Vậy dãy số đó là:

1/2 + 1/4 + 1/8 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512 =

256/512 + 128/512 + 64/512 + 32/512 + 16/512 + 8/512 + 4/512 + 2/512 + 1/512 511/512

Đáp số: 511/512

1/2 + 1/4 =3/4

1/2+1/4 +1/8=7/8

1/2+1/4+1/8+1/16=15/16

....tương tự ta có

1/2 +1/4+1/8+1/16+...+1/256+1/512=511/512

\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}+\frac{1}{512}\)

\(=\frac{256}{512}+\frac{128}{512}+\frac{64}{512}+\frac{32}{512}+\frac{16}{512}+\frac{8}{512}+\frac{4}{512}+\frac{2}{512}\)

\(=\frac{511}{512}\)

Đặt \(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}+\frac{1}{512}\)

\(Ax2=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}\)

\(Ax2-A=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+...+\frac{1}{256}+\frac{1}{512}\right)\)

\(A=1-\frac{1}{512}\)

\(A=\frac{511}{512}\)
 

1 / 2 + 1 / 4 + 1 / 8 + 1 / 16 + 1 / 32 + 1 / 64 + 1 / 128 + 1 / 256 + 1 / 512 = 511 / 512 . 

dãy số đó là:

1/2+1/4+1/8+1/32+1/64+1/128+1/128+1/256+1/512=511/512

1/2 + 1/4 + 1/8 + 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512

= 1 - 1/2 + 1/2 - 1/4 + 1/4 - 1/8 + 1/8 - 1/16 + 1/16 + 1/32 + 1/32 - 1/64 + 1/64 - 1/128 + 1/128 - 1/256  + 1/256 - 1/512

= 1 - 1/512

= 511/512

1/2 + 1/4+ 1/8+ 1/16 + 1/32 + 1/64 + 1/128 + 1/256 + 1/512
= 1 – 1/2 + 1/2- 1/4 + 1/4 – 1/8 + 1/8 – 1/16 + 1/16 – 1/32 + 1/32 – 1/64 + 1/64 – 1/128 + 1/128 – 1/256 – 1/256 – 1/512
= 1 – 1/512

= 511/512 .

A=\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}\)

2A=\(1+\frac{1}{2}+\frac{1}{4}+...+\frac{1}{256}\)

2A-A=\(1+\frac{1}{2}+\frac{1}{4}+...+\frac{1}{256}\)--\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{512}\)

A=1-\(\frac{1}{512}\) =511/512

1​023/1024 mìh dùq cấp số nhân

1023/1024

TICK CHO MIK NHA!

1/2 + 1/4 + 1/8 + 1/16 + ... + 1/256 + 1/512

= 256/512 + 128/512 + 64/512 + ... + 2/512 + 1/512

= 256 + 128 + 64 + .. + 2 + 1 / 512

= ???????

s=1/2+1/4+1/8+1/16+.....+1/256+1/512

sx2=(1/2+1/4+1/8+1/16+....+1/256+1/512)x2

sx2=1+1/2+1/4+1/8+......+1/126+1/256

sx2-s=(1+1/2+1/4+1/8+......+1/256)-(1/2+1/4+1/8+1/16++.....+1/256+1/512)

1+1/2+1/4+1/8+......+1/256-1/2-1/4-1/8-1/16-.....1/256-1/512

=1-1/512=511/512

có ai bik B=1/4+1/8+1/16+1/...+1/256 ko (nếu bik thì giải tử tế nhé mik cảm ơn)

*Tham khảo 

 Ta có: A =1/2+1/4+1/8+1/16+....+1/256+1/512 

=> 2A = 1 + 1/2 + 1/4 + 1/8 + ...+ 1/128 + 1/256

=> 2A - A = (1 + 1/2 + 1/4 + 1/8 + ...+ 1/128 + 1/256 -(1/2+1/4+1/8+1/16+....+1/256+1/512 )

         A =  1 - 1/512 = 511/512

= 511/512

\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}+\frac{1}{512}\)

\(A\cdot2=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{256}\)

\(A\cdot2-A=1-\frac{1}{512}\)

\(A=\frac{511}{512}\)

1/2+1/4+1/8+1/16+...+1/256+1/512(gọi A là tổng các PS trên)

A*2=(1+1/2+1/4+1/8+...+1/128+1/256)/2

A*2-A=1+1/2+1/4+1/8+...+1/128+1/256-1/2-1/4-1/8-1/16-...-1/256-1/512.

A=1-1/512

A=511/512.

Kết bạn với mình nha!