25%xX+3/4xX+x=35
b)25%xX+3/4xX+X=35
ai làm được cho tích
=0,25 x X +0,75 x X +X x1=35
=X x (0,25 +0,75 +1)=35
=X x 2=35
X = 35:2
X = 17,5
TÌM X:75%xX+3/4xX+X=30
\(75\%x+\frac{3}{4}x+x=30\)
\(\Leftrightarrow\left(75\%+\frac{3}{4}+1\right)x=30\)
\(\Leftrightarrow\frac{5}{2}x=30\)
\(\Leftrightarrow x=30:\frac{5}{2}\)
\(\Leftrightarrow x=12\)
Tìm X biết : 75%xX+3/4xX+X=30
đổi 75%=3/4.Ta có:
3/4xX+3/4xX+X=30
(3/4+3/4+1)xX=30
5/2 x X=30
X = 30:5/2
X = 12
\(75\%\times x+\frac{3}{4}\times x+x=30\)
\(\frac{3}{4}\times x+\frac{3}{4}\times x+1\times x=30\)
\(\left(\frac{3}{4}+\frac{3}{4}+1\right)\times x=30\)
\(\frac{5}{2}\times x=30\)
\(x=30\div\frac{5}{2}\)
\(x=12\)
giá xăng từ 20 000 đồng lên 21 000 đồng 1 lít . hỏi giá xăng tăng bao nhiêu phần trăm?
75%xX+3/4xX+X=30
tìm X
0,75 x X + 0,75 x X + X = 30
X x ( 0,75 + 0,75 + 1 ) = 30
X x 2,5 = 30
X = 30 : 2,5
X = 12
75%xX+3/4xX+X=30
<=>3/4xX+3/4xX+X=30
<=>10/4xX=30
<=>10xX=120
<=>X=120/10=12
Vậy X=12
75%xX+3/4xX+x=30
toán tìm X
0,75x + 0,75x = 30
0,75 . 2x = 30
2x = 40
x = 20
\(75\%\cdot x+\frac{3}{4}\cdot x+x=30\)
\(x\cdot\left(\frac{3}{4}+\frac{3}{4}+1\right)=30\)
\(x\cdot\frac{5}{2}=30\)
\(x=30\cdot\frac{2}{5}\)
\(x=12\)
\(75\%\cdot x+\frac{3}{4}\cdot x+x=30\)
\(\frac{3}{4}\cdot x+\frac{3}{4}\cdot x+x=30\)
\(\left(\frac{3}{4}+\frac{3}{4}\right)\cdot x+x=30\)
\(\frac{3}{2}\cdot x+x=30\)
\(\frac{3}{2}\cdot x+\frac{1}{1}\cdot x=30\)
\(\left(\frac{3}{2}+\frac{1}{1}\right)\cdot x=30\)
\(\frac{5}{2}\cdot x=30\)
\(x=30\text{ : }\frac{5}{2}\)
\(x=12\)
75%xx+3/4xx+x=30
= 75% x X + 3/4 x X + X = 30
= X x (3/4 + 3/4 + 1) = 30
= X x 10/4 = 30
= X = 30 : 10/4
X = 12
75%xX+3/4xX+X=30
x+0,25= 18/5+43/4
( 5xX+7):2= 16 128 - 3 x(X - 4)=23 [ (4xX+28) x 3+55 ] :5=35
\(\left(5\cdot x+7\right):2=16\) \(128-3\cdot\left(x-4\right)=23\)
\(\left(5\cdot x+7\right)=16\cdot2\) \(3\cdot\left(x-4\right)=128-23\) \([\left(4\cdot x+28\right)\cdot3+55]:5=35\)
\(\left(5\cdot x+7\right)=32\) \(3\cdot\left(x-4\right)=105\) \([\left(4\cdot x+28\right)\cdot3+55]=35\cdot5\)
\(5\cdot x=32-7\) \(x-4=105:3\) \([\left(4\cdot x+28\right)\cdot3+55]=175\)
\(5\cdot x=25\) \(x-4=35\) \(\left(4\cdot x+28\right)\cdot3=175-55\)
\(x=25:5\) \(x=35+4\) \(\left(4\cdot x+28\right)\cdot3=120\)
\(x=5\) \(x=39\) \(\left(4\cdot x+28\right)=120:3\)
\((4\cdot x+28)=40\)
\(4\cdot x=40-28\)
\(4\cdot x=12\)
\(x=12:4\)
\(x=3\)
Chúc bạn hok tốt !
a) 5x X+7=16x2 b)3x(X-4)=128-23 c)(4x X +28 ) x 3 + 55 = 35 x 5
5xX+7=32 3x(X-4)=105 (4x X + 28) x3 +55 =175
5xX=32-7 X-4 = 105 : 3 (4x X + 28 ) x3 = 175 -55
5xX=25 X-4 = 35 (4x X + 28 ) x3 = 120
X=25:5 X = 35 + 4 4x X + 28 = 120 : 3=40
X=5 X = 39 X = (40-28):4=3
Tìm X:
4xX/1x5+4xX/5x9+4xX/9x13+4xX/13x17=16
\(\dfrac{4\times x}{1\times5}\) + \(\dfrac{4\times x}{5\times9}\) + \(\dfrac{4\times x}{9\times13}\) + \(\dfrac{4\times x}{13\times17}\) = 16
\(x\times\left(\dfrac{4}{1\times5}+\dfrac{4}{5\times9}+\dfrac{4}{9\times13}+\dfrac{4}{13\times17}\right)\) = 16
\(x\) \(\times\) (\(\dfrac{1}{1}\) - \(\dfrac{1}{5}\) + \(\dfrac{1}{5}\) - \(\dfrac{1}{9}\) + \(\dfrac{1}{9}\) - \(\dfrac{1}{13}\) + \(\dfrac{1}{13}\) - \(\dfrac{1}{17}\)) = 16
\(x\) \(\times\) ( \(\dfrac{1}{1}\) - \(\dfrac{1}{17}\)) = 16
\(x\) \(\times\) \(\dfrac{16}{17}\) = 16
\(x\) = 16 : \(\dfrac{16}{17}\)
\(x\) = 17