a: =>-12x=60-12=48

=>x=-4

b: =>-5x=24+6-5=25

=>x=-5

Chi tiết nha

Lời giải:
a.

$(-12).x=(-15)(-4)-12$

$(-12)x=60-12=48$

$x=48:(-12)=-4$

b.

$(-5)x+5=(-3)(-8)+6$

$(-5)x+5=24+6=30$

$(-5)x=30-5=25$

$x=25:(-5)=-5$

a,-4/7=x/21
-12/21 = x/21
x= -12 

b,(x-3)/15=1/-5
x - 3 = -1/5 * 15
x - 3 = -3
x = 0

c,.(3x+8)/-12=-5/30
=> 3x + 8 = 2
=> 3x=-6
=>x=-2

Giải:

a) \(\dfrac{-1}{5}\le\dfrac{x}{8}\le\dfrac{1}{4}\) 

\(\Rightarrow\dfrac{-8}{40}\le\dfrac{5x}{40}\le\dfrac{10}{40}\) 

\(\Rightarrow5x\in\left\{0;\pm5;10\right\}\) 

\(\Rightarrow x\in\left\{0;\pm1;2\right\}\) 

b) \(\dfrac{4}{x-6}=\dfrac{y}{24}=\dfrac{-12}{18}\) 

\(\Rightarrow\dfrac{4}{x-6}=\dfrac{-12}{18}\) 

\(\Rightarrow-12.\left(x-6\right)=4.18\) 

\(\Rightarrow-12x+72=72\) 

\(\Rightarrow-12x=72-72\) 

\(\Rightarrow-12x=0\) 

\(\Rightarrow x=0:-12\) 

\(\Rightarrow x=0\) 

\(\Rightarrow\dfrac{y}{24}=\dfrac{-12}{18}\) 

\(\Rightarrow y=\dfrac{-12.24}{18}=-16\) 

c) \(\dfrac{x+46}{20}=x.\dfrac{2}{5}\) 

\(\dfrac{x+46}{20}=\dfrac{2x}{5}\) 

\(\Rightarrow5.\left(x+46\right)=2x.20\) 

\(\Rightarrow5x+230=40x\) 

\(\Rightarrow5x-40x=-230\) 

\(\Rightarrow-35x=-230\) 

\(\Rightarrow x=-230:-35\) 

\(\Rightarrow x=\dfrac{46}{7}\) 

Chúc bạn học tốt!

Bài 13: 

a: =>20-x=15-8+13=20

hay x=0

\(a,\left(2x-5\right)+17=6\\ \Rightarrow2x-5=-11\\ \Rightarrow2x=-6\\ \Rightarrow x=-3\\ b,10-2\left(4-3x\right)=-4\\ \Rightarrow2\left(4-3x\right)=14\\ \Rightarrow4-3x=7\\ \Rightarrow3x=-3\\ \Rightarrow x=-1\\ c,24:\left(3x-2\right)=-3\\ \Rightarrow3x-2=-8\\ \Rightarrow3x=-6\\ \Rightarrow x=-2\\ d,5-2x=-17+12\\ \Rightarrow5-2x=-5\\ \Rightarrow2x=10\\ \Rightarrow x=5\)

a: =>2x-5=-11

=>2x=-6

hay x=-3

b: =>2(4-3x)=14

=>4-3x=7

=>3x=-3

hay x=-1

c: =>3x-2=-8

=>3x=-6

hay x=-2

a) 2x-5+17=6

2x+12=6

2x=12-6

2x=6

x=6:2

x-3

b) 10-8+6x=-4

2+6x=-4

6x=-4-2

6x=-6

x=(-6):6

x=-1

c) 3x-2=24:(-3)

3x-2=-8

3x=-8+2

3x=-6

x=-6:3

x=-2

d) 5-2x=-5

-2x=-5-5

-2x=-10

x=-10:(-2)

x=5

a. \(-3x=36\)

\(x=\dfrac{36}{-3}=-12\)

Vậy....

b. \(-100:\left(x+5\right)=-5\)

\(x+5=-100:\left(-5\right)\)

\(x+5=20\)

\(x=20-5=15\)

Vậy....

a) (-3)x=36

nên x=-12

Vậy: x=-12

b) (-100):(x+5)=-5

\(\Leftrightarrow x+5=20\)

hay x=15

Vậy: x=15

\(a,2x-5+17=6\\ \Rightarrow2x=-6\\ \Rightarrow x=-3\\ b,\Leftrightarrow10-8+6x=-4\\ \Leftrightarrow6x=-6\Leftrightarrow x=-1\\ d,\Rightarrow-2x=-10\\ \Rightarrow x=5\)

câu c giống câu b nhó

❤                                              ✔

a) Tìm số nguyên x, biết:

Với \(x\in Z\), ta có:

9 - x = 8 - (2x + 16)

<=> 9 - x = 8 - 2x - 16 

<=> 9 - x = -2x - 8

<=> x  = -17 (TM)

Vậy x = -17

b) Với \(x\in Z\), ta có:

18 - 2x = 21 - (3x - 5)

<=> 18 - 2x = 21 - 3x + 5

<=> 18 - 2x = 26 - 3x

<=> x = 8 (TM)

Vậy x = 8

a) Ta có: 9-x=8-(2x+16)

\(\Leftrightarrow9-x=8-2x-16\)

\(\Leftrightarrow9-x=-2x-8\)

\(\Leftrightarrow9-x+2x+8=0\)

\(\Leftrightarrow x+17=0\)

hay x=-17

Vậy: x=-17

b) Ta có: 18-2x=21-(3x-5)

\(\Leftrightarrow18-2x=21-3x+5\)

\(\Leftrightarrow18-2x+3x-26=0\)

\(\Leftrightarrow x-8=0\)

hay x=8

Vậy: x=8

a,\(\dfrac{6}{2x+1}=\dfrac{2}{7}\)

⇒\(\dfrac{6}{2x+1}=\dfrac{6}{21}\)

⇒\(2x+1=21\)

\(2x=21-1\)

\(2x=20\)

⇒\(x=10\)