a = 1/2 + 1/6 +1/12 + 1/20 + 1/30 + ....................................................... + 1/n biết a = 39/40 .tim n ?
a=1/2+1/6+1/12+1/20+1/30+...1/n
tim n biet a=39/40
a=1/2+1/6+1/12+1/20+1/30+1/n
a=1/1-1/2+1/2-...+1/a+1
a=1+1/a-1=39
=>a=40
vay n=39X40=1560
ai h minh h lai
A= 1/2+1/6+1/12+20+1/30+....+1/n
biet A=39/40 tim n
A = 1/1.2 + 1/2.3 +.......+1/a(a + 1)
A = 1/1 - 1/2 + 1/2 - ..... - 1/a+1
A= 1 - 1/a+ 1 = 39/40
1/a + 1 = 1/4 0 => a + 1= 40 => a= 39
Vậy n= 39 x 40 = 1560
A=1/2+1/6+1/12+1/20+1/30+...+1/n Biết A=39/40 Tìm n
A=\(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+.........+\frac{1}{n}=\frac{39}{40}\)
A=\(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+..........+\frac{1}{ax\left(a+1\right)}=\frac{39}{40}\)
A=\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+.......+\frac{1}{a}-\frac{1}{a+1}=\frac{39}{40}\)
A=\(1-\frac{1}{a+1}=\frac{39}{40}\)
\(\frac{1}{a+1}=1-\frac{39}{40}\)
\(\frac{1}{a+1}=\frac{1}{40}\)
a+1=40
a=40-1
a=39
n=39x40
n=1560
Tính n. Biết A = 1/2+1/6+1/12+1/20+1/30+....+1/n
Biết A = 39/40
a= 1/2 + 1/6 +1/12 + 1/20 +1/30 + .... + 1/n. tìm n biết a= 39/40
Ta có:
\(a=\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{n}=\frac{39}{40}\)
Coi n=a.(a+1)
\(=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{a.\left(a+1\right)}\)
Ta thấy:
\(\frac{1}{1.2}=1-\frac{1}{2};\frac{1}{2.3}=\frac{1}{2}-\frac{1}{3};...\)
\(\Rightarrow a=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{a}-\frac{1}{a+1}\)
\(=1+\frac{-1}{2}+\frac{1}{2}+\frac{-1}{3}+\frac{1}{3}+...+\frac{-1}{a}+\frac{1}{a}-\frac{1}{a+1}\)
\(=1+\left(\frac{-1}{2}+\frac{1}{2}\right)+\left(\frac{-1}{3}+\frac{1}{3}\right)+...-\frac{1}{a+1}\)
\(=1+0+0+...+0-\frac{1}{a+1}\)
\(\Rightarrow1-\frac{1}{a+1}=\frac{39}{40}\)
\(\Rightarrow a+1=40\Rightarrow a=39\)
\(\Rightarrow n=39.40=1560\)
Cho A = 1/2 + 1/6 + 1/12 + 1/20 +1/30 + ....... + 1/n . Biết A =39/40.Tìm n.
A = 1/2+1/6+1/12+1/20+1/30+...+1/n = 1/1.2 + 1/2.3 +1/3.4 + 1/4.5 + 1/5.6 ......+1/a.b ( với a; b là hai số tự nhiên liên tiếp và a.b = n )
A = 1/2 + (1/2 -1/3) +( 1/3 -1/4) +(1/4 -1/5) +(1/5 -1/6) + ......
+( 1/a -1/b) = 1-1/b = 39/40 => b = 40 ; suy ra a = 39
vậy n = 39 x 40 =1560
A = 1/2+1/6+1/12+1/20+1/30+...+1/n = 1/1.2 + 1/2.3 +1/3.4 + 1/4.5 + 1/5.6 ......+1/a.b ( với a; b là hai số tự nhiên liên tiếp và a.b = n )
A = 1/2 + (1/2 -1/3) +( 1/3 -1/4) +(1/4 -1/5) +(1/5 -1/6) + ......
+( 1/a -1/b) = 1-1/b = 39/40 => b = 40 ; suy ra a = 39
vậy n = 39 x 40 =1560
A = 1/2+1/6+1/12+1/20+1/30+...+1/n = 1/1.2 + 1/2.3 +1/3.4 + 1/4.5 + 1/5.6 ......+1/a.b ( với a; b là hai số tự nhiên liên tiếp và a.b = n )
A = 1/2 + (1/2 -1/3) +( 1/3 -1/4) +(1/4 -1/5) +(1/5 -1/6) + ......
+( 1/a -1/b) = 1-1/b = 39/40 => b = 40 ; suy ra a = 39
vậy n = 39 x 40 =1560
a= 1/2 + 1/6 +1/12 + 1/20 +1/30 + .... + 1/n. tìm n biết a= 39/40
a= 1/2 + 1/6 +1/12 + 1/20 +1/30 + .... + 1/n. tìm n biết a= 39/40
1/2 + 1/6 + 1/12 + 1/20 + ... + 1/n = 39/40
1/(1x2) + 1/(2x3) + 1/(3x4) + 1/(4x5) + ... + 1/n = 39/40
1 - 1/2 + 1/2 - 1/3 + 1/3 - 1/4 + 1/4 - 1/5 + ... - 1/n = 39/40
1 - 1/n = 39/40
=> 1/n = 1 - 39/40 = 1/40
=> n = 40
A=1/2+1/6+1/12+1/20+1/30+...+1/n
Biết A=39/40 tìm n.
A = 1/2+1/6+1/12+1/20+1/30....+1/n
tìm n biết A = 39/40