Tìm x biết -x + 7 = 13.
tìm x y biết 7-x/13+y=7/13 và x+y=2022
Ta có \(\dfrac{7-x}{13+y}=\dfrac{7}{13}\Rightarrow\dfrac{7-x}{7}=\dfrac{13+y}{13}\)
Áp dụng tính chất dãy tỉ số bằng nhau:
\(\dfrac{7-x}{7}=\dfrac{13+y}{13}=\dfrac{13+y-7+x}{13-7}=\dfrac{6+x+y}{6}=\dfrac{2022+6}{6}=338\)
\(\Rightarrow\left\{{}\begin{matrix}7-x=338\times7=2366\\13+y=338\times13=4394\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-2359\\y=4381\end{matrix}\right.\)
tìm x y biết 7-x/13+y=7/13 và x+y=2022
Ta có \(\dfrac{7-x}{13+y}=\dfrac{7}{13}\Rightarrow\dfrac{7-x}{7}=\dfrac{13+y}{13}\)
Áp dụng tính chất dãy tỉ số bằng nhau:
\(\dfrac{7-x}{7}=\dfrac{13+y}{13}=\dfrac{13+y-7+x}{13-7}=\dfrac{6+x+y}{6}=\dfrac{2022+6}{6}=338\)
\(\Rightarrow\left\{{}\begin{matrix}7-x=338\times7=2366\\13+y=338\times13=4394\end{matrix}\right.\Rightarrow\left\{{}\begin{matrix}x=-2359\\y=4381\end{matrix}\right.\)
Tìm x biết : 13/15 - (13/21+x)*7/12 = 7/10
Tìm y biết: ( 7 x 13 + 8 x 13 ) : 9 2 3 - y = 39
Tìm y biết:
b) (7 x 13 + 8 x 13) : ( 2 3 – y) = 39
Tìm x biết:
13/15 - ( 13/21 + x ) . 7/12 = 7/10.
13/15 - (13/21 + x) . 7/12 = 7/10
=> (13/21 + x). 7/12 = 13/15 - 7/10
=> (13/21 + x) . 7/12 = 1/6
=> 13/21 + x = 1/6 : 7/12
=> 13/21 + x = 2/7
=> x = 2/7 - 13/21
=> x = -1/3
Tìm x,biết: a)2/3.x=2/7 b)x.3/5=2/5 c)x:8/13=13/7 d)3/2:x=7/4
ai giúp mik với ạ
\(a,\dfrac{2}{3}.x=\dfrac{2}{7}\\ x=\dfrac{2}{7}:\dfrac{2}{3}=\dfrac{3}{7}\\ ---\\ b,x.\dfrac{3}{5}=\dfrac{2}{5}\\ x=\dfrac{2}{5}:\dfrac{3}{5}=\dfrac{2}{3}\\ ---\\ c,x:\dfrac{8}{13}=\dfrac{13}{7}\\x=\dfrac{13}{7}.\dfrac{8}{13}=\dfrac{8}{7}\\ ----\\ d,\dfrac{3}{2}:x=\dfrac{7}{4}\\ x=\dfrac{3}{2}:\dfrac{7}{4}=\dfrac{3}{2}.\dfrac{4}{7}=\dfrac{6}{7}\)
Tìm x biết ||x-4|-13| = 7
\(|x-4|-13\)
\(\Leftrightarrow \left[\begin{array}{} x-4=13\\ x-4=-13 \end{array} \right.\)
\(\Leftrightarrow \left[\begin{array}{} x=13+4\\ x=(-13)+4 \end{array} \right.\)
\(\Leftrightarrow \left[\begin{array}{} x=17\\ x=-9 \end{array} \right.\)
Vậy x ∈ {17;-9}
\(|x-4|-13=7\)
\(\Leftrightarrow |x-4|=7+13\)
\( \Leftrightarrow |x-4|=20\)
\(\Leftrightarrow \left[\begin{array}{} x-4=20\\ (x-4=-20 \end{array} \right.\)
\(\Leftrightarrow \left[\begin{array}{} x=20+4\\ x=(-20)+4 \end{array} \right.\)
\(\Leftrightarrow \left[\begin{array}{} x=24\\ x=-16 \end{array} \right.\)
Vậy x ∈{24;-16}
\(\left|\left|x-4\right|-13\right|=7\)
\(\Leftrightarrow\left[{}\begin{matrix}\left|x-4\right|-13=7\\\left|x-4\right|-13=-7\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left|x-4\right|=21\\\left|x-4\right|=6\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x-4=21\\x-4=-21\end{matrix}\right.\\\left[{}\begin{matrix}x-4=6\\x-4=-6\end{matrix}\right.\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}\left[{}\begin{matrix}x=25\\x=-17\end{matrix}\right.\\\left[{}\begin{matrix}x=10\\x=-2\end{matrix}\right.\end{matrix}\right.\)
tìm x biết :18/x-13 =3/7 . x=?