10,01 < 6,x + x,6 < 11,11

=> x = 4 

vì 6,4 + 4,6 = 11

10,01<11<11,11

10,01 < 6,x + x,6 < 11,11

Suy ra : 6,x + x,6 = 11

Vậy x = 4

k minh minh giai

\(x\times12-x\div0,5=10,01\)

\(x\times12-x\times2=10,01\)

\(x\times\left(12-2\right)=10,01\)

\(x\times10=10,01\)

\(x=10,01\div10\)

\(x=1,001\)

_Học_tốt_

x×12−x÷0,5=10,01

\(\Rightarrow\)x×12−x×2=10,01

\(\Rightarrow\)x×(12−2)=10,01

\(\Rightarrow\)x×10=10,01

\(\Rightarrow\)x=10,01÷10

\(\Rightarrow\)x=1,001

SORRY MIK BẤM NHẦM

\(x\times12-x\div0,5=10,01\)

\(\Rightarrow x\times12-x\times2=10,01\)

\(\Rightarrow x\times(12-2)=10,01\)

\(\Rightarrow10x=10,01\)

\(\Rightarrow x=10,01\div10\)

\(\Rightarrow x=1,001\)

Ko cần nữa đâu, mk bt làm rồi

Chọn đáp án A

1C

2A

\(\dfrac{x-6}{50}+\dfrac{x-6}{51}=\dfrac{x-6}{52}+\dfrac{x-6}{53}\)

\(\Rightarrow\dfrac{x-6}{51}+\dfrac{x-6}{50}-\dfrac{x-6}{52}-\dfrac{x-6}{53}=0\)

\(\Rightarrow\left(x-6\right)\left(\dfrac{1}{50}+\dfrac{1}{51}-\dfrac{1}{52}-\dfrac{1}{53}\right)=0\)

\(\Rightarrow x-6=0\) \(\Rightarrow x=6\)

  Vậy ...

jjjjjjbbb

x-6/50+x-6/51=x-6/52+x-6/53

x+x-x-x=6/50+6/51-6/52-6/53

0x=6/50+6/51-6/52-6/53(vô ly)

=>ko tồn tại giá trị x