\(19\cdot27+41\cdot81+19\cdot20\)

=\(513+3321+380\)

=\(4214\)

19. 27+41.81+19.20 = 80. 28

19*27+41*81+19*20=513+3321+380=4214

ʇɐɥʇ ɥuɐɹ uɐq ɔɐɔ ɐl ƃunp ıɥʇ ʎɐp uǝp ɔonp ɔop uɐq ɔɐɔ ɐl ʇǝıq ɥuıɯ ƃunɥu 'ɔonp ɔop ıoɯ ıɐl ɔonƃu ʎɐox ıɐɥd ɐʌ ɔop oɥʞ ɐl ʇɐɹ ıɥʇ ʎɐu ǝɥʇ ʇǝıʌ ɐl ʇǝıq ɥuıɯ

mjk dịch đc nè''

mình ko cần xoay ngược cũng đọc đc

Tách hai dấu ngoặc thành hai vế A và B

Ta có : 

A=5.4¹⁵.9⁹-4.3²⁰.8⁹=5.2³⁰.3¹⁸-2².2²⁷.3²⁰

=2²⁹.3¹⁸(2.5-3²)=2²⁹.3¹⁸

B=5.2⁹.6¹⁹-7.2²⁹.27⁶=5.2⁹.2¹⁹.3¹⁹-7.2²⁹.3¹⁸

=2²⁸.3¹⁸(5.3-7.2)=2²⁸.3¹⁸

=>A:B=2²⁹.3¹⁸:2²⁸:3¹⁸=2

   - ( -27 + 85 ) + ( 157 - 35 + 73 )

= - 112 + ( 122 + 73 )

= - 112 + 195

= 173

= 27-85+157-35+73

= -58+157-35+73

= 99-35+73

=63+73

= 133

k cho mình nha

lung tung dã man bài toán này bịa

bài này đến cả giáo viên con không nghĩ ra nói gì tụi này

hại não qá bà con ơi 

\(A< B\) \(nha\)\(bn\)

A<B nha

\(\frac{5.4^{15}.9^9-4.3^{20}.8^9}{5.2^9.6^{19}-7.2^{29}.27^6}\)

\(=\frac{5.\left(2^2\right)^{15}.\left(3^2\right)^9-2^2.3^{20}.\left(2^3\right)^9}{5.2^9.\left(2.3\right)^{19}-7.2^{29}.\left(3^3\right)^6}\)

\(=\frac{5.2^{30}.3^{18}-2^2.3^{20}.2^{27}}{5.2^9.2^{19}.3^{19}-7.2^{29}.3^{18}}\)

\(=\frac{5.2^{30}.3^{18}-2^{29}.3^{20}}{5.2^{28}.3^{19}-7.2^{29}.3^{18}}\)

\(=\frac{2^{29}.3^{18}.\left(5.2-3^2\right)}{2^{28}.3^{18}.\left(5.3-7.2\right)}\)

\(=\frac{2^{29}.3^{18}.1}{2^{28}.3^{18}.1}\)

\(=\frac{2^{29}}{2^{28}}=2\)

\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}\)

\(=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{2^9.3^9.2^{10}+2^{20}.3^{10}}\)

\(=\frac{2^{19}.3^9+2^{18}.3^9.5}{2^{19}.3^9+2^{19}.2.3^9.3}\)

\(=\frac{2^{18}.3^9.\left(2+5\right)}{2^{19}.3^9.\left(1+6\right)}\)

\(=\frac{7}{2.7}\)

\(=\frac{1}{2}\)

\(\sqrt{3}.\sqrt{\frac{1}{27}}.\sqrt{5}.\sqrt{20}=\sqrt{3.\frac{1}{27}}.\sqrt{5.20}=\sqrt{\frac{1}{9}}.\sqrt{100}=\frac{1}{3}.10=\frac{10}{3}\)