(1+2012/1)(1+2012/2)(1+2012/3).......(1+2012/1000) 

(1+1000/1)(1+1000/2)..........(1+1000/2012)

Đề bài là rút gọn, giúp mình với

tính: B=[(1+2012/1)+(1+2012/2)+....+(1+2012/1000)]:[(1+1000/1)+(1+1000/2)+....+(1+1000/2012)]

 giúp mk với nha các bạn . mình đang cần gấp .  mình tick cho

Tinh     [(1+2012/1)*(1+2012/2)*(1+2012/3)*...*(1+2012/1000)]/[(1+1000/1)*(1+1000/2)*(1+1000/3)*...*(1+1000/2012)]

tính B=[(1+2012/1)+(1+2012/2)+(1+2012/3)+...+(1+2012/1000)]:[(1+1000/1)+(1+1000/2)+...+(1+1000/2012)]

(1+2012/1)(1+2012/2)(1+2012/3).......(1+2012/1000) 

(1+1000/1)(1+1000/2)..........(1+1000/2012)

Tính A

tính: B=[(1+2012/1)+(1+2012/2)+....+(1+2012/1000)]:[(1+1000/1)+(1+1000/2)+....+(1+1000/2012)]

.

Tính:

(1 + 2012/1)(1 + 2012/2)....(1 + 2012/1000)

(1 + 1000/1)(1 + 1000/2)....(1 + 1000/2012)

So Sánh A=1000^2012+2/1000^2012-1 và B=1000^2012/1000^2012-3 ( ghi cách làm giùm mình nha tks)

Rút gọn : 

a/ \(A=\frac{\frac{1}{19}+\frac{2}{18}+\frac{3}{17}+...+\frac{19}{1}}{\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+...+\frac{1}{20}}\)

b/ \(B=\frac{\left(1+\frac{2012}{1}\right)\left(1+\frac{2012}{2}\right)...\left(1+\frac{2012}{1000}\right)}{\left(1+\frac{1000}{1}\right)\left(1+\frac{1000}{2}\right)...\left(1+\frac{1000}{2012}\right)}\)