\(\frac{7}{20}\) -{\(\frac{5}{8}\) - \(\frac{25}{5}\) }
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Thực hiện phép tính:
A=\(\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
B=1\(\frac{13}{15}.0,75-\left(\frac{11}{20}+25\%\right):\frac{7}{5}\)
A=3/4
B=29/35
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\(A=\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{3}{8}+\frac{-6}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{-3}{8}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\left(\frac{-36}{24}+\frac{56}{24}\right):\frac{5}{6}+\frac{1}{2}\)
\(A=\frac{5}{6}:\frac{5}{6}+\frac{1}{2}\)
\(A=\frac{5}{6}\times\frac{6}{5}+\frac{1}{2}\)
\(A=1+\frac{1}{2}\)
\(A=\frac{1}{1}+\frac{1}{2}=\frac{2}{2}+\frac{1}{2}\)
\(A=\frac{3}{2}\)
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Bài 1:Tìm x,biết
a) x-frac{20}{11.13}-frac{20}{13.15}-frac{20}{15.17}-...-frac{20}{53.55}frac{3}{11}
b)x+frac{15}{90.94}+frac{15}{94.98}+frac{15}{98.102}+...+frac{15}{146.150}frac{2}{3}
c)x-frac{1}{2}-frac{1}{6}-frac{1}{12}-frac{1}{20}-frac{1}{30}-frac{1}{42}-frac{1}{56}frac{5}{24}
d)8-frac{8-frac{8}{5}+frac{8}{25}-frac{8}{125}}{9-frac{9}{5}+frac{9}{25}-frac{9}{125}}:frac{161616}{151515}frac{4+frac{4}{73}-frac{4}{115}}{5+frac{5}{73}-frac{1}{23}}
Đọc tiếp
Bài 1:Tìm x,biết
a) \(x-\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-...-\frac{20}{53.55}=\frac{3}{11}\)
b)\(x+\frac{15}{90.94}+\frac{15}{94.98}+\frac{15}{98.102}+...+\frac{15}{146.150}=\frac{2}{3}\)
c)\(x-\frac{1}{2}-\frac{1}{6}-\frac{1}{12}-\frac{1}{20}-\frac{1}{30}-\frac{1}{42}-\frac{1}{56}=\frac{5}{24}\)
d)\(8-\frac{8-\frac{8}{5}+\frac{8}{25}-\frac{8}{125}}{9-\frac{9}{5}+\frac{9}{25}-\frac{9}{125}}:\frac{161616}{151515}=\frac{4+\frac{4}{73}-\frac{4}{115}}{5+\frac{5}{73}-\frac{1}{23}}\)
a, Câu hỏi của Nguyễn Ánh Ngân - Toán lớp 6 - Học toán với OnlineMath
b, Câu hỏi của Vũ Xuân Hiếu - Toán lớp 6 | Học trực tuyến
c)
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a,1frac{13}{15}.0,75-left(frac{8}{15}+0,25right).frac{24}{47}
b,5:left(4frac{3}{4}-1frac{25}{28}right)-1frac{3}{8}:left(frac{3}{8}+frac{9}{20}right)
c,6frac{5}{12}:2frac{3}{4}+11frac{1}{4}.left(frac{1}{3}-frac{1}{5}right)
d,left(frac{3}{5}+0,415-frac{3}{200}right).2frac{2}{3}.0,25
e,left(frac{3}{8}+frac{-3}{4}+frac{7}{12}right):frac{5}{6}+frac{1}{2}
g,1frac{13}{15}.0,75-left(frac{11}{20}+25%right);frac{7}{3}
Đọc tiếp
\(a,1\frac{13}{15}.0,75-\left(\frac{8}{15}+0,25\right).\frac{24}{47}\)
\(b,5:\left(4\frac{3}{4}-1\frac{25}{28}\right)-1\frac{3}{8}:\left(\frac{3}{8}+\frac{9}{20}\right)\)
\(c,6\frac{5}{12}:2\frac{3}{4}+11\frac{1}{4}.\left(\frac{1}{3}-\frac{1}{5}\right)\)
\(d,\left(\frac{3}{5}+0,415-\frac{3}{200}\right).2\frac{2}{3}.0,25\)
\(e,\left(\frac{3}{8}+\frac{-3}{4}+\frac{7}{12}\right):\frac{5}{6}+\frac{1}{2}\)
\(g,1\frac{13}{15}.0,75-\left(\frac{11}{20}+25\%\right);\frac{7}{3}\)
So sánh \(A\)với\(13\),biết rằng:
\(A=\frac{13}{15}+\frac{7}{5}+\frac{3}{4}+\frac{1}{5}+\frac{1}{7}+\frac{19}{20}+\frac{5}{4}+\frac{1}{3}+\frac{1}{6}+\frac{1}{13}+\frac{17}{23}+\frac{9}{8}+\frac{2}{5}+\frac{1}{7}+\frac{1}{25}+\frac{3}{2}+\frac{1}{8}+\frac{1}{19}+\frac{1}{9}+\frac{1}{97}\)
a,\(\frac{8}{9}x-\frac{2}{3}=\frac{1}{3}x+1\frac{1}{3}\)
b,\(\left(\frac{-2}{5}+\frac{3}{7}\right)-\left(\frac{4}{9}+\frac{12}{20}-\frac{13}{25}\right)+\frac{7}{35}\)
c,(\(\left(\frac{7}{8}-2\frac{1}{3}\right):\frac{2}{5}+\frac{1}{6}\)
\(a)\frac{8}{9}x-\frac{2}{3}=\frac{1}{3}x+1\frac{1}{3}\)
\(\Rightarrow\frac{8}{9}x-\frac{1}{3}x=\frac{2}{3}+1\frac{1}{3}\)
\(\Rightarrow\frac{5}{9}x=\frac{2}{3}+\frac{4}{3}\)
\(\Rightarrow\frac{5}{9}x=2\Rightarrow x=2\div\frac{5}{9}=\frac{18}{5}\)
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\(b)(\frac{-2}{5}+\frac{3}{7})-(\frac{4}{9}+\frac{12}{20}-\frac{13}{25})+\frac{7}{35}\)
\(=\frac{1}{35}-(\frac{4}{9}+\frac{3}{5}-\frac{13}{25})+\frac{1}{5}\)
\(=\frac{1}{35}-(\frac{4}{9}+\frac{15}{25}-\frac{13}{25})+\frac{1}{5}\)
\(=\frac{1}{35}-(\frac{4}{9}+\frac{2}{25})+\frac{1}{5}\)
\(=\frac{1}{35}-\frac{118}{25}+\frac{1}{5}\)
Làm nốt
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\(c)(\frac{7}{8}-2\frac{1}{3})\div\frac{2}{5}-\frac{1}{6}=(\frac{7}{8}-\frac{7}{3})\div\frac{2}{5}-\frac{1}{6}\)
\(=\frac{-13}{24}\div\frac{2}{5}-\frac{1}{6}\)
\(=\frac{-65}{48}-\frac{1}{6}=\frac{-65}{48}-\frac{8}{48}=\frac{-65-8}{48}=\frac{-73}{48}\)
P/S : Hoq chắc :>
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\(\frac{2}{7}\) + \(\frac{3}{8}\) ; \(\frac{7}{56}\) : \(\frac{20}{25}\) ; \(\frac{20}{35}\) x \(\frac{5}{4}\) ; \(\frac{8}{7}\) - \(\frac{5}{6}\)
a)\(\frac{2}{7}+\frac{3}{8}=\frac{16}{56}+\frac{21}{56}=\frac{37}{56}\)
b)\(\frac{7}{56}:\frac{20}{25}=\frac{6}{56}x\frac{25}{20}=\frac{150}{1120}=\frac{15}{112}\)
c)\(\frac{20}{35}x\frac{5}{4}=\frac{100}{140}=\frac{5}{7}\)
d)\(\frac{8}{7}-\frac{5}{6}=\frac{48}{56}-\frac{35}{56}=\frac{13}{56}\)
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Mình mong ai đo trả lời giúp mình:
Tinh bằng cách thuận tiện
\(\frac{9}{25}\cdot\frac{5}{7}+\frac{6}{25}\cdot\frac{20}{28}+2\cdot\frac{1}{5}:\frac{7}{5}-\frac{3}{7}-\frac{2}{7}\)
\(\frac{\frac{8}{5}:\left(\frac{8}{5}.\frac{5}{4}\right)}{\frac{16}{25}-\frac{1}{25}}+\frac{1:\frac{4}{7}}{\left(\frac{50}{9}-\frac{9}{4}\right).\frac{36}{17}}+0,6.0,5:\frac{2}{5}\)
8/5:(8/5.5/4) / 16/25-1/25 + 1:4/7 / (50/9-9/4).36/17) + 0,6.0,5:2/5
= 8/5:8/5:5/4 / 3/5 + 7/4 / 50/9.36/17-9/4.36/17 + 0,3.5/2
= 4/5:3/5 + 7/4 / 200/17-81/17 + 3/10.5/2
= 4/5.5/3 + 7/4 / 119/17 + 3/4
= 4/3 + 7/4 : 7 + 3/4
= 4/3 + 4 + 3/4
= 16/12 + 48/12 + 9/12
= 73/12
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a. \(\frac{5}{6}\)- |1-x| = \(\frac{1}{2}\)
b. \(\frac{8^5.\left(-5\right)^8+\left(-2\right)^5.\left(-10\right)^9}{4^{10}.5^7+20^8.4}\). \(\frac{144}{25}\)
a) \(\frac{5}{6}-\left|1-x\right|=\frac{1}{2}\)
<=> \(\left|1-x\right|=\frac{5}{6}-\frac{1}{2}\)
<=>\(\left|1-x\right|=\frac{1}{3}\)
<=>\(\orbr{\begin{cases}1-x=\frac{1}{3}\\1-x=-\frac{1}{3}\end{cases}}\)
<=>\(\orbr{\begin{cases}x=1-\frac{1}{3}\\x=1-\left(-\frac{1}{3}\right)\end{cases}}\)
<=>\(\orbr{\begin{cases}x=\frac{2}{3}\\x=\frac{4}{3}\end{cases}}\)
Vậy \(x=\frac{2}{3}\)hoặc\(x=\frac{4}{3}\)
b) \(\frac{8^5.\left(-5\right)^8+\left(-2\right)^5.\left(-10\right)^9}{4^{10}.5^7+20^8.4}.\frac{144}{25}\)
\(=\frac{2^{15}.5^8+2^5.2^9.5^9}{2^{20}.5^7+2^{16}.5^8.2^2}.\frac{2^4.3^2}{5^2}\)
\(=\frac{2^{14}.5^8.\left(2+5\right)}{2^{18}.5^7.\left(2^2+5\right)}.\frac{2^4.3^2}{5^2}\)
\(=\frac{2^{14}.5^8.7}{2^{18}.5^7.3^2}.\frac{2^4.3^2}{5^2}\)
\(=\frac{2^{18}.3^2.5^8.7}{2^{18}.3^2.5^9}\)
\(=\frac{7}{5}\)
Học tốt!!!!
a.\(\frac{5}{6}-\left|1-x\right|=\frac{1}{2}\)
\(=>\left|1-x\right|=\frac{5}{6}-\frac{1}{2}\)
\(=>\left|1-x\right|=\frac{1}{3}\)
\(=>\orbr{\begin{cases}1-x=\frac{1}{3}\\1-x=\frac{-1}{3}\end{cases}}\)
\(=>\orbr{\begin{cases}x=1-\frac{1}{3}=\frac{2}{3}\\x=1-\frac{-1}{3}=\frac{4}{3}\end{cases}}\)
bài 1: a) frac{-7}{12} + frac{11}{20} - frac{8}{15}b) frac{9}{11} +left(frac{-2}{5}+frac{1}{6}right) :frac{11}{30}c) frac{-17}{25}.frac{20}{33}+frac{-17}{25}.frac{13}{33}+frac{-3}{25}bài 2.a) frac{3}{5}.frac{4}{9}+frac{-3}{10}.frac{4}{9}+1frac{3}{10}b) 0,7 + frac{8}{5} : 3 - frac{7}{30}bài 3.a) frac{13}{30}+frac{11}{20}-frac{7}{15}b) frac{-5}{72}:left(frac{3}{8}.frac{7}{9}right)c) frac{-23}{25}.frac{10}{13}+frac{-23}{25}.frac{3}{13}+frac{-27}{25}
Đọc tiếp
bài 1: a) \(\frac{-7}{12}\) + \(\frac{11}{20}\) - \(\frac{8}{15}\)
b) \(\frac{9}{11}\) +\(\left(\frac{-2}{5}+\frac{1}{6}\right)\) :\(\frac{11}{30}\)
c) \(\frac{-17}{25}.\frac{20}{33}+\frac{-17}{25}.\frac{13}{33}+\frac{-3}{25}\)
bài 2.
a) \(\frac{3}{5}.\frac{4}{9}+\frac{-3}{10}.\frac{4}{9}+1\frac{3}{10}\)
b) 0,7 + \(\frac{8}{5}\) : 3 - \(\frac{7}{30}\)
bài 3.
a) \(\frac{13}{30}+\frac{11}{20}-\frac{7}{15}\)
b) \(\frac{-5}{72}:\left(\frac{3}{8}.\frac{7}{9}\right)\)
c) \(\frac{-23}{25}.\frac{10}{13}+\frac{-23}{25}.\frac{3}{13}+\frac{-27}{25}\)