111/115>555/559 bn nhá

\(\frac{111}{115}\)= 1 - \(\frac{4}{115}\)

\(\frac{555}{559}\)= 1 - \(\frac{4}{559}\)

\(\frac{4}{115}\)> \(\frac{4}{559}\)

=> \(\frac{111}{115}\) < \(\frac{555}{559}\)

Ta có:

\(\frac{111}{115}=\frac{111.5}{115.5}=\frac{555}{575}< \frac{555}{559}\)

=> \(\frac{111}{115}< \frac{555}{559}\)

111/115= 1 - 4/115

555/559= 1- 4/559

Vì: 4/115> 4/559

=> 1- 4/115< 1- 4/559

=> 111/115< 555/559

111/115=555/575 mà 555/575<555/559 ==> 111/115<555/559

< bạn ạ

đơn giản mà bạn lấy \(\frac{111}{115}\) x 5 ta được \(\frac{555}{575}\) mà cả 2 phân số đều có chung tử số nên mẫu số nhỏ hơn thì phân số đó lớn hơn ( Chú ý nếu đó là phép chia thì ta cũng có thể đặt làm phân số)

a) Ta có:

\(\frac{232323}{999999}=\frac{23.10101}{99.10101}=\frac{23}{99}\)

Vì : \(\frac{23}{99}=\frac{23}{99}\\ =>\frac{23}{99}=\frac{232323}{999999}\)

b) \(-\frac{63}{84}=-\frac{3}{4}\\ \frac{65}{-91}=-\frac{5}{7}\)

Vì: \(-\frac{3}{4}< -\frac{5}{7}\\ =>-\frac{63}{84}< \frac{65}{-91}\)

c) Ta có: \(\frac{111}{115}=1-\frac{4}{115}\\ \frac{555}{559}=1-\frac{4}{559}\)

Vì: \(\frac{4}{115}>\frac{4}{559}\\ =>1-\frac{4}{115}< 1-\frac{4}{559}\\ =>\frac{111}{115}< \frac{555}{559}\)

a) \(\dfrac{23}{99}\) và \(\dfrac{232323}{999999}\)

* Giữ nguyên \(\dfrac{23}{99}\).

* Rút gọn \(\dfrac{232323}{999999}=\dfrac{23}{99}\).

Vì \(\dfrac{23}{99}=\dfrac{23}{99}\) nên \(\dfrac{23}{99}=\dfrac{232323}{999999}\)

Vậy \(\dfrac{23}{99}=\dfrac{232323}{999999}\).

b) \(\dfrac{-63}{84}\) và \(\dfrac{65}{-91}\)

\(\circledast\) Rút gọn:

\(\dfrac{-63}{84}=\dfrac{-3}{4}\) ; \(\dfrac{65}{-91}=\dfrac{-5}{7}\)

\(\circledast\) Quy đồng:

Mẫu chung: 28

\(\dfrac{-3}{4}=\dfrac{-3.7}{4\cdot7}=\dfrac{-21}{28}\)

\(\dfrac{-5}{7}=\dfrac{-5\cdot4}{7\cdot4}=\dfrac{-20}{28}\)

Vì \(\dfrac{-21}{28}< \dfrac{-20}{28}\) nên \(\dfrac{-63}{84}< \dfrac{65}{-91}\).

Vậy \(\dfrac{-63}{84}< \dfrac{65}{-91}\).

c) \(\dfrac{111}{115}\) và \(\dfrac{555}{559}\)

\(\dfrac{111}{115}=1-\dfrac{4}{115}\) ; \(\dfrac{555}{559}=1-\dfrac{4}{559}\)

Vì \(\dfrac{4}{115}>\dfrac{4}{559}\)

\(\Rightarrow\) \(1-\dfrac{4}{115}< 1-\dfrac{4}{559}\)

\(\Rightarrow\) \(\dfrac{111}{115}< \dfrac{555}{559}\)

Vậy \(\dfrac{111}{115}< \dfrac{555}{559}\).

a)\(\dfrac{23}{99}\)và \(\dfrac{232323}{999999}\)

ta có:\(\dfrac{232323}{999999}\)=\(\dfrac{23}{99}\)

vì \(\dfrac{23}{99}\)=\(\dfrac{23}{99}\)\(\Rightarrow\)\(\dfrac{23}{99}\)=\(\dfrac{232323}{999999}\)

b)\(\dfrac{-63}{84}\)và\(\dfrac{65}{-91}\)

ta có:

\(\dfrac{-63}{84}\)=\(\dfrac{-3}{4}\)=\(\dfrac{-21}{28}\); \(\dfrac{65}{-91}\)=\(\dfrac{-5}{7}\)=\(\dfrac{-20}{28}\)

vì \(\dfrac{-21}{28}\)<\(\dfrac{-20}{28}\)\(\Rightarrow\)\(\dfrac{-63}{84}\)<\(\dfrac{65}{-91}\)

`#3107.101107`

`a)`

Ta có:

\(\dfrac{2727}{3131}=\dfrac{2727\div27}{3131\div31}=\dfrac{27}{31}\)

Vì \(\dfrac{27}{31}=\dfrac{27}{31}\)

\(\Rightarrow\dfrac{27}{31}=\dfrac{2727}{3131}\)

`b)`

Ta có:

\(\dfrac{11}{31}=1-\dfrac{20}{31}=1-\dfrac{200}{310}\)

\(\dfrac{111}{311}=1-\dfrac{200}{311}\)

Vì \(\dfrac{200}{310}>\dfrac{200}{311}\)

\(\Rightarrow1-\dfrac{200}{310}< 1-\dfrac{200}{311}\)

\(\Rightarrow\dfrac{11}{31}< \dfrac{111}{311}.\)

27/31 = 2727/3131

11/31 bé hơn 111/311