so sánh:
a) A=\(\frac{2014.2015-1}{2014.2015}\)và C=\(\frac{2015.2016-1}{2015.2016}\)
b)B=\(\frac{2015.2016+1}{2015.2016}\)và D=\(\frac{2016.2017+1}{2016.2017}\)
So sánh: M = \(\frac{2014.2015-1}{2014.2015}\) và N = \(\frac{2015.2016-1}{2015.2016}\)
Vì \(2014.2015=2014.2015\)nên \(2014.2015-1< 2014.2015\)1 đơn vi
Vì \(2015.2016=2015.2016\)nên \(2015.2016-1< 2015.2016\)1 đơn vị
Ta có :
\(1-M=1-\frac{2014.2015-1}{2014.2015}=\frac{1}{2014.2015}\)
\(1-N=1-\frac{2015.2016-1}{2015.2016}=\frac{1}{2015.2016}\)
Vì \(2015=2015\)nên \(2014.2015< 2015.2016\)
Vì \(\frac{1}{2014.2015}>\frac{1}{2015.2016}\)( do \(2014.2015< 2015.2016\))
Nên \(N>M\)
Vậy \(N>M\)
1. So sanh :
a) \(\frac{2015.2016-1}{2016.2015}\) va \(\frac{2016.2017-1}{2016.2017}\)
b) \(\frac{2015.2016}{2015.2016+1}\) va \(\frac{2016.2017}{2016.2017+1}\)
c) \(\frac{33.10^3}{2^3.5.10^3+7000}\) va \(\frac{3774}{5271}\)
a.\(\frac{2015.2016-1}{2015.2016}=1-\frac{1}{2015.2016}\)
\(\frac{2016.2017-1}{2016.2017}=1-\frac{1}{2016.2017}\)
vì \(\frac{1}{2015.2016}>\frac{1}{2016.2017}\)
=>\(-\frac{1}{2015.2016}< -\frac{1}{2016.2017}\)
=>\(1-\frac{1}{2015.2016}< 1-\frac{1}{2016.2017}\)
so sánh
\(\frac{456}{461}\)và \(\frac{123}{128}\) ; \(\frac{2014.2015-1}{2014.2015}\) và \(\frac{2015.2016-1}{2015.2016}\)
a) So sánh \(\frac{461}{456}\) và \(\frac{128}{123}\):
\(\frac{461}{456}\) = \(\frac{456+5}{456}=1+\frac{5}{456};\frac{128}{123}=\frac{123+5}{123}=1+\frac{5}{123}\)
Vì \(\frac{1}{456}
Cho A=2015.2016/2015.2016+1 và B=2016.2017/2016.2017+1
So sánh A vs B
Bạn nào giải đc mk sẽ tick
a) Hãy so sánh M=2015.2016-1/2015.2016 với N=2016.2017-1/2016.2017
so sánh: 58/89 và 36/53; 25/103 và 74/294; \(\frac{2014.2015}{2014.2015+3}\) và \(\frac{2015.2016-2}{2015.2016+1}\)
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{2015.2016}+\frac{1}{2016.2017}\)
\(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{2016\cdot2017}\)
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2016}-\frac{1}{2017}\)
\(=1-\frac{1}{2017}=\frac{2016}{2017}\)
So sánh :
2015.2016-1
2015.2016
và
2016.2017-1
2016.2017
Tính một cách hợp lí tổng sau :
A = \(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{2015.2016}+\frac{1}{2016.2017}.\)
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+.....+\frac{1}{2016.2017}\)
\(A=\left(\frac{1}{1}-\frac{1}{2}\right)+\left(\frac{1}{2}-\frac{1}{3}\right)+......+\left(\frac{1}{2016}-\frac{1}{2017}\right)\)
\(A=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+....+\frac{1}{2016}-\frac{1}{2017}\)
\(A=\frac{1}{1}-\frac{1}{2017}\)
\(A=\frac{2016}{2017}\)
A=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+.....+\frac{1}{2016.2017}\)
\(\Rightarrow A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+......+\frac{1}{2016}-\frac{1}{2017}\)
\(\Rightarrow A=1-\frac{1}{2017}\)
\(\Rightarrow A=\frac{2016}{2017}\)
\(A=\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+...+\frac{1}{2015.2016}+\frac{1}{2016.2017}\)
\(\Rightarrow A=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+...+\frac{1}{2015}-\frac{1}{2016}+\frac{1}{2016}-\frac{1}{2017}\)
\(\Rightarrow A=1-\frac{1}{2017}\)
\(\Rightarrow A=\frac{2016}{2017}\)