\(\frac{2323+1313+1414+1515+1616}{4141+2222+2323+2424+2525}\)

=\(\frac{8181}{13635}\)

18180,8               

khong hieu

\(\frac{1010+1111+1212+1313+1414+1515+1616+1717}{2020+2121+2222+2323+2424+2525+2626+2727}\)

\(=\frac{101.10+101.11+...+101.17}{101.20+101.21+...+101.27}\)

\(=\frac{101.\left(10+11+...+17\right)}{101.\left(20+21+...+27\right)}\)

\(=\frac{108}{188}\)

\(=\frac{27}{47}\)

\(2>\left(\frac{1}{6}+\frac{2}{15}+\frac{3}{40}+\frac{4}{96}\right)\cdot5.y>\frac{5}{6}\)

\(\Rightarrow2>\left(\frac{1}{6}+\frac{2}{15}+\frac{3}{40}+\frac{1}{24}\right):5.y>\frac{5}{6}\)

\(\Rightarrow2>\left(\frac{20}{120}+\frac{16}{120}+\frac{9}{120}+\frac{5}{120}\right):5.y>\frac{5}{6}\)

\(\Rightarrow2>\frac{5}{12}:5.y>\frac{5}{6}\)

\(\Rightarrow2>\frac{1}{12}.y>\frac{5}{6}\)

Đặt :\(\frac{1}{12}.y=2\Rightarrow y=2:\frac{1}{12}=24\)

\(\frac{1}{12}.y=\frac{5}{6}\Rightarrow y=\frac{5}{6}:\frac{1}{12}=10\)

\(\Rightarrow24>y>10\)

\(\Rightarrow y\in\left\{11;12;...;23\right\}\)

ko biết

I am sorry

Kb nhé

Đề bài kiểu gì vậy?VIết rõ hơn đi

rối mắt á

1414+1515+1616+1717+1818+1919

2020+2121+2222+2323+2424+2525

=19695.95

\(\frac{1414+1515+1616+1717+1818+1919}{2000+2121+2222+2323+2424+2525}\)

\(=\frac{101.\left(14+15+16+17+18+19\right)}{101.\left(20+21+22+23+24+25\right)}\)

\(\frac{14+15+16+17+18+19}{20+21+22+23+24+25}=\frac{99}{135}=\frac{11}{15}\)

L_I_K_E NHA

căm ơn mấy bạn nhak

\(\frac{11}{15}\)

Đinh Tuấn Việt trả lời linh tinh để kiếm l-i-k-e kìa

\(\frac{\text{(1414+1919)+(1515+1818)+(1616+1717) }}{\left(2020+2525\right)+\left(2121+2424\right)+\left(2222+2323\right)}\)\(=\frac{3333+3333+3333}{4545+4545+4545}=\frac{3333}{4545}=\frac{11}{15}\)

đúng rồi mình cũng làm như thế đấy

1414+1515+1616+1717+1818+1919/2020+2121+2222+2323+2424+2525=2525 nhé bạn

Vì 14/14 = 1; 15/15 = 1 ; ....

⇔ Tổng trên là 6 < 11.

Vì 20/20 = 1 ; 21/21 = 1 ; ...

⇒ Tổng trên là 6 < 15.