bn viết rõ đề đc ko

tc tỉ lệ thức,ta có (ra số hơi to thông cảm )

\(\Leftrightarrow\frac{22990993x+80556557}{1870865100}=-\frac{4}{1}\Rightarrow\left(22990993x+80556557\right)1=-1870865100.4\)

\(\frac{\left(22990993x+80556557\right)1}{22990933x}=-\frac{1870865100.4}{22990993x}\)( chia 2 vế cho 2290933x)

\(\Rightarrow\frac{22990933x+80556557}{22990933x}=-\frac{1870865100.4}{22990933x}\)

=>x=-329

Từ 1 đến x có (x-1):2+1 số hạng

Số cặp là ((x-1):2+1):2

tổng mỗi cặp là 1+x

Suy ra x=79

ô kia sai rồi

\(3^x+3^x.3=324\)

\(3^x.\left(1+3\right)=324\)

\(3^x.4=324\)

\(3^x=324:4\)

\(3^x=81\)

\(3^x=3^4\)

\(\Rightarrow x=4\)

3^x + 3^x+1     = 324

3^x .1+ 3^x.3   = 324

 3^x.(1+3)      = 324

    3^x .4        = 324

     3^x           = 324:4

     3^x            = 81

 81=3 .3.3.3 =3⁴ => 81 =3⁴=> x =4

Vậy x=4

ta co :3^x+3^x+1=324

=>3^x+3^x.3=324

=>3^x.(1+3)=324

=>3^x=324/4=81=3^4

=>x=4

vay x=4

\(\frac{x+2}{327}+\frac{x+3}{326}+\frac{x+4}{325}+\frac{x+5}{324}=-4\)

<=>\(\left(\frac{x+2}{327}+1\right)+\left(\frac{x+3}{326}+1\right)+\left(\frac{x+4}{325}+1\right)+\left(\frac{x+5}{324}+1\right)=0\)

<=>\(\frac{x+329}{327}+\frac{x+329}{326}+\frac{x+329}{325}+\frac{x+329}{324}=0\)

<=>\(\left(x+329\right)\left(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\right)=0\)

Vì \(\frac{1}{327}+\frac{1}{326}+\frac{1}{325}+\frac{1}{324}\ne0\Rightarrow x+329=0\Leftrightarrow x=-329\)

a) X +  5 9 =  3 2   ⇒ X =  3 2 - 5 9 = 27 18 - 10 18 = 17 18 .

b) X +  1 1 2   =   3 3 4   ⇒ X =  3 3 4 - 1 1 2 = 15 4 - 3 2 = 9 4 .

a ) x : 4 5 + 5 2 = − 3 3 4 ⇒ x : 4 5 = − 3 3 4 − 5 2 ⇒ x : 4 5 = − 11 2 ⇒ x = − 22 5 .

b ) x − 3 4 = 1 5 4 ⇒ x − 3 4 = 9 4     ⇒ x = 3 x − 3 4 = − 9 4 ⇒ x = − 3 2 .