Tìm x, biết: 0 , 5 x - 2 3 x = 7 12
Tìm x, biết:
a) (x - 7):5 = 0;
b) x : 3 - 13 = 47
c) (x : 7 - 7) (x: 12 - 12) = 0;
d) 135 + x : 2 = 150
e) 140 - 100 : x = 120;
g) 300 - x : 5 = 273.
a) x - 7 = 5. 0 => x - 7 = 0 =>x = 7.
b) x: 3 = 47 +13 => x: 3 = 60 => x = 60.3 => x = 180.
c) x : 7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144.
d) x : 2 = 150 - 135 => x: 2 = 15 => x = 15.2 => x = 30.
e) 100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5.
g) x : 5 = 300 - 273 => x : 5 = 27 =>x = 27.5 => x = 135
Tìm x, biết:
a) (x - 7):5 = 0; b) x : 3 - 13 = 47
c) (x : 7 - 7) (x: 12 - 12) = 0; d) 135 + x : 2 = 150
e) 140 - 100 : x = 120; g) 300 - x : 5 = 273
a) x - 7 = 5. 0 => x - 7 = 0 =>x = 7.
b) x: 3 = 47 +13 => x: 3 = 60 => x = 60.3 => x = 180.
c) x : 7 - 7 = 0 hoặc x : 12 - 12 = 0. Do đó x = 49 hoặc x = 144.
d) x : 2 = 150 - 135 => x: 2 = 15 => x = 15.2 => x = 30.
e) 100: x = 140 -120 => 100: x = 20 => x = 100:20 => x = 5.
g) x : 5 = 300 - 273 => x : 5 = 27 =>x = 27.5 => x = 135
Tìm x thuộc Z biết
a,-12.(x-5)+7.(3-x)=5
b,-15(x-2)+7.(3-x)=7
c,(x-3).(x-5)<0
d,(x-5).(x-7)>0
Tìm x,biết: a.-12(x-5)+7(3-x)=5
b.(x-2).(x+4)=0
c.(x-2).(x+15)=0
d.(7-x).(x+19)=0
tìm số nguyên, biết :
1/ x.(x+7) = 0
2/ (x+12).(x-3) = 0
3/ (-x+5).(3-x) = 0
1) \(x.\left(x+7\right)=0\)
\(x+7=0:x\)
\(x+7=0\)
\(x=0-7\)
\(x=-7\)
các ý sau bn làm tương tự nha!
chúc bn học giỏi!
\(x\left(x+7\right)=0\)
\(\Rightarrow\hept{\begin{cases}x=0\\x+7=0\end{cases}\Rightarrow\hept{\begin{cases}x=0\\x=-7\end{cases}}}\)
\(\left(x+12\right)\left(x-3\right)=0\)
\(\Rightarrow\hept{\begin{cases}x+12=0\\x-3=0\end{cases}\Rightarrow\hept{\begin{cases}x=-12\\x=3\end{cases}}}\)
\(\left(-x+5\right)\left(3-x\right)=0\)
\(\Rightarrow\hept{\begin{cases}-x+5=0\\3-x=0\end{cases}\Rightarrow\hept{\begin{cases}x=5\\x=3\end{cases}}}\)
1/ \(\Leftrightarrow\hept{\begin{cases}x=0\\x+7=0\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}x=0\\x=0-7\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}x=0\\x=-7\end{cases}}\)
Vậy x = {0;-7}
2/ \(\Leftrightarrow\hept{\begin{cases}x+12=0\\x-3=0\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}x=0-12\\x=0+3\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}x=-12\\x=3\end{cases}}\)
Vậy x = {-12;3}
3/ \(\Leftrightarrow\hept{\begin{cases}-x+5=0\\3-x=0\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}-x=0-5\\x=3-0\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}-x=-5\\x=3\end{cases}}\)\(\Leftrightarrow\hept{\begin{cases}x=5\\x=3\end{cases}}\)
Vậy x = {3;5}
Tìm x,biết: a.-12(x-5)+7(3-x)=5
b.(x-2).(x+4)=0
c.(x-2).(x+15)=0
d.(7-x).(x+19)=0
e.-5<x<1
g.|x|<3
a) x = 4
b) x = 2 ; x = -4
c) x = 2 ; x = -15
d) x = 7 ; x = -19
e) x = -4 ; -3 ; -2 ; -1 ; 0
g) x = -1 ; - 2 ; 1 ; 2 ; 3 ; 4 ; ...
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a) -12x + 60 + 21 - 7x = 5
-12x - 7x + 60+21 = 5
-19x + 81 = 5
81-5 = 19x
19x = 76
x= 4
Bài : Tìm x thuộc Z , biết :
a) 15 - 5. | x+4 | =-12 - 3
b) ( 4x - 8) . ( 7-x ) = 0
c) ( x^2 - 36) x ( x^2 + 5 ) =0
d) -3. ( x+7) -11 = 2.(x +5)
a) \(15-5\left|x+4\right|=-12-3\)
\(\Leftrightarrow5\left|x+4\right|=30\)
\(\Leftrightarrow\left|x+4\right|=6\)
\(\Leftrightarrow\orbr{\begin{cases}x+4=6\\x+4=-6\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=-10\end{cases}}\)
b) \(\left(4x-8\right)\left(7-x\right)=0\Leftrightarrow\orbr{\begin{cases}4x-8=0\\7-x=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=2\\x=7\end{cases}}\)
c) \(\left(x^2-36\right)\left(x^2+5\right)=0\Rightarrow\left(x-6\right)\left(x+6\right)=0\)
\(\Leftrightarrow\orbr{\begin{cases}x-6=0\\x+6=0\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=6\\x=-6\end{cases}}\)
d) \(-3\left(x+7\right)-11=2\left(x+5\right)\)
\(\Leftrightarrow-3x-32=2x+10\)
\(\Leftrightarrow5x=-42\Rightarrow x=-\frac{42}{5}\)
tìm x, biết:
a. - 12 . ( x - 5) + 7 . ( 3 - x ) =5
b. 30 .( x+ 2 ) - 6 . ( x- 5) -24 .x = 100
c. ( x - 1 ) . ( x mũ 2 + 1) = 0
d. - 12 .( x-5) + 7 . (3- x) =5
a/ \(-12\left(x-5\right)+7\left(3-x\right)=5\)
\(< =>-12x+60+21-7x=5\)
\(< =>-19x+81=5\)
\(< =>-19x=-76\)
\(< =>x=\frac{76}{19}\)
b/ 30(x+2)-6(x-5)-24x=100
<=>30x + 60 - 6x + 30 - 24x =100
<=> 90=100( vô lý)
c/ \(\left(x-1\right)\left(x^2+1\right)=0\)
\(< =>\hept{\begin{cases}x-1=0\\x^2+1=0\end{cases}}< =>\hept{\begin{cases}x=1\\x^2=-1\left(voly\right)\end{cases}}\)
d/ làm rồi mà
a. \(-12.\left(x-5\right)+7.\left(3-x\right)=5\)
\(-12x+60+21-7x=5\)
\(-19x+81=5\)
\(-19x=-76\)
\(x=4\)
b. \(30.\left(x+2\right)-6.\left(x-5\right)-24x=100\)
\(30x+60-6x+30-24x=100\)
\(\left(30x-6x-24x\right)+\left(60+30\right)=100\)
\(90=100\)(vô lí)
\(\Rightarrow x=\varnothing\)
c. \(\left(x-1\right)\left(x^2+1\right)=0\)
\(\Rightarrow\orbr{\begin{cases}x-1=0\\x^2+1=0\end{cases}\Rightarrow\orbr{\begin{cases}x=1\\x^2=-1\left(loại\right)\end{cases}}}\)
\(\Rightarrow x=1\)
Câu d) chính là câu a) :D
a) - 12 . ( x - 5) + 7 . ( 3 - x ) =5
-12x-(-60)+21-7x=5
-12x+60+21-7x=5
-12x-7x=5-60-21
-19x=-76
19x=76
x=76:19
x=4
vậy x=4
b) 30 .( x+ 2 ) - 6 . ( x- 5) -24 .x = 100
30x-60-6x+30-24x=100
(30x-6x-24x)+(60+30)=100
90=100 (vô lí)
vậy \(x\in\varnothing\)
c) ( x - 1 ) . ( x 2+ 1) = 0
* x-1=0 * x2+1=0
x=0+1 x2=0-1
x=1 x2=-1 ( vô lí ,x2 \(\ge0\))
Bài 1: Tìm x, biết:
a) 4/3 - 1/3 . x =3
b) 12/5 - ( x + 12/5 ) = 1/3 - 2/5
c) 15/7 + ( x - 1/7 ) = -3
d) 3x/5 . (3x - 1/2) = 0
e) 11/12 - ( 2/5 + x ) = 2/3
bài 1:
a) 1/3x=-5/3
x=-5
b) x+12/5=37/15
x=1/15
c) x-1/7=-36/7
x=-5
d) 3x-1/2=0
3x=1/2
x=1/6
e) 2/5+x=1/4
x=-3/20
Bài 3. Tìm x biết:
1) |x| = 10 2) |x - 8| = 0 3) 7 + |x| = 12
4) |x + 1| = 3 5) 15 - x = 16 - (14 - 42) 6) 210 - (x - 12) = 168
1/ `|x|=10<=> x=\pm 10`
2/ `|x-8|=0<=>x-8=0<=>x=8`
3/ `7+|x|=12<=>|x|=5<=>x=\pm 5`
4/ `|x+1|=3`
$\Leftrightarrow\left[\begin{array}{1}x+1=3\\x+1=-3\end{array}\right.\\\Leftrightarrow\left[\begin{array}{1}x=3\\x=-4\end{array}\right.$
5/ `15-x=16-(14-42)`
`<=>15-x=16+28`
`<=>15-x=44`
`<=>x=-29`
6/ `210-(x-12)=168`
`<=>210-x+12=168`
`<=>222-x=168`
`<=>x=54`
1.
\(\left|x\right|=10\Leftrightarrow x=\pm10\)
2.
\(\left|x-8\right|=0\Leftrightarrow x-8=0\Leftrightarrow x=8\)
3.
\(7+\left|x\right|=12\Leftrightarrow\left|x\right|=5\Leftrightarrow x=\pm5\)