kho

kho

a, \(\left|2x+1\right|=5\Rightarrow2x+1\in\left\{5;-5\right\}\)

+) Nếu :\(2x+1=5\Rightarrow2x=4\Rightarrow x=4\div2=2\)

+) Nếu : \(2x+1=-5\Rightarrow2x=-6\Rightarrow x=-6\div2=-3\)

Vậy \(x\in\left\{2;-3\right\}\)

b, \(\left|x-4\right|=\left|2-x\right|\)

\(\Rightarrow\left[\begin{matrix}x-4=2-x\\x-4=-\left(2-x\right)\end{matrix}\right.\)

+) Nếu : x - 4 = 2 - x

\(\Rightarrow x+x=2+4\Rightarrow2x=6\Rightarrow x=3\)

+) Nếu : x - 4 = - ( 2 - x )

\(\Rightarrow x-4=-2+x\Rightarrow x-x=-2+4\Rightarrow0=2\) ( loại )

Vậy x = 3 thỏa mãn đề bài

c, \(\left|x-5\right|=2-x\Rightarrow\left|x-5\right|+x=2\)

+) Nếu : \(x< 5\Rightarrow x-5< 5-5\Rightarrow x-5< 0\Rightarrow\left|x-5\right|=-x+5\)

Thay vào đề , ta có :

\(-x+5+x=2\Rightarrow-x+x+5=2\Rightarrow5=2\) ( loại )

+) Nếu : \(x\ge5\Rightarrow x-5\ge5-5\Rightarrow x-5\ge0\Rightarrow\left|x-5\right|=x-5\)

Thay vào đề , ta có :

\(\left(x-5\right)-x=2\Rightarrow x-5-x=2\)

\(\Rightarrow x-x-5=2\Rightarrow-5=2\) ( loại )

Vậy \(x\in\varnothing\)

đầu tiên ta tính 

\(A=1+5+5^2+..+5^{2011}\)

\(\Rightarrow5A=5+5^2+..+5^{2012}\)

lấy hiệu hai đẳng thức trên ta có \(4A=5^{2012}-1\Leftrightarrow A=\frac{5^{2012}-1}{4}\Rightarrow x-1=4\Rightarrow x=5\)

=>1/3 - 1/7=1/x

\(\frac{5}{1.2}+\frac{5}{2.3}+\frac{5}{3.4}+...+\frac{5}{x\left(x+1\right)}=\frac{9998}{9999}\)

\(\Leftrightarrow5\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{9998}{9999}\)

\(\Leftrightarrow5\left(1-\frac{1}{x+1}\right)=\frac{9998}{9999}\)

\(\Leftrightarrow1-\frac{1}{x+1}=\frac{9998}{9999}\div5\)

\(\Leftrightarrow1-\frac{1}{x+1}=\frac{9998}{49995}\)

\(\Leftrightarrow\frac{1}{x+1}=1-\frac{9998}{49995}=\frac{39997}{49995}\)

\(\Leftrightarrow x=\frac{9998}{39997}\)

\(\left(x+1\right)\left(xy-5\right)=5\)

\(\Rightarrow\left(x+1\right);\left(xy-5\right)\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\)

Xét bảng

Vậy........................

P/S: ko chắc    

Ta có : ( x+1 ) + ( x + 2 ) + ( x + 3 ) + ( x + 4 ) + ( x + 5 ) = 30

            ( x + x + x +x +x ) + ( 1 + 2 + 3 + 4 + 5 ) = 30

             x * 5 + 15 = 30

              x * 5 = 30 - 15

              x * 5 = 15

                   x = 15 : 5 

                  x = 3

Vậy x = 3

Duyệt đi , chúc bạn học giỏi

(x + 1) + (x + 2) + (x + 3) + (x + 4) + (x + 5) = 4 + 5 + 6 + 7 + 8

x + 1 + x + 2 + x + 3 + x + 4 + x + 5 = 30

\(x\)x 5  + 15 = 30

\(x\)x 5 = 30 - 15 = 15

x = 15 : 5 = 3

\(\frac{x}{4}=\frac{5}{x+1}\)

\(\Rightarrow x\left(x+1\right)=4.5\)

\(\Rightarrow x\left(x+1\right)=4\left(4+1\right)\)

\(\Rightarrow x=4\)

thank you very so much

Theo bài ra , ta có :

x/4 = 5/x+1 

(=) x(x+1) = 20 

(=) x = 4 

Vậy x = 4