\(\dfrac{1}{2}=\dfrac{6}{12};\dfrac{2}{3}=\dfrac{8}{12};\dfrac{7}{12}=\dfrac{7}{12}\)

Chắc là quy đồng nhỉ :)

\(\dfrac{1\times6}{2\times6}=\dfrac{6}{12};\dfrac{2\times4}{3\times4}=\dfrac{8}{12};\dfrac{7}{12}\)

6/12

8/12

7/12 

Đề là gì v cậu?

\(a\left(\sqrt{2}-1\right)+b\left(\sqrt{2}+1\right)=12\\ \Leftrightarrow a\sqrt{2}-a+b\sqrt{2}+b=12\)

Đề như vậy á cậu?

a) \(\dfrac{5}{4}+\dfrac{3}{5}=\dfrac{25}{20}+\dfrac{12}{20}=\dfrac{37}{20}\)

b) \(\dfrac{7}{8}+\dfrac{9}{24}=\dfrac{21}{24}+\dfrac{9}{24}=\dfrac{30}{24}=\dfrac{15}{12}\)

c) \(\dfrac{2}{36}+\dfrac{1}{6}+\dfrac{5}{12}=\dfrac{2}{36}+\dfrac{6}{36}+\dfrac{15}{36}=\dfrac{23}{36}\)

a) \(\dfrac{5}{4}+\dfrac{3}{5}=\dfrac{25}{20}+\dfrac{12}{20}=\dfrac{37}{20}\)

b) \(\dfrac{7}{8}+\dfrac{9}{24}=\dfrac{21}{24}+\dfrac{9}{24}=\dfrac{30}{24}=\dfrac{5}{4}\)

c) \(\dfrac{2}{36}+\dfrac{1}{6}+\dfrac{5}{12}=\dfrac{2}{36}+\dfrac{6}{36}+\dfrac{15}{36}=\dfrac{23}{36}\)

\(\dfrac{1}{2}< \dfrac{2}{3}\\ \dfrac{2}{3}=\dfrac{8}{12}\)

ta có :

`1/2=(1xx3)/(2xx3)=3/6 ; 2/3=(2xx2)/(3xx2)=4/6`

`-> 1/2 < 2/3`

`---`

ta có : 

`2/3=(2xx4)/(3xx4)=8/12;8/12`

`->2/3=8/12`

a)

`1/2=(1xx3)/(2xx3)=3/6`

`2/3=(2xx2)/(3xx2)=4/6`

vì 3<4 nên `3/6<4/6`

`=> 1/2<2/3`

b)

`8/12=(8:4)/(12:4)=2/3`

vì 2=2 nên `2/3=2/3`

`=> 2/3=8/12`

a) 10/7 - 3/8 

= 59/56

b) 9/10- 7/12

= 19/60

giúp mình với

a 4/7 x 5/2 -3/8 = 10/7 - 3/8 = 59/56

b 9/10 - 7/12 =19/60

Đề là j

để là quy đồng mẫu số

à nhầm đề

\(a,=7xy\left(x^2-2xy+y^2\right)=7xy\left(x-y\right)^2\\ b,=3x\left(x-y\right)-5\left(x-y\right)=\left(3x-5\right)\left(x-y\right)\\ c,=x^2+3x+4x+12=\left(x+3\right)\left(x+4\right)\)

A

A

A