Tìm x
a) \(1+\frac{-1}{60}\)\(+\frac{19}{120}\)<\(\frac{x}{36}\)\(+\frac{-1}{60}\)<\(\frac{58}{90}\)\(+\frac{59}{72}\)\(+\frac{-1}{60}\)
Tìm x thuộc Z, biết: \(1+\frac{-1}{60}+\frac{19}{120}
tìm x thuộc z biết 1 +\(\frac{1}{60}\)+ \(\frac{19}{120}< \frac{x}{36}+\frac{-1}{60}< \frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
tìm \(x\in Z\)
\(1+\frac{-1}{60}+\frac{19}{120}<\frac{x}{36}+\frac{-1}{60}<\frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
Tim x biet
\(1+\frac{-1}{60}+\frac{19}{120}< \frac{x}{36}< \frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
\(1+\frac{-1}{60}+\frac{19}{120}< \frac{x}{36}< \frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
=> \(\frac{137}{120}< \frac{x}{36}< \frac{521}{360}\)
=> \(\frac{411}{360}< \frac{10x}{360}< \frac{521}{360}\)
=> 411 < 10x < 521
=> x \(\in\){ 42,43,44,...,52}
Tìm x\(\in\) Z biết 1+\(\frac{-1}{60}\)+\(\frac{19}{120}\)<\(\frac{x}{36}\)+\(\frac{-1}{60}<\frac{58}{90}+\frac{59}{72}+\frac{-1}{60}\)
bài1 : tìm x, biết
\(1+\frac{-x}{60}+\frac{19}{120}< \frac{x}{36}+\frac{-1}{60}< \frac{58}{90}+\frac{1}{60}\)
bài 2: C/M
1) \(\frac{1}{9}=\frac{1}{9+1}+\frac{1}{9\left(9+1\right)}\) 2) \(\frac{a}{b}=\frac{1}{m+1}+\frac{a\left(m+1\right)-b}{b\left(m+1\right)}\)
bài 3: Tính tổng các phân số có tử = 4, thỏa mãn lớn hơn \(\frac{1}{5}\)và nhỏ hơn \(\frac{1}{4}\)
Bài 2,
a, \(\frac{1}{9+1}+\frac{1}{9\left(9+1\right)}\)
\(=\frac{1}{10}+\frac{1}{9.10}\)
\(=\frac{9+1}{9.10}\)
\(=\frac{1}{9}\)
\(\Leftrightarrow\frac{1}{9}=\frac{1}{9+1}+\frac{1}{9\left(9+1\right)}\)(đpcm)
b, \(\frac{1}{m+1}+\frac{a\left(m+1\right)-b}{b\left(m+1\right)}\)
\(=\frac{b+a\left(m+1\right)-b}{b\left(m+1\right)}\)
\(=\frac{a}{b}\)
\(\Leftrightarrow\frac{a}{b}=\frac{1}{m+1}+\frac{a\left(m+1\right)-b}{b\left(m+1\right)}\)(đpcm)
Tính nhanh:
\(1\frac{13}{15}.\left(0,5\right)^2.3-\left(\frac{8}{15}+1\frac{19}{60}\right):1\frac{19}{60}\)
\(1\frac{13}{15}\cdot\left(0,5\right)^2\cdot3-\left(\frac{8}{15}+1\frac{19}{60}\right):1\frac{19}{60}\)
\(=\frac{28}{15}\cdot\frac{1}{4}\cdot\frac{3}{1}-\frac{37}{20}\cdot\frac{60}{79}\)
\(=\frac{7}{5}-\frac{111}{79}\)
\(=\frac{-2}{395}\)
=28/15.1/4.3-8/15-79/60.60/79
=7.4/15.1/4.3-8/15-1
=7/15.3-8/15-1
=21/15-8/15-1
=13/15-1
=-2/15
ko hc mà đòi có thi thì đúp
tìm x biết :
1 + \(\frac{-1}{60}\) + \(\frac{19}{120}\) < \(\frac{x}{36}\) < \(\frac{58}{90}\) + \(\frac{59}{72}\) + \(\frac{-1}{60}\)
tìm x biết
1+\(\frac{-1}{60}\) +\(\frac{19}{120}\) < \(\frac{x}{36}\) <\(\frac{58}{90}\) + \(\frac{59}{72}\) +\(\frac{-1}{60}\)