nho cac ban giai dum tim x biet (x4+2013)(x4+2014)=0
Cau 1:
Tim x, biet: 1-4+7-10+.............-x=-75
Cau 2:
Cho x1, x2, x3, x4, x5 thuộc Z
Biết x1+ x2 + x3 + x4 + x5=0
và x1 + x2=x3+ x4= x4 + x5 =2
Tinh x3, x4 , x5
Cau 3: Tim x biet
(x+7+1) chia het cho (x+7)
tinh tong cac so nguyen x, biet -2013<x<2013
nho ghi ro lluon nha cam on cac ban
-2013<x<2013
=>x thuộc {-2012;-2011;-2010;....;0;...;2010;2011;2012}
=>tổng các số nguyên x là :
(-2012)+(-2011)+(-2010)+...+0+...+2010+2011+2012
=[(-2012)+2012]+[(-2011)+2011]+...+0
=0+0+...+0
=0
tim x biet
a)2x = 64
b)3x-1=81
cac ban nho ghi cach giai nhe!thanhks
a)2x=64
2x=26
=>x=6
Vậy x =6
b)3x-1=81
3x-1=34
=>x-1=4
x=1+4
x=5
Vậy x=5
tim x trong cac hon so 2 x4/15 biet 5x1/5 < x x 4/15 < 9x4/15
Bai 1. 12 chia het ( x + 3 )
bai 2. Tim so tu nhien x, biet 6x + 4 chia het cho 2x
cac ban nho giai chi tiet giup minh nha cam on
tim x biet:\(\frac{1+2y}{8}=\frac{1+4y}{24}=\frac{1+6y}{6x}\)
nho trinh bay cach giai nhe cac ban
\(\frac{1+2y}{8}=\frac{1+4y}{24}=\frac{1+6y}{6x}=\frac{2\left(1+2y\right)-\left(1+4y\right)}{2.8-24}=\frac{1}{-8}\)
=> \(\frac{1+2y}{8}=\frac{1}{-8}\) => 1+2y = -1 => y = -1
\(\frac{1+6y}{6x}=\frac{1}{-8}\) => \(\frac{1+6.\left(-1\right)}{6x}=\frac{1}{-8}\)
=> \(\frac{-5}{6x}=\frac{1}{-8}\) => x = (-5).(-8)/6 = 20/3
Tim so tu nhien a nho nhat biet chia 5;8:12 deu du 2;6;8 ai giai duoc va nhanh minh like cho cam on cac ban
tim x biet :2*x-12*x=0. cac ban oi giup minh giai cau nay voi
2.x - 12.x = 0
=> 2 - 12 . x = 0
=> - 10.x = 0
=> x = 0 : ( - 10 )
=> x = 0
????
\(2\times x-12\times x=0\)
\(\left(2-12\right)\times x=0\)
\(-10\times x=0\)
\(x=0:\left(-10\right)\)
\(x=0\)
Vậy x = 0
tim ( a;n) E N biet a khac 0 , a < 10
va aaa= 1+2+3+.............+n
cac ban nho giai gium minh nha , viet ca cach giai nua nhe , cam on nhieu
nhung cach lam the nao ha ban , chi cho minh voi
may ban oi , cac cau lam sai rui , minh vua moi nhan ket qua la :
a = 6 , n = 36
cam on cac ban da dong gop y kien , to cam on nhieu