8}{45}+\dfrac{17}{51}+\dfrac{3}{11}\)
\(=\left(\dfrac{38}{45}-\dfrac{8}{45}\right)+\dfrac{1}{3}+\dfrac{3}{11}\)
\(=\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{3}{11}\)
\(=\left(\dfrac{2}{3}+\dfrac{1}{3}\right)+\dfrac{3}{11}\)
\(=1+\dfrac{3}{11}\)
\(=\dfrac{11}{11}+\dfrac{3}{11}\)
\(=\dfrac{14}{11}\)

Biết lên mạng mà ko biết vào máy tính ak

Biết lên mạng mà ko biết vào máy tính ak

\(\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

\(=\left(\frac{38}{45}-\frac{8}{45}\right)-\left(\frac{17}{51}-\frac{3}{11}\right)\)

\(=\frac{2}{3}-\frac{2}{33}\)

\(=\frac{20}{33}\)

Học tốt # ^-<

\(\dfrac{38}{45}-\left(\dfrac{8}{45}-\dfrac{17}{51}-\dfrac{3}{11}\right)\)

\(=\dfrac{38}{45}-\dfrac{8}{45}+\dfrac{17}{51}+\dfrac{3}{11}\)

\(=\dfrac{2}{3}+\dfrac{1}{3}+\dfrac{3}{11}\)

\(=1\dfrac{3}{11}\)

\(C=\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\\ =\frac{38}{45}-\frac{8}{45}+\frac{1}{3}+\frac{3}{11}\\ =\frac{30}{45}+\frac{1}{3}+\frac{3}{11}\\ =\frac{2}{3}+\frac{1}{3}+\frac{3}{11}\\ =1+\frac{3}{11}=\frac{14}{11}\)

Chúc bạn học tốt nha.

\(C=\frac{38}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

\(C=\frac{38}{45}-\left(-\frac{212}{495}\right)\)

\(C=\frac{14}{11}.\)

Chúc bạn học tốt!

\(C=\frac{28}{45}-\left(\frac{8}{45}-\frac{17}{51}-\frac{3}{11}\right)\)

\(\Leftrightarrow C=\frac{28}{45}-\frac{8}{45}+\frac{1}{3}+\frac{3}{11}\)

\(\Leftrightarrow C=\frac{30}{45}+\frac{1}{3}+\frac{3}{11}=\frac{2}{3}+\frac{1}{3}+\frac{3}{11}\)

\(\Leftrightarrow C=1+\frac{3}{11}=\frac{14}{11}\)

Vậy : \(C=\frac{14}{11}\).

2/15-2/65-4/39=4/39-4/39=0

32/13-(7/23+8/23)=32/13-15/23=541/299

(1/3+12/67+13/41) - (79/67 - 28/41)=6836/8241-1363/2747=1/3

38/145 - (8/45-17/51-3/11)=38/145-(-212/495)=1982/2871

\(a\frac{31}{23}-\left(\frac{7}{23}+\frac{8}{23}\right)\)

\(=\frac{31}{23}-\frac{7}{23}-\frac{8}{23}\)

\(=\frac{16}{23}\)

Hot

tốt

!

a)\(\frac{31}{23}-\left(\frac{7}{23}+\frac{8}{23}\right)=\frac{31}{23}-\frac{8}{23}+\frac{7}{23}=1+\frac{7}{23}=1\frac{7}{23}\)

b)\(\left(\frac{1}{3}+\frac{12}{67}+\frac{13}{41}\right)-\left(\frac{79}{67}-\frac{28}{41}\right)=\left(\frac{13}{41}+\frac{28}{41}\right)+\left(\frac{79}{67}-\frac{12}{67}\right)-\frac{1}{3}=1+1-\frac{1}{3}\)

\(=2-\frac{1}{3}=\frac{5}{3}\)

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