Ta có: 2+4+6+8+…+2.n=210

=>2.1+2.2+2.3+2.4+…+2.n=210

=>2.(1+2+3+4+…+n)=210

=>1+2+3+4+…+n=210:2

=>n.(n+1):2=210:2

=>n.(n+1)=210=14.15

=>n.(n+1)=14.(14+1)

=>n=14

2+4+6+8+...+2x=210

=>2.1+2.2+2.3+2.4+...+2.x=210

=>2.(1+2+3+4+...+x)=210

=>1+2+3+4+...+x=210:2

=>1+2+3+4+...+x=105

=>x=14

2+4+6+8+...+2x=210

=>2.1+2.2+2.3+2.4+...+2.x=210

=>2.(1+2+3+4+...+x)=210

=>1+2+3+4+...+x=210:2

=>1+2+3+4+...+x=105

=>x=14

a, 2+4+...+2n=210

=> 2(1+2+...+n)=210

=> \(\frac{2n\left(n+1\right)}{2}=210\)

=> n(n+1) = 210

Mà 14.15 = 210

=> n=14

b, 1+3+....+2n=225

=> \(\frac{\left[\left(2n+1\right)-1\right].n}{2}=225\)

=> \(\frac{2n.n}{2}=225\)

=> n² = 225

=> \(n=\pm15\)

b, tiếp....n=\(\pm15\)

Mà n thuộc N nên n=15

2 + 4 + 6 + 8 + ... + 2n = 210

=> 2 . (1 + 2 + 3 + 4 + ... + n) = 210

=> 1 + 2 + 3 + 4 + ... + n = 210 : 2

=> 1 + 2 + 3 + 4 + ... + n = 105

=> n . (n + 1) : 2 = 105

=> n . (n + 1) = 105 . 2

=> n . (n + 1) = 210

Vì 14 . 15 = 210 => n = 14

b) 1 + 3 + 5 + ... + (2n - 1) = 225

<=> {[(2n - 1) + 1] . [(2n - 1) - 1] : 2 + 1} : 2 = 225

<=> (2n . 2n) : 4 = 225

<=> n² = 225

=> n = 15.

2 + 4 + 6 +.......... + 2n = 210

 1 * 2 + 2 * 2 + 2 * 3 + ..... + 2n = 210

2 ( 1 + 2 + 3 +...... + n ) = 210

1 + 2 + 3 +....... + n = 105

\(\frac{n\left(n+1\right)}{2}=105\)

n(n + 1 ) = 210

n(n+ 1 ) = 14 * 15

n( n + 1 ) = 14 ( 14 + 1 )

=> n = 14

Câu b làm tương tự

2+4+6+8+...+2n = 210

2.(1+2+3+4+...+n) = 210

1+2+3+4+...+n = 210:2

1+2+3+4+...+n = 105

=> n.(n+1):2 = 105

n.(n+1) = 105.2

n.(n+1) = 210

Vì 14.15 = 210 => n = 14

2+4+6+...+2n = 210

((2n-2):2+1). (2n+2):2=210

n.(n+1)= 210

mà 210 = 15.14

=> n+1=15=> n=14

     n+1=14=> n= 13(L)

vậy n= 14

2+4+6+...+2n= 210

1.2+2.2+2.3+...+2n=210

2.(1+2+3+...+n)=210

1+2+3+...+n= 105

n(n+1) :2=105

n(n+1)=210

Mà 210=14.15

=>n(n+1)=14.15

=> n=14

a) 2 + 4 + 6 + ... + 2n = 210

1.2 + 2.2 + 2.3 + ... + 2n = 210

2.(1+2+3+...+n) = 210

1 + 2 + 3 + n = 105

n(n+1):2 = 105

n(n+1) = 210 = 14.15

=> n = 144

b) 1 + 3 + 5 + ... + ( 2n - 1 ) = 225

( 2n-1 + 1).n/2 = 225

n² = 225

=> n = 15

n(n+1) Là gì?zZz Hóng hớt zZz

câu a. n=14 chớ ko phải 144

a) 2 + 4 + 6 + ... +  2n = 210 

1.2 + 2.2 + 2.3 + ... + 2n = 210

2.(1+2+3+...+n) = 210

1 + 2 + 3 + ... + n = 105

\(\frac{n\left(n+1\right)}{2}\)= 105

n(n+1) = 210

n(n+1) = 14.15

=> n = 14

b) 1+3+5+...+(2n-1)=225

\(\frac{\left(2n-1+1\right).n}{2}\)  =225

\(\frac{2n.n}{2}\) =225

\(\frac{2.n^2}{2}\)     =225

\(n^2\) =225

Ta có: \(n^2\)  =225  = \(3^2\).\(5^2\)= \(\left(15\right)^2\)

=> n = 15

Câu a tương tự câu c và d