a) (x – 45).27 = 0 ó x – 45 = 0 ó x = 45

b) 45.(2x – 4).13 = 0 ó 2x – 4 = 0 ó 2x – 4 = 0 ó 2x = 4 ó x = 2

c) (x – 3).(x – 5) = 0

Vậy tập nghiệm của phương trình là S = {3;5}

a x=45+0=45

(82 - 5.x) : 13 - 4 = 0

(82 - 5.x) : 13 = 0 + 4

(82 - 5.x) : 13 = 4

(82 - 5.x) = 4 . 13

(82 - 5.x) = 52

5.x  = 82 - 52

5.x = 30

x = 30 : 5 = 6

(32 . 45) : 2 = (x + 70) : 14 - 40

720 = (x + 70) : 14 - 40

(x + 70) : 14 = 720 + 40

(x + 70) : 14 = 760

(x + 70) = 760 . 14

(x + 70) = 10640

x = 10640 - 70

x = 10570

Tìm x biết : 

( 82 - 5 . x ) : 13 - 4 = 0 

( 82 - 5 . x ) : 13 = 0 + 4 

( 82 - 5 . x )  : 13 = 4 

82 - 5 . x = 4 × 13 

82 - 5 . x = 52 

5 . x = 82 - 52 

5 . x = 30 

x = 30 : 5 

x = 6

Vậy x = 6

  a) ( 82- 5x ): 13- 4= 0

( 82- 5x ): 13           = 0+ 4

( 82- 5x ): 13           = 4

82- 5x                      = 4. 13

82- 5x                      = 52

5x                            =  82- 52

5x                            = 30

x                              = 30: 5

x                              = 6

  b) ( 32. 45 ): 2= ( x+ 70 ): 14- 40

1440: 2             = ( x+ 70 ): 14- 40

720                    = ( x+ 70): 14- 40

   => ( x+ 70 ): 14= 720+ 40

( x+ 70 ): 14       = 760

x+ 70                  = 760. 14

x+ 70                  = 10640

x                         = 10640- 70

x                         = 10570

x + 3 0   :   − 45   =   −  4 x + 3 0   =   − 4 .   − 45 x + 3 0   =  18 0 x   = 18 0   –  3 0 x   = 15 0

Theo đề bài ta có

x+1/5-1/9+1/9-1/13+.........+1/41-1/45=-37/45

x+(1/5-1/45)=-37/45

x+8/45=-37/45

x=-37/45 - 8/45

x=-45/45

x=-1

Theo bài ra ta có:

x1/5-1/9+1/9-1/13+...+1/41-1/45=-37/45

x+8/45=-37/45

x=-45/45

x=-1/1

x=-1

Cho mình sửa xíu x1/5 sửa thành x+1/5

\(x+\frac{4}{5.9}+\frac{4}{9.13}+\frac{4}{13.17}+...+\frac{4}{41.45}=\frac{-37}{45}\)

\(x+4\left(\frac{1}{5.9}+\frac{1}{9.13}+\frac{4}{13.17}+...+\frac{1}{41.45}\right)=\frac{-37}{45}\)

\(x+4.\frac{1}{4}\left(\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+\frac{1}{13}-\frac{1}{17}+...+\frac{1}{41}-\frac{1}{45}\right)=\frac{-37}{45}\)

\(x+1\left(\frac{1}{5}-\frac{1}{45}\right)=\frac{-37}{45}\)

\(x+\frac{8}{45}=\frac{-37}{45}\)

\(x=\frac{-37}{45}-\frac{8}{45}\)

\(x=\frac{-45}{45}=-1\)

LÀ 4,23 

x có  là 4,23

Ta có:

\(\frac{7}{x}+\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{41.45}\)

\(=\frac{7}{x}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+...+\frac{1}{41}-\frac{1}{45}\)

\(=\frac{7}{x}+\frac{1}{5}-\frac{1}{45}\)

\(=\frac{7}{x}+\frac{9}{45}-\frac{1}{45}=\frac{7}{x}+\frac{8}{45}=\frac{29}{45}\)

\(\Rightarrow\frac{7}{x}=\frac{29}{45}-\frac{8}{45}=\frac{21}{45}=\frac{7}{15}\)

\(\Rightarrow x=15\)

Vậy x=15