chứng minh:
1/2-2/3^2+3/3^3+...+99/3^99-100/3^100<3/10
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Chứng minh rằng :
100 - ( 1 + 1/2 + 1/3 + .....+ 1/100) = 1/2 + 2/3 + 3/4 + .......+ 99/100
Ta có :
\(100-\left(1+\frac{1}{2}+\frac{1}{3}+...+\frac{1}{100}\right)\)
\(=100-\left[1+\left(1-\frac{1}{2}\right)+\left(1-\frac{2}{3}\right)+...+\left(1-\frac{99}{100}\right)\right]\)
\(=100-\left[\left(1+1+1+...+1\right)-\left(\frac{1}{2}+\frac{2}{3}+...+\frac{99}{100}\right)\right]\)
\(=100-\left[100-\left(\frac{1}{2}+\frac{2}{3}+...+\frac{99}{100}\right)\right]\)
\(=100-100+\left(\frac{1}{2}+\frac{2}{3}+...+\frac{99}{100}\right)\)
\(=\frac{1}{2}+\frac{2}{3}+...+\frac{99}{100}\)
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ta có 100-(1+1/2+1/3+.....+1/100)
=(1+1+1......1)(99 số 1)-(1+1/2+1/3+......+1/100)
=(1-1)+(1-1/2)+(1-1/3)+.......+(1-1/100)
=1/2+2/3+3/4+.....+99/100
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Xem thêm câu trả lời
Chứng minh rằng
D= 1/3-2/32+3/33-4/34+..........+99/399-100/3100<3/16
E=1/52-2/53+3/54-4/55+.......+99/5100-100/5101<1/36
F=1/22+1/32+1/42+.......+1/502<1
Chứng minh rằng: 1/2!+2/3!+3/4!+......+99/100! <1
Thêm câu này nhé!
Chứng minh rằng: Mọi số nguyên dương thì 3 mũ n+2 - 2 mũ n+2 +3 mũ n -2 mũ n chia hết cho 10
Chứng minh rằng 1/3-3/2^2+3/3^3-4/3^4+...+99/3^99-100/3^100
1+1+1+1+2+2+2+2+3+3+3+3+...+99+99+99+99+100+100+100+100=?
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==========================ko bt
( ;-; )
Xem thêm câu trả lời
chumg minh rang 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
chứng minh: 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
Chứng minh rằng : 1/3-2/3^2+3/3^3-4/3^4+...+99/3^99-100/3^100<3/16
chung minh rang 1/3-2/3^2+3/3^3-4/3^4+....+99/3^99-100/3^100<3/16