khong dung may tinh hay so sanh
A 2011^2010+1/2011^2011+1
khong quy dong hay so sanh
A=-9/102010+-19/102011 ; B-9/102011+ -19/102010
khong quy dong mau so hay so sanh;
A= \(\frac{-9}{10^{2010}}+\frac{-19}{10^{2011}};\) B= \(\frac{-9}{10^{2011}}+\frac{-19}{10^{2010}}\)
so sanh :
a=2010 /2011 +2011/2012 +2012/2013
b =2010+2011+2012 /2011 +20120 +2012
so sanh 1/51+1/52 +1/53 +.......+1/60 voi:
a .1/5
b.1/6
tra loi nhanh ho minh nha !
a < b k mình nha xong mình k lại cho
a)
Ta có a > b vì b > 3 còn a < 3
b)
a. Ta có : 1/51 + 1/52 + 1/53 +...+ 1/60 < 1/51 x 10 < 1/50 x 10 = 1/5
=> 1/51 + 1/52 +1/53 +...+1/60 < 1/5
b. Ta có : 1/51 + 1/52 + 1/53 +...+ 1/60 > 1/60 x 10 = 1/6
=> 1/51 + 1/52 +1/53 +...+ 1/60 > 1/6
a﴿
Ta có a > b vì b > 3 còn a < 3
b﴿
a. Ta có : 1/51 + 1/52 + 1/53 +...+ 1/60 < 1/51 x 10 < 1/50 x 10 = 1/5
=> 1/51 + 1/52 +1/53 +...+1/60 < 1/5
b. Ta có : 1/51 + 1/52 + 1/53 +...+ 1/60 > 1/60 x 10 = 1/6
=> 1/51 + 1/52 +1/53 +...+ 1/60 > 1/6
giup to voi moi nguoi
Thuc hien so sanh: A=2011^2010+1/2011^2011+1 voi B=2011^2011+1/2011^2012+1
Mới học lớp 5 chưa biết bài lớp 6 .
Tha lỗi
A=2010^2011+1/2010^2012+1
B=2010^2010+1/2010^2011+1
SO SANH A VA B
A = 20102011+1/ 20102012+1 < 20102011+1 + 2009 / 20102012+1+2009
= 20102011+2010/20102012+2010
=2010(2010^2010+1) / 2010(2010^2011+1)
= 2010^2010 + 1 / 2010^ 2011 +1 = B
=> A < B
Như vậy mới đúng nè
Ta có B=2010^2010 + 1/ 2010^2011 + 1 < 2010^2010+1+9/2010^2011+1+9=2010^2011+1/2010^2012+1
Vậy B<A
So sanh A va B biet A=2010/2011+2011/2012+2012/2010 va B=1/3+1/4+1/5+....+1/17
so sanh (20102011+1)/(20102012+1)va( 20102010+1)/(20102011+1)
so sanh (20102011+1)/(20102012+1)va( 20102010+1)/(20102011+1)
So sanh:
A = 20102011+1 phan 20102012+1 va B =20102010+1 phan 20102011+1
\(A=\frac{2010^{2011}+1+2009}{2010^{2012}+1+2009}=\frac{2010^{2011}+2010}{2010^{2012}+2010}=\frac{2010\left(2010^{2010}+1\right)}{2010\left(2010^{2011}+1\right)}\)\(=B\)