Đặt \(A=\sqrt{50}+\sqrt{26}+1\)

Ta thấy: \(\sqrt{50}>\sqrt{49}=7,\sqrt{26}>\sqrt{25}=5\)

\(\Rightarrow A>\sqrt{49}+\sqrt{25}+1=7+5+1=13\left(1\right)\)

Ta thấy: \(\sqrt{168}< \sqrt{169}=13\left(2\right)\)

Từ (1) và (2) => \(\sqrt{50}+\sqrt{26}+1>13>\sqrt{168}\Rightarrow\sqrt{50}+\sqrt{26}+1>\sqrt{168}\)

\(\sqrt{50}>\sqrt{49}=7\)

\(\sqrt{26}>\sqrt{25}=5\)

\(\sqrt{1}=1\)

cộng vào \(VT>VP=13>\sqrt{169}>\sqrt{168}\)

\(\sqrt{50}+\sqrt{26}+1>\sqrt{168}\)

bt la vay nhung cach trinh bay la the nao??? 

căn 50 > căn 49
căn 26 > căn 25
==> căn 50 + căn 26 + 1 > căn 49+ căn 25 +1= 7+5+1=13
Lại co 13= căn 169 > căn 168
=> can 20 + can 26+ 1>13> can 168
 

\(\sqrt{27}>\sqrt{25}=5.\)

\(\sqrt{26}>\sqrt{25}=5.\)

\(\sqrt{27}+\sqrt{26}+1>5+5+1=11.\)

\(\sqrt{99}< \sqrt{100}=10\)

\(\sqrt{27}+\sqrt{26}+1>\sqrt{99}\)

ta có : \(\sqrt{27}+\sqrt{26}+1\approx11,29\)

                \(\sqrt{99}\approx9,94\)

\(\Rightarrow\sqrt{27}+\sqrt{26}+1>\sqrt{99}\)

\(\sqrt{27}>\sqrt{25}=5\)(1)

\(\sqrt{26}>\sqrt{25}=5\)(2)

\(\sqrt{99}< \sqrt{100}=10\)(3)

Từ (1) và (2) và (3) ta có \(:\)\(\sqrt{27}+\sqrt{26}>5+5=10>\sqrt{99}\)

                        \(\Rightarrow\sqrt{27}+\sqrt{26}+1>\sqrt{99}\)

\(\sqrt{17}+\sqrt{26}+1>\sqrt{16}+\sqrt{25}+1=4+5+1=10\)

\(\sqrt{99}\sqrt{99}\)

\(\sqrt{17}+\sqrt{26}+1>\sqrt{16}+\sqrt{25}+1=4+5+1=10=\sqrt{100}>\sqrt{99}\)

Bui Cam Lan Bui ko có tick chán ghê         

\(\sqrt{50}+\sqrt{26}+1>\sqrt{168}\)

thế này nhé:

\(\sqrt{50}>\sqrt{49}=7\)

\(\sqrt{26}>\sqrt{25}=5\)

\(\Rightarrow\sqrt{50}+\sqrt{26}>5+7+1=13\)

MÀ  : \(\sqrt{168}<\sqrt{169}=13\)

=>\(\sqrt{50}+\sqrt{26}+1>\sqrt{49}+\sqrt{25}+1=13>\sqrt{168}\)

VẬY : \(\sqrt{50}+\sqrt{26}+1>\sqrt{168}\)

k cho mh nha bạn

\(\sqrt{17}+\sqrt{26}+1>\sqrt{16}+\sqrt{25}+1=4+5+1=10=\sqrt{100}>\sqrt{99}\)

Vậy..........