Tính tích A=(\(\frac{7}{9}\)+1)(\(\frac{7}{20}\)+1)(\(\frac{7}{33}\)+1)...(\(\frac{7}{2900}\)+1)
Những câu hỏi liên quan
tính tích P=[1+\(\frac{7}{9}\)].[1+\(\frac{7}{20}\)].[1+\(\frac{7}{33}\)]...[1+\(\frac{7}{2900}\)]
tính tổng\(A=\left(1+\frac{7}{9}\right).\left(1+\frac{7}{20}\right).\left(1+\frac{7}{33}\right)....\left(1+\frac{7}{2900}\right)\)
Tính
\(A=\left(1+\frac{7}{9}\right)\left(1+\frac{7}{20}\right)\left(1+\frac{7}{33}\right)....\left(1+\frac{7}{2900}\right)\)
Cô giải như sau Minh nhé :)
\(A=\left(1+\frac{7}{9}\right)\left(1+\frac{7}{20}\right)\left(1+\frac{7}{33}\right)...\left(1+\frac{7}{2900}\right)=\frac{16}{9}.\frac{27}{20}.\frac{40}{33}...\frac{2907}{2900}\)
\(=\frac{8.2}{9.1}.\frac{9.3}{10.2}.\frac{10.4}{11.3}....\frac{57.51}{58.50}=\frac{\left(8.9.10....57\right)\left(2.3.4...51\right)}{\left(9.10.11...58\right)\left(2.3.4....50\right)}=\frac{8.51}{58}=\frac{204}{29}\)
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( 1 + 7/9 ) x ( 1 + 7/20 ) x ( 1 + 7/33 ) x...x ( 1 + 7/2900)
= (8x2)/(9x1) x (9x3)/(10x2) x (10x4)/(11x3) x...x (57x51)(58x50)
=(8x2x9x3x10x4x...x57x51) / (9x1x10x2x11x3x...x58x50) Sau khi giản ước ta được :
= (8x51) / (1x58) = 204/29
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\(A=\left(1+\frac{7}{9}\right)\left(1+\frac{7}{20}\right)\left(1+\frac{7}{33}\right)..........\left(1+\frac{7}{2900}\right)\)
\(A=\frac{16}{9}.\frac{27}{20}.\frac{40}{33}.......\frac{2907}{2900}\)
\(A=\frac{2.8}{1.9}.\frac{3.9}{2.10}.\frac{4.10}{3.11}......\frac{51.57}{50.58}\)
\(A=\frac{2.3.4.....51}{1.2.3...50}.\frac{8.9.10....57}{9.10.11...58}\)
\(A=51.\frac{8}{58}=\frac{204}{29}\)
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Bạn Nguyễn Tuấn Minh làm đúng rùi đó !!! Chuẩn ý kiến mk...^.^
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tính \(B=\left(1+\frac{7}{9}\right)\left(1+\frac{7}{20}\right)\left(1+\frac{7}{33}\right)...\left(1+\frac{7}{2900}\right)\)
Nhanh giùm mình nha, gấp lắm rùi
1/ Tìm giá trị nhỏ nhất của biểu thức: A= |x-20| + |y+5| - 2015
2/ Tính: \(B=\left(1+\frac{7}{9}\right)\left(1+\frac{7}{20}\right)\left(1+\frac{7}{33}\right)....\left(1+\frac{7}{2900}\right)\)
Chứng minh rằng:
\(\left(1+\frac{7}{9}\right).\left(1+\frac{7}{20}\right).\left(1+\frac{7}{33}\right)....\left(1+\frac{7}{2900}\right)=7\frac{1}{29}\)
CMR : \(\left(1+\frac{7}{7}\right)+\left(1+\frac{7}{20}\right)+\left(1+\frac{7}{33}\right)+...+\left(1+\frac{7}{2900}\right)=7\frac{1}{29}\)
Tính : A = \(\left(1+\frac{7}{9}\right)\)\(\left(1+\frac{7}{20}\right)\)\(\left(1+\frac{7}{33}\right)\).............\(\left(1+\frac{7}{2900}\right)\)