\(\frac{5}{7}\times\frac{1}{3}-\frac{5}{7}\times\frac{1}{4}-\frac{5}{7}\times\frac{1}{2}\)

\(=\frac{5}{7}\times\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{2}\right)\)

\(=\frac{5}{7}\times\left(\frac{4}{12}-\frac{3}{12}-\frac{6}{12}\right)\)

\(=\frac{5}{7}\times\left(\frac{4-3-6}{12}\right)\)

\(=\frac{5}{7}\times\frac{-5}{12}\)

\(=\frac{5\times\left(-5\right)}{7\times12}\)

\(=\frac{-25}{84}\)

\(\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{2}\)

= \(\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{2}\right).1\)

\(=\frac{5}{7}.\frac{-5}{12}\)

\(=-\frac{25}{84}\)

\(75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2\)

= \(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}:\frac{5}{12}-\frac{1}{4}\)

\(\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{5}{12}-\frac{1}{4}\)

\(\frac{3}{4}-\frac{3}{2}+\frac{5}{24}-\frac{1}{4}\)

\(\frac{18}{24}-\frac{36}{24}+\frac{5}{24}-\frac{6}{24}\)

-19/24

\(a,\frac{-7}{25}.\frac{11}{13}+\frac{-7}{25}.\frac{2}{13}-\frac{18}{25}\)

\(=\frac{-7}{25}.\left(\frac{11}{13}+\frac{2}{13}\right)-\frac{18}{25}=\frac{-7}{25}-\frac{18}{25}=-1\)

\(b,\frac{5}{7}.\frac{1}{3}-\frac{5}{7}.\frac{1}{4}-\frac{5}{7}.\frac{1}{12}=\frac{5}{7}.\left(\frac{1}{3}-\frac{1}{4}-\frac{1}{12}\right)=\frac{5}{7}.\left(\frac{4}{12}-\frac{3}{12}-\frac{1}{12}\right)\)

\(=\frac{5}{7}.0=0\)

c)\(5\frac{2}{5}.4\frac{2}{7}+5\frac{5}{7}.5\frac{2}{5}=\frac{27}{5}.\frac{30}{7}+\frac{40}{7}.\frac{27}{5}=\frac{27}{5}.\left(\frac{30}{7}+\frac{40}{7}\right)\)

\(=\frac{27}{5}.10=27.2=54\)

\(d,75\%-1\frac{1}{2}+0,5:\frac{5}{12}-\left(\frac{-1}{2}\right)^2=\frac{3}{4}-\frac{3}{2}+\frac{1}{2}.\frac{12}{5}-\frac{1}{4}\)

\(=\left(\frac{3}{4}-\frac{1}{4}\right)-\frac{3}{2}+\frac{6}{5}=\frac{1}{2}-\frac{3}{2}+\frac{6}{5}=-1+\frac{6}{5}=\frac{-5}{5}+\frac{6}{5}=\frac{1}{5}\)

cho mk hỏi, bn có thể lm thêm c d dc ko

=10/17+-5/13+7/17+-8/13+-11/25

=1+-1+-11/25

=11/25

b , 

= 1+-2+3+-4+5+-6+......2011+-2012

=1+1+1+1+1.........+-2012

=1.2011+-2012

=2011+-2012

=-1

2.

2/3-x = 5/4

=>x=2/3-5/4

=>x=-7/12

b,

[124-(20-4x)]:30+7=11

=>124-(20-4x)] :30 =11-7

=>[124-(20-4x)]:30=4

=>124-(20-4x)=4x30

=>124-(20-4x)=120

=>20-4x=120-124

=>20-4x=4

=>4x=20-4

=>4x=16

=>x=16:4

=>x=4

bài 1 

a, ghép cặp phân số 10/17 + 7/17 và 5/13 + -8/13 

b, 1-2+3-4+5-6+.....+2011-2012

= ( 1-2) + ( 3-4) + ( 5-6) +....+(2011-2012)

= (-1) + (-1) + (-1) + ....+ (-1)

< từ 1 đến 2012 có 2012 số số hạng, suy ra có 1006 cặp mà mỗi cặp có giá trị = (-1) Suy ra tổng trên = (-1) * 1006=-1006

Bài 2:

a,2/3 - x =5/4

          x=2/3 - 5/4

           x= -7/12

Nhanh lên nha mình cần gấp lắm

Tách tổng A thành 4 nhóm

A = ( 1 + \(\frac{1}{2}+\frac{1}{3}+...+\frac{1}{49}+\frac{1}{50}\)) + ( \(\left(\frac{1}{51}+\frac{1}{52}+\frac{1}{53}+...+\frac{1}{99}+\frac{1}{100}\right)+\left(\frac{1}{101}+\frac{1}{102}+\frac{1}{103}+...+\frac{1}{149}+\frac{1}{150}\right)+\left(\frac{1}{151}+\frac{1}{152}+\frac{1}{153}+...+\frac{1}{199}+\frac{1}{200}\right)\)

A > \(\frac{1}{50}.50+\frac{1}{100}.50+\frac{1}{150}.50+\frac{1}{200}.50\)= \(\left(\frac{1}{50}+\frac{1}{100}+\frac{1}{150}+\frac{1}{200}\right).50=\frac{1}{24}.50=\frac{25}{12}\)

\(\Rightarrow\) A > \(\frac{25}{12}\)

a) \(\frac{10}{17}-\frac{5}{13}+\frac{7}{17}+\frac{-8}{13}-\frac{11}{25}\)

\(=\frac{10}{17}+\frac{-5}{13}+\frac{7}{17}+\frac{-8}{13}+\frac{-11}{25}\)

\(=\left(\frac{10}{17}+\frac{7}{17}\right)+\left(\frac{-5}{13}+\frac{-8}{13}\right)+\frac{-11}{25}\)

\(=1+\left(-1\right)+\frac{-11}{25}\)

\(=0+\frac{-11}{25}\)

\(=\frac{-11}{25}\)

a) \(\frac{10}{17}-\frac{5}{13}+\frac{7}{17}+\frac{-8}{13}-\frac{11}{25}\)

\(=\frac{10}{17}+\frac{-5}{13}+\frac{7}{17}+\frac{-8}{13}+\frac{-11}{15}\)

\(=\left(\frac{10}{17}+\frac{7}{17}\right)+\left(\frac{-5}{13}+\frac{-8}{13}\right)+\frac{-11}{15}\)

\(=1+\left(-1\right)+\frac{-11}{15}\)

\(=0+\frac{-11}{15}\)

\(=\frac{-11}{15}\)

b) 1 - 2 + 3 - 4 + ...... + 2011 - 2012 ( có 2012 số )

= ( 1 - 2 ) + ( 3 - 4 ) + ....... + ( 2011 - 2012 ) ( có 1006 nhóm )

= ( - 1 ) + ( - 1 ) + ........ + ( - 1 ) ( có 1006 số )

= ( - 1 ) . 1006

= - 1006