phan tich da thuc thanh nhân tử : giup minh giai bài toan này voi
\(x^3-6x^2+11x+6\)
Những câu hỏi liên quan
phan tich da thuc thanh nhan tu (xy+1)^2 -(x-y)^2 ai giup minh voi
\(\left(xy+1\right)^2-\left(x-y\right)^2=\left(xy+1+x-y\right)\left(xy+1-x+y\right)\)
\(=x^2y^2+xy-x^2y+xy^2+xy+1-x+y+x^2y+x-x^2+xy-xy^2-y+xy-y^2\)
\(=x^2y^2+2xy-x^2-y^2+1\)
cac ban oi giup minh bai toan phan tich da thuc thanh nhan tu x^7+x^5+1
\(x^7+x^5+1\)
\(\left(x^2+x+1\right)\left(x^5-x^4+x^3-x+1\right)\)
k cho mình nha
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\(\text{OoO cô bé tinh nghịch OoO làm đúng rồi nhé}\)
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Phan tich da thuc thanh nhan tu
3x^2-11x+6
x^2-6x+5
x^4+x^2+1
x^4-4x^2+3
6x^2+7xy+2y^2
(*)\(3x^2-11x+6=3x^2-2x-9x+6=x\left(3x-2\right)-3\left(3x-2\right)=\left(x-3\right)\left(3x-2\right)\)
(*)\(x^2-6x+5=x^2-x-5x+5=x\left(x-1\right)-5\left(x-1\right)=\left(x-5\right)\left(x-1\right)\)
(*)\(x^4+x^2+1=x^4+2x^2+1-x^2=\left(x^2+1\right)^2-x^2=\left(x^2+1+x\right)\left(x^2+1-x\right)\)
(*)\(x^4-4x^2+3=x^4-x^2-3x^2+3=x^2\left(x^2-1\right)-3\left(x^2-1\right)=\left(x+1\right)\left(x-1\right)\left(x^2-3\right)\)
(*)\(6x^2+7xy+2y^2=6x^2+4xy+3xy+2y^2=2x\left(3x+2y\right)+y\left(3x+2y\right)=\left(2x+y\right)\left(3x+2y\right)\)
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a, \(3x^2-11x+6=3x^2-2x-9x+6=x\left(3x-2\right)-3\left(3x-2\right)=\left(3x-2\right)\left(x-3\right)\)
b, \(x^2-6x+5=x^2-x-5x+5=x\left(x-1\right)-5\left(x-1\right)=\left(x-1\right)\left(x-5\right)\)
c, \(x^4+x^2+1=x^4+2x^2+1-x^2=\left(x^2+1\right)^2-x^2=\left(x^2+x+1\right)\left(x^2-x+1\right)\)
d, \(x^4-4x^2+3=x^4-4x^2+4-1=\left(x^2-2\right)^2-1=\left(x^2-1\right)\left(x^2-3\right)=\left(x+1\right)\left(x-1\right)\left(x^2-3\right)\)
e, \(6x^2+7xy+2y^2=6x^2+3xy+4xy+2y^2=3x\left(2x+y\right)+2y\left(2x+y\right)=\left(2x+y\right)\left(3x+2y\right)\)
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phan tich da thuc thanh nhan tu (x^2+xy)^2-(y^2+xy)^2
Ai giup minh voi a
Phan tich da thuc sau thanh nhan tu :
\(6x^2-11x+3\)
\(=6x^2-2x-\left(9x-3\right)\)
\(=2x\left(3x-1\right)-3\left(3x-1\right)\)
\(=\left(2x-3\right)\left(3x-1\right)\)
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6x2 - 11x + 3
= 2x(3x - 1) - 3(3x - 1)
= (3x - 1)(2x - 3)
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= 6x^2 - 9x - 2x + 3
= 3x(2x-3) -(2x-3)
= (2x-3).(3x-1)
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phan tich da thuc sau thanh nhan tu
x^3+3x^2+4x+2
6x^4-x^3-7x^2+x+1
giup minh nhe cam on nhieu
\(a.x^3+3x^2+4x+2\)
\(=x^3+x^2+2x^2+2x+2\)
\(=x^2\left(x+1\right)+2x\left(x+1\right)+2\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2+2x+2\right)\)
\(b.6x^4-x^3-7x^2+x+1\)
\(=6x^4-6x^3+5x^3-5x^2-2x^2+2x-x+1\)
\(=6x^3\left(x-1\right)+5x^2\left(x-1\right)-2x\left(x-1\right)-\left(x-1\right)\)
\(=\left(x-1\right)\left(6x^3+5x^2-2x-1\right)\)
\(=\left(x-1\right)\left(6x^3+6x^2-x^2-x-x-1\right)\)
\(=\left(x-1\right)\left[6x^2\left(x+1\right)-x\left(x+1\right)-\left(x+1\right)\right]\)
\(=\left(x-1\right)\left(x+1\right)\left(6x^2-x-1\right)\)
\(=\left(x-1\right)\left(x+1\right)\left(6x^2-3x+2x-1\right)\)
\(=\left(x-1\right)\left(x+1\right)\left[3x\left(2x-1\right)+\left(2x-1\right)\right]\)
\(=\left(x-1\right)\left(x+1\right)\left(2x-1\right)\left(3x+1\right)\)
k giùm cái cho đỡ buồn!
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phan tich da thuc thanh nhan tu : a) 3x^2 - 22xy + 4x + 8y + 7x^2 + 1 ; b) 12x^2 + 5x - 12y^2 + 12y - 10xy - 3 ; c)x^4 + 6x^3 + 11x^2 + 6x + 1
Phan tich da thuc thanh nhan tu
a) x^2 - 7xy + 10y^2
b) 4x^2 + 12x - 27
c) 81x^4 + 4
d) 3a^2 - 6ab + 3b^2 - 12c^2
e) x^3 + 6x^2 +11x +6
PHAN TICH DA THUC THANH NHAN TU
\(\left(x^2+6x\right).\left(x^2+14x+40\right)+128\)\
giup minh di!
\(\left(x^2+6x\right)\left(x^2+14x+40\right)+128\)
\(=\left(x^2+6x\right)\left(x^2+14x+40\right)\)
\(=x^4+20x^3+124x^2+240x\)
\(=x^4+20x^3+124x^2+240x+128\)
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\(\left(x^2+6x\right)\left(x^2+14x+40\right)+128\)
\(=x^4+14x^3+40x^2+6x^3+84x^2+240x+128\)
\(=x^4+20x^3+124x^2+240x+128\)
mk chỉ biết đến đây thôi
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