2Y^3-1=15

=> 2.(y^3)=16

y^3=8

y=2

x+16/9=2+30/16

x+16/9=31/8

x=151/72

\(2y^3-1=15=>2y^3=16=>y^3=8=2^3=>y=2\)

Từ \(\frac{x+16}{9}=\frac{y+30}{16}=>\frac{x+16}{9}=\frac{32}{16}=2=>x+16=2.9=18=>x=2\)

Vậy x=2

Từ  \(2y^3-1=15\)  =>  \(2y^3=16\) =>  \(y^3=8=2^3\) =>  \(y=2.\)

Thay y = 2 vào    \(x+\frac{16}{9}=y+\frac{30}{16}\) , ta được :

\(x+\frac{16}{9}=2+\frac{15}{8}=\frac{31}{8}\)=>  \(x=\frac{31}{8}-\frac{16}{9}=\frac{151}{72}.\)

_ Vậy khi đó   \(x=\frac{151}{72}.\)

Chúc bạn học tốt ^-^.

Từ \(2y^3-1=15\Rightarrow2y^3=16\Rightarrow y^3=8=2^3\Rightarrow y=2\)

Thay y = 2 vao \(x+\frac{16}{9}=y+\frac{30}{16}\)duoc :

\(x+\frac{16}{9}=2+\frac{15}{8}=\frac{31}{8}\Rightarrow x=\frac{31}{8}-\frac{16}{9}=\frac{151}{72}\)

\(2x^3-1=15\Rightarrow x^3=\frac{15+1}{2}=8\Rightarrow x=2\)

Thay x = 2, ta được

\(\frac{2+16}{9}=\frac{y-25}{16}=\frac{z+9}{25}=2\)

\(y-25=2.16=32\Rightarrow y=57\)

\(z+9=2.25=50\Rightarrow z=41\)

\(x+y+z=\)\(2+57+41\)\(=100\)

Ta có 2x³ - 1 = 15 

2x³ = 15+ 1=16

x³ =16:2=8 =>x³=2³ => x=2

Thay x = 2 vào biểu thức\(\frac{x+16}{9}\)=> \(\frac{2+16}{9}=\frac{18}{9}=2\)

*\(\frac{y-25}{16}=2\)=> y-25=32 => y = 57

*\(\frac{z+9}{25}=2\)=>z+ 9 = 50 => z= 50-9 = 41

vậy x + y +z = 2 + 57 + 41 = 100

\(2x^3-1=15\Leftrightarrow2x^3=16\Leftrightarrow x^3=8\Leftrightarrow x=2\)

=>\(\frac{2+16}{9}=\frac{y-25}{16}=\frac{z+9}{25}=2\Rightarrow y=57;z=41\)

=> x + y + z = 2 + 57 + 41 = 100

Quá đơn giản :

2x³-1 = 15

=> 2x³=16

=> x³ = 8

=> x  =2

Thay x vào \(\frac{x+16}{9}\)

=> \(\frac{2+16}{9}=2\)

=> \(2=\frac{y-25}{16}\)

=> y-25 = 32

=> y = 57

=> \(2=\frac{z+9}{25}\)

=> z + 9 = 50

=> ...

Đ/S:  ...