tính T=1-1/2+1-1/4+1-1/8+...+1-1/512+1-1/1024
giúp mk với ạ
1+1/2+1/4+1/8+1/16+1/32+1/64+......+1/512+1/1024=????
Giups mk với mk đang gấp các bạn cho mk câu trả lời ngay bây giờ nhé thanks....
\(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+...+\frac{1}{512}+\frac{1}{1024}=??????????\)
\(< =>1+\frac{1}{1\cdot2}+\frac{1}{2\cdot2}+\frac{1}{2\cdot4}+...+\frac{1}{2\cdot256}+\frac{1}{2\cdot512}\)
\(< =>1+\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+...+\frac{1}{2}-\frac{1}{256}+\frac{1}{2}-\frac{1}{512}\)
\(< =>1+\frac{1}{1}-\frac{1}{512}\)
\(< =>\frac{1023}{512}\)
chuc ban hoc tot nhe :))
tính nhanh 1/4+1/8+1/16+1/32+1/64+1/128+1/256+1/512
AI GIÚP MÌNH SẼ CHO MỘT MK
#)Giải :
\(\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+\frac{1}{128}+\frac{1}{256}+\frac{1}{512}\)
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+...+\frac{1}{256}-\frac{1}{512}\)
\(=\frac{1}{2}-\frac{1}{512}\)
\(=\frac{255}{512}\)
Lời giải
\(=\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+\frac{1}{8}-\frac{1}{16}+...+\frac{1}{256}-\frac{1}{512}\)
\(=\frac{1}{2}-\frac{1}{512}\)
\(=\frac{255}{512}\)
1) Tính nhanh:
a) A= 1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64
b) 1/4 + 1/8 + 1/16 +........+ 1/512
Trình bày diễn giải ra nhé!
Đúng mk tick cho
A=1-1/2+1/2-1/4+1/4-1/8+1/8-1/16+1/16-1/32+1/32-1/64
A=1- bạn gạch chéo từ 1/2(đầu tiên) đến 1/32 nha
A=1-1/64=65/64.
B=Bạn làm tương tự như trên nha
k mik nha. Thanks. Chúc bạn học tốt!!!
a) A=1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64
2A=1+1/2+1/4 + 1/8 + 1/16 + 1/32
2A-A= 1+1/2+1/4+1/8+1/16+1/32-(1/2+1/4+1/8+1/16+1/32+1/64)
A= 1-1/64=63/64
b) B= 1/4+1/8+1/16+......+1/512
2B= 1/2+1/4+1/8+1/16+......+1/256
2B-B=1/2+1/4+1/8+1/16+.....+1/256-(1/4+1/8+1/16+.....+1/512)
B=1/2-1/512=255/512
A = 1/2 + 1/4 + 1/8+ ......+ 1/ 512 + 1/1024
giup mk voi . mk dang can gap ,mai mk phai nop roi
Ta có: \(\frac{1}{2}=1-\frac{1}{2}\);
\(\frac{1}{4}=\frac{1}{2}-\frac{1}{4}\); \(\frac{1}{8}=\frac{1}{4}-\frac{1}{8}\);...; \(\frac{1}{512}=\frac{1}{256}-\frac{1}{512}\); \(\frac{1}{1024}=\frac{1}{512}-\frac{1}{1024}\)
=> \(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}+\frac{1}{1024}\)
=> \(A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+\frac{1}{4}-\frac{1}{8}+...+\frac{1}{256}-\frac{1}{512}+\frac{1}{512}-\frac{1}{1024}\)
=> \(A=1-\frac{1}{1024}=\frac{1023}{1024}\)
Đáp số: \(A=\frac{1023}{1024}\)
T= (1- 1/2)+ (1-1/4)+ (1-1/8)+ ...+ (1-512)+ (1-1/1025)
Tìm x
a) ( x-1/2)+(x-1/4)+(x-1/8)+...+(x-1/512)=1
b) x+1/2+1/3+1/4+...+1/100=3/2+4/3+5/4+...+101/100
Giải rõ ràng giùm mk với nha
Tính tổng:1 + 1/2 + 1/4 + 1/8 + 1/16 + ...+ 1/512 + 1/1024
Dãy số đó có số số hạng là :
( 1/1024 - 1 ) :
( 1 + 1/1024 ) *
tính: A=1/6-1/39+1/51 / 1/8-1/52+1/68 B=512-512/2-512/2^2-512/2^3-...-512/2^10
?????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????????/??bố thằng nào mà biết được
Tính tổng S = 1/2+1/4+1/8+.......+1/256+1/512
1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512
= 1 – 1/2 + 1/2- 1/4 + 1/4 – 1/8 + 1/8 – 1/16 + 1/16 – 1/32 + 1/32 – 1/64 + 1/64 – 1/128 + 1/128 – 1/256 – 1/256 – 1/512
= 1 – 1/512
= 511/512 .
1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512 + 1/1024
Ta có :
1/512 = 1×2 / 512×2 = 2/1024
1/256 = 1×4 / 256×4 = 4/1024
1/128 = 1×8 / 128×8 = 8/1024
1/64 = 1×16 / 64×16 = 16/1024
1/32 = 1×32 / 32×32 = 32/1024
1/16 = 1×64 / 16×64 = 64/1024
1/8 = 1×128 / 8×128 = 128/1024
1/4 = 1×256 / 4×256 = 256/1024
1/2 = 1×512 / 2×512 = 512/1024
___________________________
=>
1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512 + 1/1024
= 512/1024 + 256/1024 + 128/1024 + 64/1024 + 32/1024 + 16/1024 + 8/1024 + 4/1024 + 2/1024 + 1/1024
= (512 + 256 + 128 + 64 + 32 + 16 + 8 + 4 + 2 + 1) / 1024
= 1023/1024