Ta có:

\(\frac{2^3.3^3.35}{2^4.3^2.21}=\frac{3.5}{2.3}=\frac{5}{2}\)

Vậy ...

hok tốt!!

viết hẳn ra

\(A=\frac{49^2\cdot3^{11}}{81^2\cdot21^5}\)

\(=\frac{\left(7^2\right)^2\cdot3^{11}}{\left(3^4\right)^2\cdot\left(3\cdot7\right)^5}\)

\(=\frac{7^4\cdot3^{11}}{3^8\cdot3^5\cdot7^5}\)

\(=\frac{7^4\cdot3^{11}}{3^{13}\cdot7^5}\)

\(=\frac{1}{3^2\cdot7}=\frac{1}{63}\)

      Bài làm :

Ta có :

\(A=\frac{49^2\cdot3^{11}}{81^2\cdot21^5}\)

\(A=\frac{\left(7^2\right)^2\cdot3^{11}}{\left(3^4\right)^2\cdot\left(3\cdot7\right)^5}\)

\(A=\frac{7^4\cdot3^{11}}{3^8\cdot3^5\cdot7^5}\)

\(A=\frac{7^4\cdot3^{11}}{3^{13}\cdot7^5}\)

\(A=\frac{1}{3^2\cdot7}\)

\(A=\frac{1}{63}\)

Vậy A=1/63

\(A=\frac{49^2.3^{11}}{81^2.21^5}\)

\(=\frac{\left(7^2\right)^2.3^{11}}{\left(3^4\right)^2.\left(3.7\right)^5}\)

\(=\frac{7^4.3^{11}}{3^8.3^5.7^5}\)

\(=\frac{1}{3^2.7}\)

\(=\frac{1}{63}\)

Học tốt

A=663552 

   (22⋅3)6⋅84⋅35

A=   663552 

  4096⋅177147⋅4096

A=   663552
   2972033482752
A=    1
4478976

tối mk làm cho nha, giờ mk đg bận, sorry

\(\frac{2^{12}.3^5-4^6.9^2}{\left(2^2.3\right)+8^4.3^5}\)

\(\frac{2^{12}.3^5-\left(2^2\right)^6.\left(3^2\right)^2}{2^2.3+2^4.3^4.3^5}\)

\(\frac{2^{12}.3^5-2^{12}.3^4}{2^2.3+2^4.3^{20}}\)

\(\frac{2^{12}.3^4\left(3-1\right)}{2^2.3\left(1+2^2.3^{19}\right)}\)

\(\frac{2^{10}.3^2.4}{1+2^2.3^{19}}\)

bn tự giải tiếp nha mk phải có việc rồi nếu ko lm đc thì kb với mk tối mk giải cho nha