Tim x thuoc Z
a , (-10)+(-9)+(-8)+........+x=23
b, (-1)+2+(-3)+4+(-5)+6+..........+x=60
Tim x thuoc Z biet:
a,(10 - x)^2 / 3+3= -9
b,|x-6| *7-(-2)^2= -8+39
a) (10-x)2:3+3=-9
(10-x)2:3=-9-3
(10-x)2:3=-11
(10-x)2=-11.3
(10-x)2=-33
Vô lí vì -33 ko chuyển đc mũ 2
Vậy x e 0
b) |x-6|.7-4=31
|x-6|=(31+4):7
|x-6|=5
\(\Rightarrow\orbr{\begin{cases}x-6=5\Rightarrow5+6=11\\x-6=-5\Rightarrow x=-5+6=1\end{cases}}\)
Vậy.....................................................
a) \(\frac{\left(10-x\right)^2}{3}+3=-9\)
\(\Leftrightarrow\frac{\left(10-x\right)^2}{3}=-12\)
\(\Leftrightarrow\left(10-x\right)^2=-36\)( vô nghiệm vì (10-x)2 \(\ge\)0 với mọi x thuộc Z)
b) |x-6|.7-(-2)2=-8+39
<=> |x-6|.7-4=31
<=> |x-6|.7=35
<=> |x-6|=5
\(\Leftrightarrow\orbr{\begin{cases}x-6=5\\x-6=-5\end{cases}\Leftrightarrow\orbr{\begin{cases}x=11\\x=1\end{cases}}}\)
tim x thuoc z
1)26-|x+9|=-13
2)|x+7|-13=25
tim x biet
1)123-3.(x+4)=23
2)720:[41-(2x-5)]=23.5
Tìm x thuoc z:
1) \(26-\left|x+9\right|=-13\)
\(\Leftrightarrow\left|x+9\right|=26-\left(-13\right)\)
\(\Leftrightarrow\left|x+9\right|=39\)
\(\Leftrightarrow\left[{}\begin{matrix}x+9=39\\x+9=-39\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=39-9=30\\x=-39-9=-48\end{matrix}\right.\)
Vậy: \(x\in\left\{30;-48\right\}\)
2) \(\left|x+7\right|-13=25\)
\(\Leftrightarrow\left|x+7\right|=25+13=38\)
\(\Leftrightarrow x+7\in\left\{38;-38\right\}\)
\(\Leftrightarrow x\in\left\{31;-45\right\}\)
Vậy:.................
tim x biet
\(1)123-3.\left(x+4\right)=23\)
\(\Leftrightarrow3\left(x+4\right)=123-23\)
\(\Leftrightarrow3\left(x+4\right)=100\)
\(\Leftrightarrow x+4=\frac{100}{3}\)
\(\Leftrightarrow x=\frac{100}{3}-4=\frac{100-12}{3}=\frac{88}{3}\)
Vậy:................
2) Tương tự
Bai 1:
a) Cho A = 963 + 351 + x voi x thuoc N . Tim dieu kien cua x de A chia het cho 9 , de A khong chia hat cho 9
b) Cho B = 10 + 25 + x + 45 voi x thuoc N . Tim dieu kien cua x De B chia het cho 5 , B khong chia het cho 5
Bai 2 : Tim x thuoc N biet :
a) 1 + 2 + 3 + ..... + n = 325
b) 1 + 3 + 5 +... + ( 2n+1) = 144
c) 2 + 4 + 6 + ... + 2n = 756
1 )Tim x, y thuoc Z
x + y = x.y
2) Tim x thuoc Z
(x + 1)+(x+3)+(x+5)+...+(x+99)=0(x-3)+(x-2)+(x-1)+...+10+11=11-12(x-5)+7(3-x)=530(x+2)-6(x-5)-24x=100x + y = x.y
=> xy - x - y = 0
=> (xy - x) - y + 1 = 1
=> x(y - 1) - (y - 1) = 1
=> (x - 1)(y - 1) = 1
=> x - 1 = y - 1 = 1 hoặc x - 1 = y - 1 = -1
=> x = y = 2 hoặc x = y = 0
Tìm 3 số x,y,z biết rằng x/2 = y/4; y/8 = z/5 và x+y-z= 9
A. x=3, y=4, z=-2
B. x=6, y=8, z=5
C. x=-6, y=-8, z=-23
D. x=-6, y=8, z=5
Bai 1: Tinh nhanh:
a, -69+53+46+(-14)+78 b, 13-12+11+10-9+8-7-6+5-4+3+2-1
Bai 2: a,Tim gia tri nho nhat cua bieu thuc: A= |x+19|+|y-5|+1890
b, Tim gia tri lon nhat cua bieu thuc: B= -|x-7|-|y+13|+1945
Bai 3: Tim x,y thuoc Z biet: a, xy-3x= -19 b, 3x+4y-xy= 16
Bai 4: Tim x thuoc Z biet: a, x.(x+3)= 0 b, (x-2) (5-x)= 0 c, (x+1) (x2+1)= 0
d, -12 (x-5)+7 (3-x)= 5 e, 30 (x+2)-6 (x-5)-24x= 100 f, (x+1)+(x+3)+(x+5)+. . .+(x+99)= 0
Minh xin cam on truoc ! THANK YOU
khó quá mình bó tay
CHO E=\(\left(\frac{x^3}{x^3-4x}+\frac{6}{6-3x}+\frac{1}{2+x}\right):\left(x+2+\frac{10-x^2}{x-2}\right)\)
a) Rut gon E
b) Tim x thuoc Z sao cho E thuoc Z
bai 1:tim x
a) (x+1/5)2+17/25=26/25
b)-1va 5/27-(3x-7/9)3=-24/27
bai 2:cho A=n+2/n-5 (n thuoc Z ;n khac 5).Tim x de A thuoc Z
1a. x=-0,8
b)-1va 5/27-(3x-7/9)3=-24/27 mik ko hỉu đề
2.n= 6
cho A = 1/15 nhan 225/(8+2) + 3/14 nhan 196/(3x+6) (x thuoc Z; x khac -2 )
a) Rut gon A
b) Tim x thuoc Z de A thuoc Z
c) trong cac gia tri nguyen A tim gia tri lon nhat va gia tri nho nhat