Help me :) 

Suppose \(n\)is a positive integer and 3 arbitrary numbers are choosen from the set \(\left\{1;2;3...;3n+1\right\}\)with their sum equal to \(3n+1.\)

What is the largest possible product of those 3 numbers ?

Dịch ( Nhưng phiền everybody giải in tiếng Anh :v )

Cho n là một số nguyên dương và 3 số tùy ý được chọn trong tập hợp \(\left\{1;2;3...;3n+1\right\}\)mà tổng chúng bằng \(3n+1.\)

Giá trị lớn nhất có thể của tích 3 số này là ?

1) ABC is a triangle where M is the midpoint of segment BC.

MD and ME are two bisectors of triangles AMB and AMC respectively.

If AM= m; BC = a . Then DE = ???

2)\(\dfrac{1}{\left(x+29\right)^2}+\dfrac{1}{\left(x+30\right)^2}=\dfrac{5}{4}\)

What is the product of all real solutions to the equation above?

3) The sum of all possible natural numbers n such that

\(n^2+n+1589\) is a perfect square is.....

4) Given that x is a positive integer such that x and x+99 are perfect squares

The sum of integer x is ...

5)The operation @ on two numbers produces a number equal to their sum minus 2. The value of

(...((1@2)@3....@2017)

6) Given f(x)=\(\dfrac{x^2}{2x-2x^2-1}\)

=> \(f\left(\dfrac{1}{2016}\right)+f\left(\dfrac{2}{2016}\right)+f\left(\dfrac{3}{2016}\right)+...+f\left(\dfrac{2016}{2016}\right)\)

Các bn giúp mk vs >>> tks nha!!!

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