ta tách : 1,5 * ( 2/3*5 +2/5*7+.........+2/47*49)                                                                                                                                                          1,5*( 1/3-1/5+1/5-1/7 +.............+1/47-1/49)                                                                                                                                                1,5*( 1/3 -1/49) =1,5* 46/147=23/49     

6.S = 3.5.6 + 5.7.6 + 7.9.6 + ...+ 47.49.6

6S = 3.5.(7 - 1) + 5.7.(9 - 3) + 7.9.(11 - 5) + ....+ 47.49.(51 - 45)

6S = 3.5.7 - 1.3.5 + 5.7.9 - 3.5.7 + 7.9.11 - 5.7.9 +...+ 47.49.51 - 45.47.49

6S = -1.3.5 + (3.5.7 - 3.5.7) + (5.7.9 - 5.7.9) + ....+ (45.47.49 - 45.47.49) + 47.49.51

6S = -1.3.5 + 47.49.51 => S = \(\frac{-15+47.49.51}{6}=19573\)

*) Chú ý: Nhân biểu thức cần tính với 3 lần khoảng cách giữa các số để xuất hiện các số hạng đối nhau

\(1,\\ c,\dfrac{17}{6}-\dfrac{3}{7}-\dfrac{5}{6}=\dfrac{17\times7-3\times6-5\times7}{6\times7}=\dfrac{119-18-35}{42}=\dfrac{66}{42}=\dfrac{11}{7}\\ 2,\\ a,\dfrac{6}{9}+\dfrac{3}{15}+\dfrac{7}{15}\\ =\dfrac{6:3}{9:3}+\dfrac{7+3}{15}\\ =\dfrac{2}{3}+\dfrac{10}{15}\\ =\dfrac{2}{3}+\dfrac{2}{3}\\ =\dfrac{2+2}{3}=\dfrac{4}{3}\)

\(b,\dfrac{7}{2}+\dfrac{29}{12}-\dfrac{11}{12}\\ =\dfrac{7}{2}+\left(\dfrac{29}{12}-\dfrac{11}{12}\right)\\ =\dfrac{7}{2}+\dfrac{29-11}{12}\\ =\dfrac{7}{2}+\dfrac{18}{12}\\ =\dfrac{7}{2}+\dfrac{18:6}{12:6}\\ =\dfrac{7}{2}+\dfrac{3}{2}\\ =\dfrac{7+3}{2}=\dfrac{10}{2}=5\)

\(c,\dfrac{26}{25}-\dfrac{3}{5}-\dfrac{2}{5}\\ =\dfrac{26}{25}-\dfrac{3\times5}{5\times5}-\dfrac{2\times5}{5\times5}\\ =\dfrac{26-15-10}{25}\\ =\dfrac{1}{25}\)

Bài 1:
\(\dfrac{17}{6}-\dfrac{3}{7}-\dfrac{5}{6}=\left(\dfrac{17}{6}-\dfrac{5}{6}\right)-\dfrac{3}{7}=2-\dfrac{3}{7}=\dfrac{14}{7}-\dfrac{3}{7}=\dfrac{11}{7}\)
Bài 2:
a/\(\dfrac{6}{9}+\dfrac{3}{15}+\dfrac{7}{15}\)
\(=\dfrac{2}{3}+\left(\dfrac{3}{15}+\dfrac{7}{15}\right)\)
\(=\dfrac{2}{3}+\dfrac{2}{3}\)
\(=\dfrac{4}{3}\)
b/\(\dfrac{7}{2}+\dfrac{29}{12}-\dfrac{11}{12}\)
\(=\dfrac{7}{2}+\left(\dfrac{29}{12}-\dfrac{11}{12}\right)\)
\(=\dfrac{7}{2}+\dfrac{3}{2}\)
\(=5\)
c/\(\dfrac{26}{25}-\dfrac{3}{5}-\dfrac{2}{5}\)
\(=\dfrac{26}{25}-\left(\dfrac{3}{5}+\dfrac{2}{5}\right)\)
\(=\dfrac{26}{25}-1\)
\(=\dfrac{26}{25}-\dfrac{25}{25}\)
\(=\dfrac{1}{25}\)
#Đang Bận Thở

1+3+5+7+...+47+49+...+(-2)+(-4)+(-6)+...+(-48)+(-50)

=(-2+1)+(-4+3)+...+(-50+49)

=(-1)+(-1)+(-1)+...+(-1) (25 số -1)

= -25

Đáp án :C

là C.10

la c nha

\(B=\dfrac{4}{1\times3}+\dfrac{4}{3\times5}+\dfrac{4}{5\times7}+...+\dfrac{4}{47\times49}+\dfrac{4}{49\times51}\)
\(=2\times\left(\dfrac{2}{1\times3}+\dfrac{2}{3\times5}+\dfrac{2}{5\times7}+...+\dfrac{2}{47\times49}+\dfrac{2}{49\times51}\right)\)
\(=2\times\left(1-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+...+\dfrac{1}{47}-\dfrac{1}{49}+\dfrac{1}{49}-\dfrac{1}{51}\right)\)
\(=2\times\left(1-\dfrac{1}{51}\right)\)
\(=2\times\dfrac{50}{51}\)
\(=\dfrac{100}{51}\)