a.x+18=6-2x
b,17-x=7-6x
c,x+15=20-4x
d,7x-4=20+3x
e,-12+x=5x-20
f.4x-18=x+27
a, \(x+18\) = 6 - 2\(x\)
\(x\) + 2\(x\) = 18 - 6
3\(x\) = 12
\(x\) = 4
b, 17 - \(x\) = 7 - 6\(x\)
- \(x\) + 6\(x\) = 7 - 17
5\(x\) = - 10
\(x\) = - 2
c, \(x\) + 15 = 20 - 4\(x\)
\(x\) + 4\(x\) = 20 - 15
5\(x\) = 5
\(x\) = 1
d, 7\(x\) - 4 = 20 + 3\(x\)
7\(x-3x=20+4\)
4\(x\) = 24
\(x\) = 6
e, -12 + \(x\) = 5\(x\) - 20
-12 + 20 = 5\(x\) - \(x\)
4\(x\) = 8
\(x\) = 2
f, 4\(x\) - 18 = \(x\) + 27
4\(x\) - \(x\) = 27 + 18
3\(x\) = 45
\(x\) = 15
18- 4x = -20-6x
h)-15 x 24 = - 7x +32
i) 15x- 3(4x - 6) = - 12+ 36
k) -10 x - 27 = - 7x +33
m) -17 x - 24 = - 9x - 40
n) -23 x 25 = - 18x +75
p) - 5x+ 7( 2x-3) = 4( x - 4)
q)24- 6(3x + 1) = -5( 4x- 4 ) - 8
r) 18-4. (6-2x) = -3.(4x +5 ) - 11
Jup mik pls
18 - 4\(x\) = -20 - 6\(x\)
-4\(x\) + 6\(x\) = - 20 - 18
2\(x\) = - 38
\(x\) = - 19
h, -15 \(\times\) 24 = -7\(x\) + 32
7\(x\) = 360 + 32
7\(x\) = 392
\(x\) = 392:7
\(x\) = 56
i, 15\(x\) -3.(4\(x\) - 6) = -12 + 36
15\(x\) - 12\(x\) + 18 = 24
3\(x\) = 24 - 18
3\(x\) = 6
\(x\) = 2
k, -10\(x\) - 27 = -7\(x\) + 33
-27 - 33 = -7\(x\) + 10\(x\)
3\(x\) = -60
\(x\) = -20
m, -17\(x\) - 24 = - 9\(x\) - 40
- 24 + 40 = -9\(x\) + 17\(x\)
8\(x\) = 16
\(x\) = 2
n, -23 \(\times\) 25 = -18\(x\) + 75
-575 = -18\(x\) + 75
18\(x\) = 575 + 75
18\(x\) = 650
\(x\) = \(\dfrac{325}{9}\)
Giải phương trình
1) 16-8x=0
2) 7x+14=0
3) 5-2x=0
4) 3x-5=7
5) 8-3x=6
6) 8=11x+6
7)-9+2x=0
8) 7x+2=0
9) 5x-6=6+2x
10) 10+2x=3x-7
11) 5x-3=16-8x
12)-7-5x=8+9x
13) 18-5x=7+3x
14) 9-7x=-4x+3
15) 11-11x=21-5x
16) 2(-7+3x)=5-(x+2)
17) 5(8+3x)+2(3x-8)=0
18) 3(2x-1)-3x+1=0
19)-4(x-3)=6x+(x-3)
20)-5-(x+3)=2-5x
20) -5-(x + 3) = 2 - 5x ⇔ -5 - x - 3 = 2 -5x ⇔ 4x = 10 ⇔ x = \(\frac{5}{2}\)
Vậy...
1) 16 - 8x = 0 ⇔ 8(2 - x) = 0⇔ 2 - x = 0 ⇔ x = 2
Vậy phương trình có nghiệm là x = 2
giúp mình giải bài toán.......
1)3x-6=5x+2
2)15-x=4x-5
3)x-15=6+4x
4)-12+x=5x-20
5)7x-4=20+3x
6)5x-7=-21-2x
7)x+15=20-4x
8)17-x=7-6x
9)-4|x-2|=-8
10)-7|x+4|=2.(-7)
1) 3x - 6= 5x + 2
5x - 3x = -6 - 2
2x = -8
x = -4
2) 15 - x = 4x - 5
4x + x = 15 + 5
5x = 20
x = 4
Tương tự như trên
1) 3x - 6 = 5x + 2
3x - 5x = 2 + 6
-2x = 8
x = 8 : (-2)
x = -4
2) 15 - x = 4x - 5
-x - 4x = -5 - 15
-5x = -20
x = -20 : (-5)
x = 4
Giải phương trình
1) 16-8x=0
2) 7x+14=0
3) 5-2x=0
4) 3x-5=7
5) 8-3x=6
6) 8=11x+6
7)-9+2x=0
8) 7x+2=0
9) 5x-6=6+2x
10) 10+2x=3x-7
11) 5x-3=16-8x
12)-7-5x=8+9x
13) 18-5x=7+3x
14) 9-7x=-4x+3
15) 11-11x=21-5x
16) 2(-7+3x)=5-(x+2)
17) 5(8+3x)+2(3x-8)=0
18) 3(2x-1)-3x+1=0
19)-4(x-3)=6x+(x-3)
20)-5-(x+3)=2-5x
Mấy cái này chuyển vế đổi dấu là xong í mà :3
1,
16-8x=0
=>16=8x
=>x=16/8=2
2,
7x+14=0
=>7x=-14
=>x=-2
3,
5-2x=0
=>5=2x
=>x=5/2
Mk làm 3 cau làm mẫu thôi
Lúc đăng đừng đăng như v :>
chi ra khỏi ngt nản
từ câu 1 đến câu 8 cs thể làm rất dễ,bn tham khảo bài của bn muwaa r làm những câu cn lại
1, 16 - 8x = 0
<=>-8x = 16
<=> x = -2
Vậy_
2, 7x + 14 = 0
<=> 7x = -14
<=> x = -2
3, 5 - 2x = 0
<=> - 2x = -5
<=> x =\(\frac{5}{2}\)
Vậy_
4, 3x - 5 = 7
<=> 3x = 7 + 5
<=> 3x = 12
<=> x = 4
Vậy...
5, 8 - 3x = 6
<=> - 3x = 6 - 8
<=> -3x = - 2
<=> x =\(\frac{2}{3}\)
Vậy......
18x - 19 = 21+8x
g)18- 4x = -20-6x
h)-15x - 24 = - 7x +32
i) 15x- 3(4x - 6) = - 12+ 36
k) -10 x - 27 = - 7x +33
m) -17 x - 24 = - 9x - 40
n) -23x + 25 = - 18x +75
p) - 5x+ 7( 2x-3) = 4( x - 4)
q)24- 6(3x + 1) = -5( 4x- 4 ) - 8
r) 18-4. (6-2x) = -3.(4x +5 ) - 11
s) - 5. ( 4x-5) - 14 = 6.(2 - 3x) - 10x-9
giúp mik với giải cả cách làm nhé
18x -19 = 21 + 8x
18 x - 8x = 21 + 19
10 x = 40
x =4
g) 18 -4x=-20-6x
-4x + 6x = -20 - 18
2x = -38
x= -19
k, -10 \(x\) - 27 = -7\(x\) + 33
-27 - 33 = -7\(x\) + 10\(x\)
3\(x\) = -60
\(x\) - 20
m, -17\(x\) - 24 = -9\(x\) - 40
-24 + 40 = -9\(x\) + 17\(x\)
8\(x\) = 16
\(x\) = 2
h)-15x -24 = 7x + 32
-15x - 7x = 32 + 24
-22x = 56
x = \(-\dfrac{14}{5}\)
i)15x -3(4x -6)=-12+36
15x - 12x + 18 = 24
3x + 18 = 24
3x = 24 - 18
3x = 6
x=2
Giúp mình v
Bài10872917292872917 tìm x bt
5x-16=40+x
4x-10=15-x
-12+x=5x-2
7x-4=20+3x
5x-7=20+3x
x+15=7+6x
17-x=7-6x
3x+(-21)=12-8x
125:(3x-13)=25
541+(218-z)=735
3(2x+1)-19=14
175-5(x+3)=85
4x-40=|4|+12
x+15=20-4x
8x+|-3|=-4x+39
6(x-2)+(-2)=20-4x
5x-16=40+x
=> 5x-16-x = 40
=> 5x-x -16=40
4x-16=40
4x= 40+16
4x=56
x= 56:4
x=14
Vậy...
4x-10=15-x
=> 4x-10+x= 15
4x+x -10=15
5x= 15+10
5x= 25
x= 25:5
x=5
Vậy....
5x -16=40+x
=> 5x-x=40+16
=>4x=56
=>x=56:4
x=14
Tìm x
1) 5x - 16 = 40 + x
2) 4x - 10 = 15 - x
3) 3x - 6 = 5x + 2
4) 15 - x = 4x - 5
5) x - 15 = 6 + 4x
6) -12 + x = 5x - 20
7) 7x - 4 = 20 + 3x
8) 5x - 7 = -21 - 2x
9) x + 15 = 20 - 4x
10) 17 - x = 7 - 6x
1) (4-3x) (10x-5)=0
2) (7-2x) (4+8x) = 0
3) (9-7x) (11-3x) = 0
4) (7-14x) (x-2) = 0
5) (2x+1) (x-3) = 0
6) (8-3x) (-3x+5) = 0
7) (16-8x) (2-6x) = 0
8) (x+4) (6x-12) = 0
9) (11-33x) (x+11) = 0
10) (x-1/4) (x+5/6) = 0
11) (7/8-2x) (3x+1/3) = 0
12) 3x - 2x^2 = 0
13) 5x + 10x^2 = 0
14) 4x + 3x^2 = 0
15) -8x^2 + x =0
16) 10x^2 - 15x = 0
17) x^2 -4 =0
18) 9 - x^2 = 0
19) x^2 -1 = 0
20) (x-3) (2x-1) = (2x-1) ( 2x+3)
21) (5+4x) (-x+2) = (5+4x) (7+5x)
22) (4+x) (x-5) = (3x-8) (x-5) = 0
23) (3x-8) (7-21x) - (9+2x) (7-21x)
24) (10+ 7x) (x+1) = (9x-2)(x-1)
25) (9x-4) (x-1/2) - (x-1/2) (6+x) = 0
26) 9x^2 - 1 = (3x-1) (x+4)
27) (x+7) (3x+1) = 49-x^2
28) (2x+1)^2 = (x-1)^2
29)x^3- 5x^2+6x = 0
30) 3x^2 + 5x + 2 = 0
Giảii giúpp mìnhh đyy mọii ngườii .
\(\left(4-3x\right)\left(10x-5\right)=0\)
\(\Rightarrow\orbr{\begin{cases}4-3x=0\\10x-5=0\end{cases}\Rightarrow\orbr{\begin{cases}3x=4\\10x=5\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{4}{3}\\x=\frac{1}{2}\end{cases}}}\)
\(\left(7-2x\right)\left(4+8x\right)=0\)
\(\Rightarrow\orbr{\begin{cases}7-2x=0\\4+8x=0\end{cases}\Rightarrow\orbr{\begin{cases}2x=7\\8x=-4\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{7}{2}\\x=-\frac{1}{2}\end{cases}}}}\)
rồi thực hiện đến hết ...
Brainchild bé ngây thơ qus e , ko thực hiện đến hết như thế đc đâu :>
\(\left(x-3\right)\left(2x-1\right)=\left(2x-1\right)\left(2x+3\right)\)
\(2x^2-7x+3=4x^2+4x-3\)
\(2x^2-7x+3-4x^2-4x+3=0\)
\(-2x^2-11x+6=0\)
\(2x^2+11x-6=0\)
\(2x^2+12x-x-6=0\)
\(2x\left(x+6\right)-\left(x+6\right)=0\)
\(\left(x+6\right)\left(2x-1\right)=0\)
\(x+6=0\Leftrightarrow x=-6\)
\(2x-1=0\Leftrightarrow2x=1\Leftrightarrow x=\frac{1}{2}\)
\(3x-2x^2=0\)
\(x\left(2x-3\right)=0\)
\(x=0\)
\(2x-3=0\Leftrightarrow2x=3\Leftrightarrow x=\frac{3}{2}\)
Tự lm tiếp nha