a) (2+4+6+.....+100) . (36.333-108.111)

= (2+4+6+...+100).(36.111.3-108.111)

= (2+4+6+...+100).(108.111-108.111)

= (2+4+6+...+100).0

=0

b) 19991999.1998-19981998.1999

= 1999.10001.1998-1998.10001.1999

= 0

a) ( 2 + 4 + 6 + ... + 100 ) . ( 36.333 - 108.111 )

=  ( 2 + 4 + 6 + ... + 100 ) . ( 36.3.111 - 108.111)

= ( 2 + 4 + 6 + ... + 100 ) . ( 108.111 - 108.111 )

= ( 2 + 4 + 6 +... + 100 ) . 0

= 0

b) 19991999.1998 - 19981998 . 1999

= 1999.10001.1998 - 1998.10001 . 1999

= 0

b. (2+4+6+...+100).(36.333.108.111)

   =(2+4+6+...+100).          0

   =          0

a. 0             

a, 19991999.1998-19981998.1999

=1999.1001.1998-1998.1001.1999

=[1999.1001].1998-[1999.1001].1998

=0

a/ \(19.64+76.34\)

\(=19.4.16+19.4.34\)

\(=19.4\left(16+34\right)\)

\(19.4.50\)

\(=19.200=3800\)

b, \(136.68+16.272\)

\(=136.68+32.136\)

\(=136\left(68+32\right)\)

\(=136.100=13600\)

c/ \(\left(2+4+6+..........+100\right)\left(36.3.333-108.111\right)\)

\(=\left(2+4+....+100\right)\left(36.3.111-108.100\right)\)

\(=\left(2+4+.......+100\right)\left(108.111-108.111\right)\)

\(\left(2+4+...+100\right).0=0\)

\(Ta\)\(có:\)

\(\text{36.333-108.111}=0\)

\(=>tích\)\(đó=0\)

(2+4+6+...+100).(36.333-108.111

=(2+4+6+...+1000).(36.3.111-108.111)

=(2+4+6+...+1000.(108.111-108.111)

=(2+4+6+...+100).0

0

(2+4+6+..+100).(36.333-108.111)

=(2+4+6+..+100).0

=0

=0 bạn nha

(2+4+6+8+...+100). (36.333-108.111)

= (2+4+6+...+100).(36.3.111-108.111)

=(2+4+6+...+100).(108.111-108.111)

=(2+4+6+...+100).0

=0

( 2 +4+6+8...+100 ).(36.333-108.111)

=>(2+4+6+8+....+100).(108.111-108.111)

=>(2+4+6+8+...+100)x0

=>0

A= 19 . 64+ 76.34

A=19.2.32+38.2.34

A=38.32+38.68

A=38.(32+68)

A=38.100

A=3800

B= 35 .12+ 65.13

B= 35.12+65.(12+1)

B=35.12 +65.12+65

B=(35+65).12 +65

B=100.12+65

B=1200+65

B=1265

C=136.68+16.272

C=136.68+16.2.136

C=136.68+32.136

C=136.(68+32)

C=136.100

C=13600

D=(2+4+6+...+100).(36.333-108.111)

D=(2+4+6+...+100).(36.333-36.3.111)

D=(2+4+6+...+100).(36.333+36.333)

D=(2+4+6+..+100).0

D=0

E=19991999.1998+19981998.1999

E=1999.10001.1998-1998.10001.1999

E=0

A= 19.64 +76.34                                                                      B=35.12 +65.13

   =76(16+34)                                                                              =35.13-35+65.13

   =76.50                                                                                      =1300-35

   =380                                                                                         =1765

c)136.68+16.272

=136.68+16.2.136

=136.68+32.136

=136.(68+32)

=136.100=13600

a)19.64+76.34

=19.64+19.4.34

=19.64+19.136

=19.(64+136)

=19.200=3800

b)=(35+65)6.2.13

 =100.(2.13).6

 =100.(26.6)

 =100.153

 =15300

d)=(2652).(0)

=0

         vì (2++4 + 6 +...+100)có 52 chữ số và kết quả của nó ll 2450.công thức tính ra kết quả đó chính là (100+2).52:2=2652