\(\frac{1+\frac{1}{3}+\frac{1}{5}+.....+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+......+\frac{1}{49.51}}\)
\(\frac{1+\frac{1}{3}+\frac{1}{5}+.......+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+....+\frac{1}{49.51}}\)
\(\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{49.51}}\)= ?
Cho A=\(\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{49.51}}.\)Rút gọn A ta được A=.............
\(A=\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{49.51}}\)Rút gọn A ta được A =
Tính nhanh \(\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{49.51}}\)
Cho A=(1+1/3+1/5+...+1/97+1/99)/(1/1*99+1/3*97+1/5*95+...+1/49*51) rut gon ta duoc A=3
Không phải A=3 đâu bạn !!! Sau đây là cách giải của mik: Ta xét tử số : Đặt B=1+1/3+1/5+...+1/97+1/99 =>B=(1+1/99)+(1/3+1/97)+(1/5+1/95)+...+(1/49+1/51) =>B=100/1*99+100/3*97+100/5*95+...+100/49*51 =>B=100*(1/1*99+1/3*97+1/5*95+...+1/49*51) Ta có : A=B/(1/1*99+1/3*97+1/5*95+...+1/49*51) =>A=100*(1/1*99+1/3*97+1/5*95+...+1/49*51)/ (1/1*99+1/3*97+1/5*95+...+1/49*51) =>A=100 Vậy A=100 Mik chắc chắn 100% lun đó !!! Nếu các bạn thấy cách giải của mik hay thì nhớ *** cho mik nha (^.^) Thank you các bạn nhìu nhìu lắm ... >-<
Rút gọn \(A=\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{49.51}}\)
Giải
\(A=\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{49.51}}\)
Tính A
\(A=\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{49.51}}\)
Cho A= \(\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+....+\frac{1}{49.51}}\)rút gọn A ta được A=........
Cho A=\(\frac{1+\frac{1}{3}+\frac{1}{5}+...+\frac{1}{97}+\frac{1}{99}}{\frac{1}{1.99}+\frac{1}{3.97}+\frac{1}{5.95}+...+\frac{1}{49.51}}\) . Rút gọn A=