Ta có:

T = \(\frac{2009\times2010+2000}{2011\times2010-2020}=\frac{2009\times2010+2010-10}{2010\times2010+2010-2020}=\frac{2010\times2010-10}{2010\times2010-10}=1\)

Vậy T = 1

2009×2010+2000/2011×2010-2020

=2009×2010+2000/2009×2010+2×2010-2020

=2009×2010+2000/2009×2010+4020-2020

=2000/4020-2020

=2000/2000

=1

K đúng cho mk nha !!!

Cảm ơn các bạn nhiều lắm.

\(t=\frac{2009.2010+2000}{2011.2010-2020}\)

\(t=\frac{2009.2010+2000}{\left(2009+2\right).2010-2020}\)

\(t=\frac{2009.2010+2000}{2009.2010+2.2010-2020}\)

\(t=\frac{2009.2010+2000}{2009.2010+2000}=1\)

\(q=\frac{\text{2014.2015+2010}}{2016.2015-2020}\)

\(q=\frac{\text{2014.2015+2010}}{\left(2014+2\right).2015-2020}\)

\(q=\frac{\text{2014.2015+2010}}{2014.2015+2.2015-2020}\)

\(q=\frac{\text{2014.2015+2010}}{\text{2014.2015+2010}}=1\)

\(A=\frac{2009x2010+2000}{2011x2010-2020}=\frac{2009x2010+2000}{2009x2010+2x2010-2020}=\frac{2009x2010+2000}{2009x2010+4020-2020}=\frac{2000}{4020-2020}=\frac{2000}{2000}=1\)

Nhấn đúng cho mk nha!!!!!!!!!!

2009x2010+2011x12+1998

      2011x2010-2010x 2009

=2009x2010+2010x12+12+1998

       2010x(2011-2009)

=2010x2009+2010x12+2010x1

              2010x2

=2010x(2009+12+1)

          2010x2

=2010x2022

    2010x2

=2022

     2

=1011

\(=\frac{\left(2009-1\right)\cdot2009+2000}{2009\cdot\left(2009+1\right)-2018}=\frac{2009^2-9}{2009^2-9}=1\\ \)

\(\frac{2009.2011-1}{2011.2010-2012}=\frac{2009.2011-1}{2011.\left(2009+1\right)-2012}\)

\(=\frac{2009.2011-1}{2011.2009+2011-2012}\)

\(=\frac{2009.2011-1}{2009.2011-1}\)

\(=1\)

\(\frac{2009.2011-1}{2011.2010-2012}=\frac{2009.2011-1}{2011.2009-2011-2012}=\frac{2009.2011-1}{2011.2009-1}=1\)

\(\text{ta có : }A=\frac{2009.2010-1}{2009.2010}=\frac{2009.2010}{2009.2010}-\frac{1}{2009.2010}=1-\frac{1}{2009.2010}\)

\(B=\frac{2010.2011-1}{2010.2011}=\frac{2010.2011}{2010.2011}-\frac{1}{2010.2011}=1-\frac{1}{2010.2011}\)

\(\text{Vì }2009.2010\frac{1}{2010.2011}\)

Hay A<B