\(\frac{30\cdot25\cdot7\cdot8}{75\cdot8\cdot12\cdot14}\)=
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\(\frac{30\cdot25\cdot7\cdot8}{75\cdot8\cdot12\cdot14}\)=
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\(\frac{\text{30.25.7.8}}{\text{75.8.12.14}}=\frac{\left(30:6\right).\left(25:25\right).\left(7:7\right).\left(8:8\right)}{\left(75:25\right).\left(8:8\right).\left(12:6\right).\left(14:7\right)}=\frac{5..1.1.1}{3.1.2.2}=\frac{5}{12}\)
Tính nhanh:\(\frac{6\cdot7\cdot8\cdot9\cdot10\cdot11}{22\cdot20\cdot18\cdot16\cdot14\cdot12}\)
= 6.7.4.4.3.3.2.5.11
11.2.4.5.3.6.16.2.7.2.3,2
= 1
16
S=\(\frac{1}{5\cdot6}+\frac{1}{6\cdot7}+\frac{1}{7\cdot8}+...+\frac{1}{24\cdot25}\)
S=\(\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+...+\frac{1}{24.25}\)
= \(\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-\frac{1}{8}+...+\frac{1}{24}-\frac{1}{25}\)
= \(\frac{1}{5}-\frac{1}{25}\)
=\(\frac{4}{25}\)
k mik nha
\(S=\frac{1}{5.6}+\frac{1}{6.7}+\frac{1}{7.8}+...+\frac{1}{24.25}\)
\(S=\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}+\frac{1}{7}-...-\frac{1}{24}+\frac{1}{24}-\frac{1}{25}\)
\(S=\frac{1}{5}-\frac{1}{25}=\frac{4}{25}\)
Vậy \(S=\frac{4}{25}\)
Tính (theo mẫu)
Mẫu:\(\frac{5\cdot6\cdot7\cdot9}{12\cdot7\cdot27}\)=\(\frac{5\cdot6\cdot7\cdot9}{6\cdot2\cdot7\cdot9\cdot3}\)=\(\frac{5}{6}\)
a.\(\frac{3\cdot4\cdot7}{12\cdot8\cdot9}\)=.........................................................................
b.\(\frac{4\cdot5\cdot6}{12\cdot10\cdot8}\)=.......................................................................
c\(\frac{5\cdot6\cdot7}{12\cdot14\cdot15}\)=......................................................................
a.\(\frac{3\cdot4\cdot7}{12\cdot8\cdot9}\)= \(\frac{3\cdot4\cdot7}{3\cdot4\cdot8\cdot9}\)= \(\frac{7}{72}\)
b. \(\frac{4\cdot5\cdot6}{12\cdot10\cdot8}\)= \(\frac{4\cdot5\cdot2\cdot3}{3\cdot4\cdot5\cdot2\cdot8}\)= \(\frac{1}{8}\)
c.\(\frac{5\cdot6\cdot7}{12\cdot14\cdot15}\)= \(\frac{5\cdot6\cdot7}{2\cdot6\cdot2\cdot7\cdot3\cdot5}\)= \(\frac{1}{12}\)
Tính (theo mẫu)
Mẫu:\(\frac{5\cdot6\cdot7\cdot9}{12\cdot7\cdot27}\)=\(\frac{5\cdot6\cdot7\cdot9}{6\cdot2\cdot7\cdot9\cdot3}\)=\(\frac{5}{6}\)
a.\(\frac{3\cdot4\cdot7}{12\cdot8\cdot9}\).............................................
b.\(\frac{4\cdot5\cdot6}{12\cdot10\cdot8}\)...........................................
c.\(\frac{5\cdot6\cdot7}{12\cdot14\cdot15}\)........................................
(Lưu ý:Dấu chấm là dấu nhân)
a, \(\frac{3.4.7}{12.8.9}\)= \(\frac{3.4.7}{3.4.8.9}\)= \(\frac{7}{72}\)
b, \(\frac{4.5.6}{12.10.8}\)= \(\frac{4.5.6}{3.4.2.5.8}\)= \(\frac{1}{8}\)
c, \(\frac{5.6.7}{12.14.15}\)= \(\frac{5.6.7}{2.6.2.7.3.5}\)= \(\frac{1}{12}\)
Tính nhanh:
\(\frac{126\cdot14\cdot12\cdot148\cdot333\cdot15}{74\cdot21\cdot9\cdot37\cdot8\cdot16\cdot18}\)
Giải nhanh hộ mik nha!!
Rút gọn phân số sau : \(\frac{2^3\cdot3^3\cdot5^3\cdot7\cdot8}{3\cdot2^4\cdot5^3\cdot14}\)
Ai xong trước và đúng mình tích cho
\(=\frac{2^3.3^3.5^3.2^3.7}{3.2^4.5^3.2.7}=\frac{2^6.5^3.3^3}{3.2^5.5^3}=2.3^2=2.9=18\)
=\(\frac{2^3\cdot3^3\cdot5^3\cdot2^3\cdot7}{3\cdot2^4\cdot5^3\cdot2\cdot7}=\frac{2^{3_{ }}\cdot3^3\cdot2^3}{3\cdot2^4\cdot2}=\frac{1728}{96}=\frac{18}{1}=18\)
2 câu trên câu nào cũng đúng. nhưng làm theo cách 2 thì nhanh hơn
\(\frac{0,8\cdot0,04\cdot1,25\cdot25+0,6524+0.3476}{10\cdot125\cdot4\cdot25\cdot8}\)
làm giúp mik, mik vộiiii
\(\frac{0,8.0,04.1,25.25+0,6524+0,3476}{10.125.4.25.8}\)
\(=\frac{\left(0,8.1,25\right).\left(0,04.25\right)+\left(0,6524+0,3476\right)}{10.\left(125.8\right).\left(25.4\right)}\)
\(=\frac{1.1+1}{10.1000.100}\)
\(=\frac{1}{500000}\)
nếu mà ra phân số thì mình tính là \(\frac{2}{1000000}\)
nếu mà mình lấy 2:1000000=0,000002
chưa chắc là mình tính đúng đâu bạn nhớ tính lại nhé
chú bạn học giỏi nha
\(B=\frac{2\cdot4+2\cdot4\cdot8+4\cdot8\cdot16+8\cdot16\cdot32}{3\cdot4+2\cdot6\cdot8+4\cdot12\cdot16+8\cdot24\cdot32}\)
\(B=\frac{2.4+2.4.8+4.8.16+8.16.32}{3.4+2.6.8+4.12.16+8.24.32}\)
\(B=\frac{2.4+2.4.8+4.2.4.16+2.4.16.32}{3.4+2.2.3.2.4+4.3.4.16+2.4.8.3.32}\)
\(B=\frac{2.4.\left(1+8+4.16+16.32\right)}{3.4.\left(1+2.2.2+4.16+2.8.32\right)}\)
\(B=\frac{2.4.\left(1+8+4.16+16.32\right)}{3.4.\left(1+8+4.16+16.32\right)}\)
\(B=\frac{2}{3}\)
Chúc bn học tốt !!!!