a)(x3-27)÷(x-3)
b)(x+2y)2÷(5x-10y)
a)[5(a-b)^3+2(a-b)^2]:(b-a)^2
b)5(x-2y)^3:(5x-10y)
c)(x^3+8y^3):(x+2y)
a) \(\frac{5\left(a-b\right)^3+2\left(a-b\right)^2}{\left(b-a\right)^2}=\frac{\left(a-b\right)^2\cdot\left[5\cdot\left(a-b\right)+2\right]}{\left(a-b\right)^2}=5\cdot\left(a-b\right)+2\)
b) \(\frac{5\left(x-2y\right)^3}{5x-10y}=\frac{5\left(x-2y\right)^3}{5\left(x-2y\right)}=\left(x-2y\right)^2\)
c) \(\frac{x^3+8y^3}{x+2y}=\frac{\left(x+2y\right)\left(x^2-2xy+4y^2\right)}{x+2y}=x^2-2xy+4y^2\)
làm tính chia
a) (x^3 + 3x^2 + 3xy^2 + y^3) : (2x + 2y)
b) [5(a-b)^3 + 2(a-b)^2 ]
c) 5(x-2y)^3 : (5x - 10y)
a) \(\dfrac{\left(x+y\right)^2}{2}\)
b)\(\dfrac{5a-5b}{2}\)
c)\(\left(x-2y\right)^2\)
Chứng minh rằng:
a)x^2+5y^2+2x-4xy-10y+14>0
b)5x^2+10y^2-6xy-4x-2y+3>0
Làm phép chia
a)[5(a-b)3+2(a-b)2]:(b-a)2
b)5(x-2y)3:(5x-10y)
c)(x3+8y3):(x+2y)
a, x^2-y^2-2y-1
b, 5x-10y-x^2+4y^2
c, x^2-4x+3
d, x^3-9x^2y + 9xy^2-3xy^2
e, x^4 +64
a,=x^2-[y-1]^2
=[x-y+1] [x+y-1]
b,=5[x-2y]-[x-2y].[x+2y]
=[x-2y].[5-x-2y]
CMR:
a,\(x^2+5y^2+2x-4xy-10y+10>0\forall x,y\)
b,\(5x^2+10y^2-6xy-4x-2y+3>0\forall x,y\)
Bài 1: Thực hiện phép tính:
a) [9(a-b)3+ 2(a-b)2] : (b-a)2
b) 5(x-2y)3 (5x-10y)
c) (x3+8y3) : (x+2y)
CMR:
a,\(x^2+5y^2+2x-4xy-10y+14>0\)với mọi x
b,\(5x^2+10y^2-6xy-4x-2y+3>0\) với mọi x