tìm x : (2/x+1)-(5/x-1)=16x^2+1
Tìm x: 4x+1.(16x2-4x+1)-16x.(x2-5)=17
Tìm x: 4x+1.(16x2-4x+1)-16x.(x2-5)=17
Tìm x:
( 4x + 1 )( 16x^2 - 4x + 1 ) - 16x ( 4x^2 - 5 ) = 17
Tính giá trị biểu thức:
p=(x+1)(x^2-x+1)+x-(x-1)(x^2+x+1)+2010; x=-2010)
q=16x(4x^2-5)-(4x+1)(16x^2-4x+1); x=1/5
\(p=\left(x+1\right)\left(x^2-x+1\right)+x-\left(x-1\right)\left(x^2+x+1\right)+2010\)\(=\left(x^3+1\right)+x-\left(x^3-1\right)+2010=x^3+1+x-x^3+1+2010=x+2012\)Với \(x=-2010\Rightarrow p=-2010+2012=2\)
\(q=16x\left(4x^2-5\right)-\left(4x+1\right)\left(16x^2-4x+1\right)=64x^3-80x-64x^3-1=-80x-1\)Với \(x=\dfrac{1}{5}\Rightarrow q=-80.\dfrac{1}{5}-1=-17\)
(x-1)2-(x+2)(x-5)+(4x-1)2=(-x-1)(2-16x)
tìm x
(x - 1)2 - (x + 2)(x - 5) + (4x - 1)2 = (-x - 1)(2 - 16x)
=> x2 - 2x + 1 - x2 + 5x - 2x + 10 + 16x2 - 8x + 1 = -2x + 16x2 -2 + 16x
=> 16x2 - 7x + 12 = 14x - 2 + 16x2
=> -21x = -14
=> 21x = 14
=> x = 2/3
\(\left(x-1\right)^2-\left(x+2\right)\left(x-5\right)+\left(4x-1\right)^2=\left(-x-1\right)\left(2-16x\right)\)
\(\Rightarrow x^2-2x+1-x^2+3x+10+16x^2-8x+1-16x^2-14x+2=0\)
\(\Rightarrow\left(x^2-x^2+16x^2-16x^2\right)+\left(-2x+3x-8x-14x\right)+\left(1+10+1+2\right)=0\)
\(\Rightarrow-21x+14=0\)
\(\Rightarrow-21x=-14\)
\(\Rightarrow x=\frac{2}{3}\)
\(x^2-2x+1-\left(x^2-3x-10\right)+16x^2-8x+1=16x^2+14x-2\)
\(x^2-2x+1-x^2+3x+10+16x^2-8x+1-16x^2-14x+2=0\)
\(-21x-14=0\)
\(-21x=14\)
\(x=\frac{-2}{3}\)
tìm x biết :
a,(2x+ 4/5) (3x-1/2)= 0
b,(x-2/5) (x+4/7)= 0
c,-1 =|x- 5/6|= 1/2
d,x+ 5/8 x- 12/16x= 1
a. 2x+\(\dfrac{4}{5}\)=0 hoặc 3x-\(\dfrac{1}{2}\)=0
2x=- 4/5 hoặc 3x=1/2
x=-2/5 hoặc x=\(\dfrac{1}{6}\)
b. x-\(\dfrac{2}{5}\)=0 hoặc x+\(\dfrac{4}{7}\)=0
x=2/5 hoặc x=-\(\dfrac{4}{7}\)
d. x(1+5/8-12/16)=1
\(\dfrac{7}{8}\)x=1=> x=8/7
tìm x : (4x+1)(16x^2-4x+1)-16x(4x^2-5)=17
64x^3 + 1 - 64x^3 + 80x =17
80x =16
x =3/10
64x^3 + 1 -64x^3 + 80x = 17
80x = 16
x = 3/10
64x^3 + 1 - 64x^3 + 80x = 17
80x = 16
x = 3/10
tìm x:
a.(x-3)^4-(x+3)^4+24x^3=216
b.(2x+1)(16x^4-8x^3+4x^2-2x+1)-(2x-1)(16x^4+8x^3+4x^2+2x+1)=2
tìm GTNN của bt:
x^2+2x+4
x^2-x-5/3/4
4x^2-x-3/16
Tìm x :
a) ( x - 2 )^3 + 6( x + 1 )^2 - x ^3 = -12
b) ( 4x + 1 )( \(16x^2\) - 4x + 1 ) - 16x ( \(4x^2\) - 5 ) = 17
b) \(\left(4x+1\right)\left(16x^2-4x+1\right)-16x\left(4x^2-5\right)=17\)
\(\Leftrightarrow64x^3+1-64x^3+80x=17\)
\(\Leftrightarrow80x=16\)
\(\Leftrightarrow x=\frac{1}{5}\)
bài 1 tìm x:a)(x+2)^3-(x+5)(x^2+x-3)
b)(x+1)^2=2(x+1)(x+2)+(x+2)^2=9
c)(x+2)^3-(x+5)(x^2+x-3)=5
d)(12x-5)(4x-1)+(3x-7)(1-16x)=81