Đặt A=\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+................+\frac{1}{2048}+\frac{1}{4096}\)

2A=\(1+\frac{1}{2}+\frac{1}{4}+....................+\frac{1}{1024}+\frac{1}{2048}\)

2A-A=\(\left(1+\frac{1}{2}+\frac{1}{4}+................+\frac{1}{1024}+\frac{1}{2048}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...............+\frac{1}{2048}+\frac{1}{4096}\right)\)

A=\(1-\frac{1}{4096}\)

A=\(\frac{4095}{4096}\)

4095/4096 đó lam lợn hả

các bạn sai rồi bằng 2047/2048 đó chắc chắn 100% luôn mk thi rồi.

Đúng thì nhớ k nha các bạn hihi ^-^

Từ biểu thức trên ta được

A=1/2+1/2^2+1/2^3+....+1/2^11+1/2^12

2A-A=2(1/2+1/2^2+1/2^3+....+1/2^11+1/2^12)-(1/2+1/2^2+1/2^3+....+1/2^11+1/2^12)

A=1+1/2^2+1/2^3+....+1/2^11-1/2-1/2^2-...-1/2^12

A=1/2-1/2^12

Ủng hộ cho mình nha bạn

\(A=\)\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{1024}+\frac{1}{2048}+\frac{1}{4096}\)

\(A=\)\(\frac{1}{2}+\frac{1}{2^2}+\frac{1}{2^3}+...+\frac{1}{2^{12}}\)

\(2A=\)\(2\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{12}}\right)\)

\(2A=\)\(1+\frac{1}{2}+...+\frac{1}{2^{11}}\)

\(2A-A=\)\(\left(1+\frac{1}{2}+...+\frac{1}{2^{11}}\right)-\left(\frac{1}{2}+\frac{1}{2^2}+...+\frac{1}{2^{12}}\right)\)

\(A=1-\frac{1}{2^{12}}\)

2

4

8

16

32

64

128

256

512

1024

2048

4096

8192

1+1=2

2+2=4

4+4=8

8+8=16

16+16=32

64+64=128

128+128=256

512+512=1024

2048+2048=4096

xong

1+1=2

2+2=4

4+4=8

8+8=16

16+16=32

32+32=64

64+64=128

128+128=256

256+256=512

512+512=1024

1024+1024=2048

2048+2048=4096

4096+4096=8192

Đặt 

\(S=1+2+4+...+2048+4096\)

\(S=1+2^1+2^2+...+2^{11}+2^{12}\)

\(2S=2+2^2+2^3+...+2^{12}+2^{13}\)

\(2S-S=\left(2+2^2+2^3+...+2^{13}\right)-\left(1+2+2^2+..+2^{12}\right)\)

\(S=2^{13}-1=8192-1=8191\)

Gọi A=1+2+4+8+16+...+1024+2048+4096

2A=2+4+8+16+32+...+2048+4096+8192

2A-A=(2+4+8+16+32+...+2048+4096+8192)-(1+2+4+8+16+...+1024+2048+4096)

A=8192-1

A=8191

                Đặt A = 1 + 2 + 4 + 8 + 16 +...+ 1024 + 2048 + 4096

                A = 1 + 2 + 2² + 2³ + 2⁴ +.... + 2¹⁰ + 2¹¹ + 2¹²

                     2A = 2 + 2² + 2³ + 2⁴ + 2⁵ + ..... + 2¹¹ + 2¹² + 2¹³

               2A - A = (2 + 2² + 2³ + 2⁴ + .... + 2¹¹ + 2¹² + 2¹³) - (1 + 2 + 2² + 2³ + 2⁴ +.....+ 2¹⁰ + 2¹¹ + 2¹²)

              => A = 2¹³ - 1

              => A = 8192 - 1 = 8191

           Ủng hộ mk nha !!! ^_^

Đặt \(A=1+2+4+.........+4096\)

\(2A=2+4+8+......+8192\)

\(\Rightarrow2A-A=8192-1\)

\(\Rightarrow A=8191\)

Đặt  \(S=1+2+4+...+1024+2048+4096\)

       \(S=1+2^1+2^2+2^3+....+2^{10}+2^{11}+2^{12}\)

    \(2S=2+2^2+2^3+....+2^{11}+2^{12}+2^{13}\)

\(2S-S=\left(2+2^2+2^3+....+2^{12}+2^{13}\right)-\left(1+2+2^2+....+2^{11}+2^{12}\right)\)

     \(S=2^{13}-1=8192-1=8191\)

            A=1+2+4+8+16+.....+1024+2048+4096

          2A= 2+4+8+16+32+....+2048+4096+8192

  2A-A=A=2+4+8+16+32+....+4096+8192-(1+2+4+8+16+...+1024+2048+4096)

           A=8192-1

            A=8191 k nha 

gọi biểu thức là A

A=1/2+1/4+1/8+...+1/2048=1/2+1/2^2+1/2^3+...+1/2^10

=>2A=1+1/2+1/2^2+...+1/2^9

=>A=2A-A(bạn đặt cột dọc ra rồi sẽ thấy:1/2-1/2=0;1/2^2-1/2^2=0;...)Ta được kết quả bằng 1+1/2^10

Đặt A =1/2 + 1/4 + 1/8 + ...+ 1/1024 + 1/2048

A= 1/2 + 1/2^2 + 1/2^3+...+ 1/2^10 + 1/2^11

2A= 1 +1/2 + 1/2^2 +...+ 1/2^9 + 1/2^10

2A-A= (1 +1/2 + 1/2^2 +...+ 1/2^9 + 1/2^10) - (1/2 + 1/2^2 + 1/2^3+...+ 1/2^10 + 1/2^11)

A= 1+1/2 + 1/2^2 +...+ 1/2^9 + 1/2^10 - 1/2 - 1/2^2 - 1/2^3 - ...- 1/2^10 - 1/2^11

A= 1- 1/2^11

A= 2047/ 2048

Đặt \(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+\frac{1}{64}+...+\frac{1}{1024}+\frac{1}{2048}\)
\(2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}+...+\frac{1}{512}+\frac{1}{1024}\)
\(2A-A=1-\frac{1}{2048}\)
\(A=\frac{2047}{2048}\)

Đặt tổng trên là A . Ta có:

\(A=\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{1024}\)

\(2A=1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{1024}\)

\(2A-A=\left(1+\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{1024}\right)-\left(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+...+\frac{1}{1024}\right)\)

\(A=1-\frac{1}{1024}\)

\(A=\frac{1023}{1024}\)

Đặt A = 2 + 4 + 8 +  ... + 2048

         = 2 + 2² + 2³ + ... + 2¹¹

=> 2A = 2² + 2³ + 2⁴ + ... + 2¹²

Lấy 2A trừ A theo vế ta có

2A - A = (2² + 2³ + 2⁴ + ... + 2¹²) - (2 + 2² + 2³ + ... + 2¹¹) 

=>   A = 2¹² - 2

Đặt \(A=2+4+8+16+...+1024+2048\)

\(\Rightarrow2A=4+8+16+32+...+2048+4096\)

\(\Rightarrow2A-A=4096-2\)

\(\Rightarrow A=4094\)

các bạn ơi có thể làm theo cách lớp 5 được ko 

vì mình năm nay mới lên lớp 6