\(1\frac{1}{5}\)X \(1\frac{1}{6}\) X \(1\frac{1}{7}\) X \(...\)X \(1\frac{1}{2014}\) = x

x = \(\frac{6}{5}\) X \(\frac{7}{6}\) X \(\frac{8}{7}\) X \(...\)X \(\frac{2015}{2014}\)

x = \(\frac{6\cdot7\cdot8\cdot...\cdot2015}{5\cdot6\cdot7\cdot...2014}\)

x = \(\frac{2015}{5}\)

x = 403

6/5 × 7/6 × 8/7 × ... × 2015/2014 = x

2015/5 = x

x = 403

Vậy x = 403

Ủng hộ mk nha ♡_♥☆_★^_-

\(\Rightarrow x=\frac{6}{5}\times\frac{7}{6}\times\frac{8}{7}\times.......\times\frac{2015}{2014}\)

\(\Rightarrow x=\frac{6\times7\times8\times......\times2015}{5\times6\times7\times......\times2014}\)

\(\Rightarrow x=\frac{2015}{5}=403\)

4

nhớ tick nha

2014/2014

chỗ \(\frac{2014}{5}sai\Rightarrow\frac{2015}{5}=403\)

bạn cứ nhân ra là xong

\(X=\frac{6}{5}x\frac{7}{6}x\frac{8}{7}x....x\frac{2014}{2013}=\frac{2014}{5}\)

tìm số tự nhiên mà

\(1\frac{1}{5}\cdot1\frac{1}{6}\cdot...\cdot1\frac{1}{2014}=x\)

\(\frac{6}{5}\cdot\frac{7}{6}\cdot...\cdot\frac{2015}{2014}=x\)

\(\frac{6\cdot7\cdot...\cdot2015}{5\cdot6\cdot...\cdot2014}=x\)

\(\frac{2015}{5}=x\)

\(2015:5=x\)

 \(403=x\)

Vậy  : \(x=403\)

\(=\frac{6}{5}.\frac{7}{6}.\frac{8}{7}............\frac{2015}{2014}=\frac{2015}{5}=403\)

=> \(\frac{6}{5}.\frac{7}{6}.\frac{8}{7}...\frac{2014}{2013}.\frac{2015}{2014}=x\)

=> \(\frac{6.7.8.9...2014.2015}{5.6.7.8...2013.2014}=x\)

=> \(x=\frac{2015}{5}=403\)

=>\(\frac{6}{5}\cdot\frac{7}{6}\cdot\frac{8}{7}\cdot...\cdot\frac{2015}{2014}=x\)

=>\(\frac{6\cdot7\cdot8\cdot...\cdot2015}{5\cdot6\cdot7\cdot...\cdot2014}=x\)

=>\(\frac{2015}{5}=x\)

=>x=403