320-20[(3^3+20^0):7-1]=
3✓20 + 7✓45 - 3✓80 + 2✓320 + 5✓500 giúp mình với ạ mình xin cảm ơn
\(=6\sqrt{5}+21\sqrt{5}-12\sqrt{5}+16\sqrt{5}+50\sqrt{5}=81\sqrt{5}\)
Bài 1: 1) tìm x biết
A, 9/20 -8/15 . 5/12. B, 2/3÷4/5÷7/12. C, 7/9.1/3+7/9.2/3
2)tìm x biết
A, 2.(x-1)=4026. B, x.3,7+6,3.x=320. C, 0,25.3<3<1,02
Bài 1:
a) \(\dfrac{9}{20}-\dfrac{8}{15}\times\dfrac{5}{12}\)
\(=\dfrac{9}{20}-\dfrac{2}{9}\)
\(=\dfrac{41}{180}\)
b) \(\dfrac{2}{3}\div\dfrac{4}{5}\div\dfrac{7}{12}\)
\(=\dfrac{2}{3}\times\dfrac{5}{4}\times\dfrac{12}{7}\)
\(=\dfrac{5}{6}\times\dfrac{12}{7}\)
\(=\dfrac{10}{7}\)
c) \(\dfrac{7}{9}\times\dfrac{1}{3}+\dfrac{7}{9}\times\dfrac{2}{3}\)
\(=\dfrac{7}{9}\times\left(\dfrac{1}{3}+\dfrac{2}{3}\right)\)
\(=\dfrac{7}{9}\times1\)
\(=\dfrac{7}{9}\)
Bài 2:
a) \(2\times\left(x-1\right)=4026\)
\(\left(x-1\right)=4026\div2\)
\(x-1=2013\)
\(x=2014\)
Vậy: \(x=2014\)
b) \(x\times3,7+6,3\times x=320\)
\(x\times\left(3,7+6,3\right)=320\)
\(x\times10=320\)
\(x=320\div10\)
\(x=32\)
Vậy: \(x=32\)
c) \(0,25\times3< 3< 1,02\)
\(\Leftrightarrow0,75< 3< 1,02\) ( S )
=> \(0,75< 1,02< 3\)
Đặt tính rồi tính:
a, 20÷7
b, 56 + 320
c, 128 - 12
d, 56×3
1) 2³ .x -5² x = 2( 5² + 2² ) -33. 2) 15÷ ( x +2) = (3³ +3) ÷1
3) 20÷ (x +1) = (5² +1 ) ÷13. 4) 320÷ ( x -1 ) = (5³ - 5² ) ÷4 +15
5) 240 ÷ ( x -5 ) = 2² .5² -20. 6) 70 ÷ ( x -3) = ( 3⁴ -1) ÷ 4 - 10
Giúp mình với mình Tối nay mình đi học rồi
1) \(2^3\times x-5^2\times x=2\times\left(5^2+2^2\right)-33\)
\(x\times\left(2^3-5^2\right)=2\times\left(25+4\right)-33\)
\(x\times\left(8-25\right)=2\times29-33\)
\(x\times-17=25\)
\(x=-\dfrac{25}{17}\)
2) \(15\div\left(x+2\right)=\left(3^3+3\right)\div1\)
\(15\div\left(x+2\right)=\left(27+3\right)\div1\)
\(15\div\left(x+2\right)=30\div1\)
\(15\div\left(x+2\right)=30\)
\(x+2=\dfrac{1}{2}\)
\(x=-\dfrac{3}{2}\)
3) \(20\div\left(x+1\right)=\left(5^2+1\right)\div13\)
\(20\div\left(x+1\right)=\left(25+1\right)\div13\)
\(20\div\left(x+1\right)=26\div13\)
\(20\div\left(x+1\right)=2\)
\(x+1=20\div2\)
\(x+1=10\)
\(x=9\)
4) \(320\div\left(x-1\right)=\left(5^3-5^2\right)\div4+15\)
\(320\div\left(x-1\right)=\left(125-25\right)\div4+15\)
\(320\div\left(x-1\right)=100\div4+15\)
\(320\div\left(x-1\right)=25+15\)
\(320\div\left(x-1\right)=40\)
\(x-1=8\)
\(x=9\)
5) \(240\div\left(x-5\right)=2^2\times5^2-20\)
\(240\div\left(x-5\right)=4\times25-20\)
\(240\div\left(x-5\right)=100-20\)
\(240\div\left(x-5\right)=80\)
\(x-5=30\)
\(x=35\)
6) \(70\div\left(x-3\right)=\left(3^4-1\right)\div4-10\)
\(70\div\left(x-3\right)=\left(81-1\right)\div4-10\)
\(70\div\left(x-3\right)=80\div4-10\)
\(70\div\left(x-3\right)=20-10\)
\(70\div\left(x-3\right)=10\)
\(x-3=7\)
\(x=10\)
\(S=1x2+2x3+3x4+.....+38x39+39x40\)
Tính S
Số các số nguyên x thỏa mãn là \(15-\left|-2x+3\right|.\left|5+4x\right|=-19\)
a)S=3+31+32+33+34+......+320
chứng minh chia hết cho 20
THỰC HIỆN CÁC PHÉP TÍNH SAU :
A= 3 - (-6/7)^0 + (1/2)^2 : 2
B= (-2)^3 + 2^2 + (-1)^20 + (-20)^0
C= 2^3 +3 * (1/2)^0 -(1/2)^2 *4 + [(-2)^2 :1/2] *8
Chú thích:
* = nhân
b1 tìm x ,biết
(x-14)-20=5
128+(202-x)=330
(x-120)*9=450
x-320:32=25*16
25-(2x+10)=5
315-(135-x)=215
x:2+21:3=37
4*(x+100)=800
504:(16-5x)=72
(x-5):7+3=20
mik cảm ơn nhaa
(x-14)-20=5
=> x-14 = 25
=> x = 39
Các dạng toán như này lớp 6 ai cũng làm được cả * lười vừa thôi*
( x - 14 ) - 20 = 5
x - 14 = 5 + 20
x - 14 = 25
x = 25 + 14
x = 39
128 + ( 202 - x ) = 330
[ 202 - x ] = 330 - 128
202 - x = 202
x = 202 - 202
x = 0
( x - 120 ) x 9 = 450
[ x - 120 ] = 450 : 9
x - 120 = 50
x = 50 + 120
x = 170
x - 320 : 32 = 25 x 16
x - 320 : 32 = 400
x - 320 = 400 x 32
x - 320 = 12800
x = 12800 + 320
x = 13120
25 - ( 2x +10 ) = 5
[ 2x + 10] = 25 - 5
2x + 10 = 20
2x = 20 - 10
2x = 10
x = 10 : 2
x = 5
315 - ( 135 - x ) = 215
[ 135 - x ] = 315 - 215
[ 135 - x ] = 100
x = 135 - 100
x = 35
x : 2 + 21 : 3 = 37
x : 2 + 21 = 37 x 3
x : 2 + 21 = 111
x : 2 = 111 - 21
x : 2 = 90
x = 90 x 2
x = 180
4 x ( x + 100 ) = 800
[ x + 100 ] = 800 : 4
[ x + 100 ] = 200
x = 200 - 100
x = 100
504 : ( 16 - 5x ) = 72
[ 16 - 5x ] = 504 : 72
[ 16 - 5x ] = 7
5x = 16 - 7
5x = 9
x = \(\dfrac{9}{5}\)
( x - 5 ) : 7 + 3 = 20
[ x - 5 ] : 7 = 20 - 3
[ x - 5 ] : 7 = 17
[ x - 5 ] = 17 x 7
x - 5 = 119
x = 119 + 5
x = 124